Starting Out with Python (4th Edition)
4th Edition
ISBN: 9780134444321
Author: Tony Gaddis
Publisher: PEARSON
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Chapter 8.1, Problem 5CP
Explanation of Solution
Computing length of string:
- • In Python, the “len()” function would return the length of sequence.
- • It returns the length of string.
Syntax:
The syntax for “len()” function is shown below:
string_variable = ‘string_value’
variable = len(string_variable)
Explanation:
In the above syntax,
- • The “string_variable” denotes variable that references a string.
- • The “variable” denotes the length of city.
- • The “len()” function computes the length of string and assigns in variable “variable”...
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Students have asked these similar questions
My code is experincing minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place.
My code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2 * pi * f; % Angular frequency
% Parameters for the filters - let's adjust these to get more reasonable cutoffs
R = 1e3; % Resistance in ohms (1 kΩ)
C = 1e-6; % Capacitance in farads (1 μF)
% For bandpass, we need appropriate L value for desired cutoffs
L = 0.1; % Inductance in henries - adjusted for better bandpass response
% Calculate cutoff frequencies first to verify they're in desired range
f_cutoff_RC = 1 / (2 * pi * R * C);
f_resonance = 1 / (2 * pi * sqrt(L * C));
Q_factor = (1/R) * sqrt(L/C);
f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor));
f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));
% Transfer functions
% Low-pass filter (RC)
H_low = 1 ./ (1 + 1i * w *…
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map the following ER diagram into a relational database schema diagram. you should take into account all the constraints in the ER diagram. Underline the primary key of each relation, and show each foreign key as a directed arrow from the referencing attributes (s) to the referenced relation.
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Chapter 8 Solutions
Starting Out with Python (4th Edition)
Ch. 8.1 - Assume the variable name references a string....Ch. 8.1 - What is the index of the first character in a...Ch. 8.1 - If a string has 10 characters, what is the index...Ch. 8.1 - Prob. 4CPCh. 8.1 - Prob. 5CPCh. 8.1 - Prob. 6CPCh. 8.2 - Prob. 7CPCh. 8.2 - Prob. 8CPCh. 8.2 - Prob. 9CPCh. 8.2 - What will the following code display? mystring =...
Ch. 8.3 - Prob. 11CPCh. 8.3 - Prob. 12CPCh. 8.3 - Write an if statement that displays Digit" if the...Ch. 8.3 - What is the output of the following code? ch = 'a'...Ch. 8.3 - Write a loop that asks the user Do you want to...Ch. 8.3 - Prob. 16CPCh. 8.3 - Write a loop that counts the number of uppercase...Ch. 8.3 - Assume the following statement appears in a...Ch. 8.3 - Assume the following statement appears in a...Ch. 8 - This is the first index in a string. a. 1 b. 1 c....Ch. 8 - This is the last index in a string. a. 1 b. 99 c....Ch. 8 - This will happen if you try to use an index that...Ch. 8 - This function returns the length of a string. a....Ch. 8 - This string method returns a copy of the string...Ch. 8 - This string method returns the lowest index in the...Ch. 8 - This operator determines whether one string is...Ch. 8 - This string method returns true if a string...Ch. 8 - This string method returns true if a string...Ch. 8 - This string method returns a copy of the string...Ch. 8 - Once a string is created, it cannot be changed.Ch. 8 - You can use the for loop to iterate over the...Ch. 8 - The isupper method converts a string to all...Ch. 8 - The repetition operator () works with strings as...Ch. 8 - Prob. 5TFCh. 8 - What does the following code display? mystr =...Ch. 8 - What does the following code display? mystr =...Ch. 8 - What will the following code display? mystring =...Ch. 8 - Prob. 4SACh. 8 - What does the following code display? name = 'joe'...Ch. 8 - Assume choice references a string. The following...Ch. 8 - Write a loop that counts the number of space...Ch. 8 - Write a loop that counts the number of digits that...Ch. 8 - Write a loop that counts the number of lowercase...Ch. 8 - Write a function that accepts a string as an...Ch. 8 - Prob. 6AWCh. 8 - Write a function that accepts a string as an...Ch. 8 - Assume mystrinc references a string. Write a...Ch. 8 - Assume mystring references a string. Write a...Ch. 8 - Look at the following statement: mystring =...Ch. 8 - Initials Write a program that gets a string...Ch. 8 - Sum of Digits in a String Write a program that...Ch. 8 - Date Printer Write a program that reads a string...Ch. 8 - Prob. 4PECh. 8 - Alphabetic Telephone Number Translator Many...Ch. 8 - Average Number of Words If you have downloaded the...Ch. 8 - If you have downloaded the source code you will...Ch. 8 - Sentence Capitalizer Write a program with a...Ch. 8 - Prob. 10PECh. 8 - Prob. 11PECh. 8 - Word Separator Write a program that accepts as...Ch. 8 - Pig Latin Write a program that accepts a sentence...Ch. 8 - PowerBall Lottery To play the PowerBall lottery,...Ch. 8 - Gas Prices In the student sample program files for...
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- What is business intelligence? Share the Business intelligence (BI) tools you have used and explain what types of decisions you made.arrow_forwardI need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…arrow_forwardTask 3. i) Compare your results from Tasks 1 and 2. j) Repeat Tasks 1 and 2 for 500 and 5,000 elements. k) Summarize run-time results in the following table: Time/size n String StringBuilder 50 500 5,000arrow_forward
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