Chemical Principles: The Quest for Insight
7th Edition
ISBN: 9781464183959
Author: Peter Atkins, Loretta Jones, Leroy Laverman
Publisher: W. H. Freeman
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Chapter 8, Problem 8H.1BST
Interpretation Introduction
Interpretation:
The half-reactions, the overall reaction for the oxidation of water by
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For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box.
Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below.
Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first
stable product you expect to form in solution.
དྲ。
✗MgBr
?
O
CI
Will the first product that forms in this reaction
create a new C-C bond?
Yes
No
•
?
Will the first product that forms in this reaction
create a new CC bond?
Yes
No
×
: ☐
X
Predict the major products of this organic reaction:
OH
NaBH4
H
?
CH3OH
Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry.
Click and drag to start drawing a
structure.
☐ :
S
Predict the major products of this organic reaction:
1. LIAIHA
2. H₂O
?
Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry.
Click and drag to start drawing a
structure.
X
: ☐
Chapter 8 Solutions
Chemical Principles: The Quest for Insight
Ch. 8 - Prob. 8A.1ASTCh. 8 - Prob. 8A.1BSTCh. 8 - Prob. 8A.2ASTCh. 8 - Prob. 8A.2BSTCh. 8 - Prob. 8A.1ECh. 8 - Prob. 8A.2ECh. 8 - Prob. 8A.3ECh. 8 - Prob. 8A.4ECh. 8 - Prob. 8A.5ECh. 8 - Prob. 8A.6E
Ch. 8 - Prob. 8A.7ECh. 8 - Prob. 8A.8ECh. 8 - Prob. 8A.9ECh. 8 - Prob. 8A.10ECh. 8 - Prob. 8A.11ECh. 8 - Prob. 8A.12ECh. 8 - Prob. 8A.13ECh. 8 - Prob. 8A.14ECh. 8 - Prob. 8A.15ECh. 8 - Prob. 8A.16ECh. 8 - Prob. 8A.17ECh. 8 - Prob. 8A.18ECh. 8 - Prob. 8A.19ECh. 8 - Prob. 8A.20ECh. 8 - Prob. 8B.1ASTCh. 8 - Prob. 8B.1BSTCh. 8 - Prob. 8B.2ASTCh. 8 - Prob. 8B.2BSTCh. 8 - Prob. 8B.1ECh. 8 - Prob. 8B.2ECh. 8 - Prob. 8B.3ECh. 8 - Prob. 8B.4ECh. 8 - Prob. 8B.5ECh. 8 - Prob. 8B.6ECh. 8 - Prob. 8B.7ECh. 8 - Prob. 8B.8ECh. 8 - Prob. 8C.1ASTCh. 8 - Prob. 8C.1BSTCh. 8 - Prob. 8C.2BSTCh. 8 - Prob. 8C.1ECh. 8 - Prob. 8C.2ECh. 8 - Prob. 8C.3ECh. 8 - Prob. 8C.4ECh. 8 - Prob. 8C.5ECh. 8 - Prob. 8C.6ECh. 8 - Prob. 8D.1ASTCh. 8 - Prob. 8D.1BSTCh. 8 - Prob. 8D.2ASTCh. 8 - Prob. 8D.2BSTCh. 8 - Prob. 8D.1ECh. 8 - Prob. 8D.2ECh. 8 - Prob. 8D.3ECh. 8 - Prob. 8D.4ECh. 8 - Prob. 8D.5ECh. 8 - Prob. 8D.6ECh. 8 - Prob. 8D.7ECh. 8 - Prob. 8D.8ECh. 8 - Prob. 8E.1ASTCh. 8 - Prob. 8E.1BSTCh. 8 - Prob. 8E.2ASTCh. 8 - Prob. 8E.2BSTCh. 8 - Prob. 8E.1ECh. 8 - Prob. 8E.2ECh. 8 - Prob. 8E.3ECh. 8 - Prob. 8E.4ECh. 8 - Prob. 8E.5ECh. 8 - Prob. 8E.6ECh. 8 - Prob. 8E.7ECh. 8 - Prob. 8E.8ECh. 8 - Prob. 8F.1ASTCh. 8 - Prob. 8F.1BSTCh. 8 - Prob. 8F.2ASTCh. 8 - Prob. 8F.2BSTCh. 8 - Prob. 8F.1ECh. 8 - Prob. 8F.2ECh. 8 - Prob. 8F.3ECh. 8 - Prob. 8F.4ECh. 8 - Prob. 8F.5ECh. 8 - Prob. 8F.6ECh. 8 - Prob. 8G.1ASTCh. 8 - Prob. 8G.1BSTCh. 8 - Prob. 8G.2ASTCh. 8 - Prob. 8G.2BSTCh. 8 - Prob. 8G.1ECh. 8 - Prob. 8G.2ECh. 8 - Prob. 8G.3ECh. 8 - Prob. 8G.4ECh. 8 - Prob. 8G.5ECh. 8 - Prob. 8G.6ECh. 8 - Prob. 8G.7ECh. 8 - Prob. 8G.8ECh. 8 - Prob. 8G.9ECh. 8 - Prob. 8G.10ECh. 8 - Prob. 8H.1ASTCh. 8 - Prob. 8H.1BSTCh. 8 - Prob. 8H.2ASTCh. 8 - Prob. 8H.2BSTCh. 8 - Prob. 8H.1ECh. 8 - Prob. 8H.2ECh. 8 - Prob. 8H.3ECh. 8 - Prob. 8H.4ECh. 8 - Prob. 8H.5ECh. 8 - Prob. 8H.6ECh. 8 - Prob. 8H.7ECh. 8 - Prob. 8H.8ECh. 8 - Prob. 8H.10ECh. 8 - Prob. 8H.11ECh. 8 - Prob. 8H.12ECh. 8 - Prob. 8I.1ASTCh. 8 - Prob. 8I.1BSTCh. 8 - Prob. 8I.2ASTCh. 8 - Prob. 8I.2BSTCh. 8 - Prob. 8I.1ECh. 8 - Prob. 8I.2ECh. 8 - Prob. 8I.3ECh. 8 - Prob. 8I.5ECh. 8 - Prob. 8I.6ECh. 8 - Prob. 8I.7ECh. 8 - Prob. 8I.8ECh. 8 - Prob. 8I.9ECh. 8 - Prob. 8I.10ECh. 8 - Prob. 8I.11ECh. 8 - Prob. 8I.12ECh. 8 - Prob. 8I.13ECh. 8 - Prob. 8I.14ECh. 8 - Prob. 8I.15ECh. 8 - Prob. 8I.16ECh. 8 - Prob. 8J.1ASTCh. 8 - Prob. 8J.1BSTCh. 8 - Prob. 8J.1ECh. 8 - Prob. 8J.2ECh. 8 - Prob. 8J.3ECh. 8 - Prob. 8J.4ECh. 8 - Prob. 8J.5ECh. 8 - Prob. 8J.6ECh. 8 - Prob. 8J.7ECh. 8 - Prob. 8J.8ECh. 8 - Prob. 8.3ECh. 8 - Prob. 8.4ECh. 8 - Prob. 8.5ECh. 8 - Prob. 8.6ECh. 8 - Prob. 8.7ECh. 8 - Prob. 8.8ECh. 8 - Prob. 8.9ECh. 8 - Prob. 8.11ECh. 8 - Prob. 8.12ECh. 8 - Prob. 8.13ECh. 8 - Prob. 8.14ECh. 8 - Prob. 8.15ECh. 8 - Prob. 8.17ECh. 8 - Prob. 8.18ECh. 8 - Prob. 8.19ECh. 8 - Prob. 8.20ECh. 8 - Prob. 8.21ECh. 8 - Prob. 8.22ECh. 8 - Prob. 8.25ECh. 8 - Prob. 8.29ECh. 8 - Prob. 8.31CE
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- For each reaction below, decide if the first stable organic product that forms in solution will create a new C - C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 tu ? ? OH Will the first product that forms in this reaction create a new CC bond? Yes No Will the first product that forms in this reaction create a new CC bond? Yes No C $ ©arrow_forwardAs the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C-C bond as its major product: 1. MgCl ? 2. H₂O* If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new CC bond. G marrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M NH4 Ksp Hg2Br2 = 5.6×10-23.arrow_forward
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