Chapter 8, Problem 8H.2E

(a)

Interpretation Introduction

Interpretation:

The chemical equation for sodium oxide and water has to be given.

Answer to Problem 8H.2E

The chemical equation for sodium oxide and water is,

  ${\text{Na}}_{\text{2}}{\text{O}}_{\left(\text{s}\right)}{\text{+H}}_{\text{2}}{\text{O}}_{\left(\text{l}\right)}\stackrel{}{\to }{\text{2NaOH}}_{\left(\text{aq}\right)}$

Explanation of Solution

Sodium oxide reacts with water to form sodium hydroxide $\left(\text{NaOH}\right)\text{.}$  The chemical equation is given as,

  ${\text{Na}}_{\text{2}}{\text{O}}_{\left(\text{s}\right)}{\text{+H}}_{\text{2}}{\text{O}}_{\left(\text{l}\right)}\stackrel{}{\to }{\text{NaOH}}_{\left(\text{aq}\right)}$

Two moles of sodium hydroxide are required in the product side to make the equation a balanced one.  The balanced chemical equation for sodium oxide and water is,

  ${\text{Na}}_{\text{2}}{\text{O}}_{\left(\text{s}\right)}{\text{+H}}_{\text{2}}{\text{O}}_{\left(\text{l}\right)}\stackrel{}{\to }{\text{2NaOH}}_{\left(\text{aq}\right)}$

(b)

Interpretation Introduction

Interpretation:

The chemical equation for sodium peroxide with water has to be given.

Answer to Problem 8H.2E

The chemical equation for sodium peroxide with water is,

  ${\text{2Na}}_{\text{2}}{\text{O}}_{\text{2}}{}_{\left(\text{s}\right)}{\text{+2H}}_{\text{2}}{\text{O}}_{\left(\text{l}\right)}\stackrel{}{\to }{\text{4NaOH}}_{\left(\text{aq}\right)}{\text{+O}}_{\text{2(g)}}$

Explanation of Solution

Sodium peroxide reacts with water to form sodium hydroxide with the evolution of oxygen gas.  The chemical equation is given as,

  ${\text{Na}}_{\text{2}}{\text{O}}_{\text{2}}{}_{\left(\text{s}\right)}{\text{+H}}_{\text{2}}{\text{O}}_{\left(\text{l}\right)}\stackrel{}{\to }{\text{NaOH}}_{\left(\text{aq}\right)}{\text{+O}}_{\text{2(g)}}$

Two moles of sodium peroxide, two moles of water are required in the reactant side and two moles of sodium hydroxide are required in the product side to make the equation a balanced one.  The balanced chemical equation for sodium peroxide with water is,

  ${\text{2Na}}_{\text{2}}{\text{O}}_{\text{2}}{}_{\left(\text{s}\right)}{\text{+2H}}_{\text{2}}{\text{O}}_{\left(\text{l}\right)}\stackrel{}{\to }{\text{4NaOH}}_{\left(\text{aq}\right)}{\text{+O}}_{\text{2(g)}}$

(c)

Interpretation Introduction

Interpretation:

The chemical equation for sulphur dioxide with water has to be given.

Answer to Problem 8H.2E

The chemical equation for sulphur dioxide with water is,

  ${\text{SO}}_{\text{2(g)}}{\text{+H}}_{\text{2}}{\text{O}}_{\left(\text{l}\right)}\stackrel{}{\to }{\text{H}}_{\text{2}}{\text{SO}}_{\text{3(aq)}}$

Explanation of Solution

Sulphur dioxide reacts with water to form sulphurous acid $\left({\text{H}}_{\text{2}}{\text{SO}}_{\text{3}}\right)\text{.}$  The chemical reaction is,

  ${\text{SO}}_{\text{2(g)}}{\text{+H}}_{\text{2}}{\text{O}}_{\left(\text{l}\right)}\stackrel{}{\to }{\text{H}}_{\text{2}}{\text{SO}}_{\text{3(aq)}}$

The reaction of sulphur dioxide with water is self-balanced.

(d)

Interpretation Introduction

Interpretation:

The chemical equation for sulphur dioxide with oxygen in presence of ${\text{V}}_{\text{2}}{\text{O}}_{\text{5}}$ has to be given.

Answer to Problem 8H.2E

The chemical equation for sulphur dioxide with oxygen in presence of ${\text{V}}_{\text{2}}{\text{O}}_{\text{5}}$  cell is,

  ${\text{2SO}}_{\text{2(g)}}{\text{+O}}_{\text{2(g)}}\stackrel{{\text{V}}_{\text{2}}{\text{O}}_{\text{5}}}{\to }{\text{2SO}}_{\text{3(g)}}$

Explanation of Solution

Sulphur dioxide reacts with oxygen to form sulphur trioxide $\left({\text{SO}}_{\text{3}}\right)\text{.}$  The chemical reaction is,

  ${\text{SO}}_{\text{2(g)}}{\text{+O}}_{\text{2(g)}}\stackrel{{\text{V}}_{\text{2}}{\text{O}}_{\text{5}}}{\to }{\text{SO}}_{\text{3(g)}}$

Two moles of sulphur dioxide are required in the reactant side and two moles of sulphur trioxide are required in the product side to make the equation a balanced one.

The balanced chemical equation for sulphur dioxide with oxygen in presence of ${\text{V}}_{\text{2}}{\text{O}}_{\text{5}}$  cell is,

  ${\text{2SO}}_{\text{2(g)}}{\text{+O}}_{\text{2(g)}}\stackrel{{\text{V}}_{\text{2}}{\text{O}}_{\text{5}}}{\to }{\text{2SO}}_{\text{3(g)}}$