Recall that the Consumer Price Index (CPI) is a measure of inflation reached by comparing current prices with base prices in 1982 – 84 . However, it is a mistake to interpret a change in the CPI as the actual percent of inflation. For example, from 2013 to 2014, the CPI for candy and chewing gum rose from 138.5 to 141.2 . However, the rate of inflation for these items was only $ 141.2 − 138.5 138.5 ≈ 0.019 = 1.9 % .For Exercises 71 – 74 , use the given information to fill in the missing items in the table. Item CPI for Item in 2005 CPI for Item in 2015 Percent of Increase Milk 3.310 2.1
Recall that the Consumer Price Index (CPI) is a measure of inflation reached by comparing current prices with base prices in 1982 – 84 . However, it is a mistake to interpret a change in the CPI as the actual percent of inflation. For example, from 2013 to 2014, the CPI for candy and chewing gum rose from 138.5 to 141.2 . However, the rate of inflation for these items was only $ 141.2 − 138.5 138.5 ≈ 0.019 = 1.9 % .For Exercises 71 – 74 , use the given information to fill in the missing items in the table. Item CPI for Item in 2005 CPI for Item in 2015 Percent of Increase Milk 3.310 2.1
Solution Summary: The author explains how to fill the missing items in the given table.
Recall that the Consumer Price Index (CPI) is a measure of inflation reached by comparing current prices with base prices in
1982
–
84
. However, it is a mistake to interpret a change in the CPI as the actual percent of inflation. For example, from 2013 to 2014, the CPI for candy and chewing gum rose from
138.5
to
141.2
. However, the rate of inflation for these items was only
$
141.2
−
138.5
138.5
≈
0.019
=
1.9
%
.For Exercises
71
–
74
, use the given information to fill in the missing items in the table.
Problem 11 (a) A tank is discharging water through an orifice at a depth of T
meter below the surface of the water whose area is A m². The
following are the values of a for the corresponding values of A:
A 1.257 1.390
x 1.50 1.65
1.520 1.650 1.809 1.962 2.123 2.295 2.462|2.650
1.80 1.95 2.10 2.25 2.40 2.55 2.70
2.85
Using the formula
-3.0
(0.018)T =
dx.
calculate T, the time in seconds for the level of the water to drop
from 3.0 m to 1.5 m above the orifice.
(b) The velocity of a train which starts from rest is given by the fol-
lowing table, the time being reckoned in minutes from the start
and the speed in km/hour:
| † (minutes) |2|4 6 8 10 12
14 16 18 20
v (km/hr) 16 28.8 40 46.4 51.2 32.0 17.6 8 3.2 0
Estimate approximately the total distance ran in 20 minutes.
-
Let n = 7, let p = 23 and let S be the set of least positive residues mod p of the first (p − 1)/2
multiple of n, i.e.
n mod p, 2n mod p, ...,
p-1
2
-n mod p.
Let T be the subset of S consisting of those residues which exceed p/2.
Find the set T, and hence compute the Legendre symbol (7|23).
23
32
how come?
The first 11 multiples of 7 reduced mod 23 are
7, 14, 21, 5, 12, 19, 3, 10, 17, 1, 8.
The set T is the subset of these residues exceeding
So T = {12, 14, 17, 19, 21}.
By Gauss' lemma (Apostol Theorem 9.6),
(7|23) = (−1)|T| = (−1)5 = −1.
Let n = 7, let p = 23 and let S be the set of least positive residues mod p of the first (p-1)/2
multiple of n, i.e.
n mod p, 2n mod p, ...,
2
p-1
-n mod p.
Let T be the subset of S consisting of those residues which exceed p/2.
Find the set T, and hence compute the Legendre symbol (7|23).
The first 11 multiples of 7 reduced mod 23 are
7, 14, 21, 5, 12, 19, 3, 10, 17, 1, 8.
23
The set T is the subset of these residues exceeding
2°
So T = {12, 14, 17, 19, 21}.
By Gauss' lemma (Apostol Theorem 9.6),
(7|23) = (−1)|T| = (−1)5 = −1.
how come?
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