
(a)
Interpretation:
The function of sulfide ions as a reducing agent on the basis of the
Concept introduction:
Redox reactions are the reactions that involve the transference of electrons. The one species gain electrons and the other one loses electrons. The reducing agent is the species that donate its electrons to the other species. It is also known as reducer or reductant. They oxidise themselves and therefore act as reducing agents.
(b)
Interpretation:
The function of sulphate ions as oxidizing agent on the basis of redox reactions is to determined.
Concept introduction:
Redox reactions are the reactions that involve the transference of electrons. The one species gain electrons and the other one loses electrons. The oxidizing agent is the species that gains electrons from the other species. It is also known as oxidizer or oxidant. They reduce themselves and therefore act as oxidizing agents.
(c)
Interpretation:
The function of sulphur dioxide as a reducing or oxidizing agent on the basis of the redox reactions is to be explained.
Concept introduction:
Redox reactions are the reactions that involve the transference of electrons. The one species gain electrons and the other one loses electrons. The reducing agent is the species that donate its electrons to the other species. It is also known as reducer or reductant. They oxidise themselves and therefore act as reducing agents. The oxidizing agent is the species that gains electrons from the other species. It is also known as oxidizer or oxidant. They reduce themselves and therefore act as oxidizing agents.

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Chapter 8 Solutions
Chemistry: The Molecular Nature of Matter and Change (Looseleaf)
- Look at the image attached pleaarrow_forwardComplete the mechanismarrow_forwardV Biological Macromolecules Drawing the Haworth projection of an aldose from its Fischer projection Draw a Haworth projection of a common cyclic form of this monosaccharide: H C=O HO H HO H H OH CH₂OH Explanation Check Click and drag to start drawing a structure. Xarrow_forward
- Complete the mechanismarrow_forwardComplete the mechanismarrow_forward8 00 6 = 10 10 Decide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH = 11. If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than unstable, you can pick any of them to redraw.) Check OH stable HO stable Ounstable unstable O OH stable unstable OH 80 F6 F5 stable Ounstable X Save For Later Sub 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy C ཀྭ་ A F7 매 F8 F9 4 F10arrow_forward
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