(a)
Interpretation:
The element with the configuration
Concept introduction:
The
(b)
Interpretation:
The element with the configuration
Concept introduction:
The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.
(c)
Interpretation:
The element with the configuration
Concept introduction:
The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.
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Chapter 8 Solutions
Chemistry: The Molecular Nature of Matter and Change (Looseleaf)
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- 3. a. Use the MS to propose at least two possible molecular formulas. For an unknown compound: 101. 27.0 29.0 41.0 50.0 52.0 55.0 57.0 100 57.5 58.0 58.5 62.0 63.0 64.0 65.0 74.0 40 75.0 76.0 20 20 40 60 80 100 120 140 160 180 200 220 m/z 99.5 68564810898409581251883040 115.0 116.0 77404799 17417M 117.0 12.9 118.0 33.5 119.0 36 133 0 1.2 157.0 2.1 159.0 16 169.0 219 170.0 17 171.0 21.6 172.0 17 181.0 1.3 183.0 197.0 100.0 198.0 200. 784 Relative Intensity 2 2 8 ō (ppm) 6 2arrow_forwardSolve the structure and assign each of the following spectra (IR and C-NMR)arrow_forward1. For an unknown compound with a molecular formula of C8H100: a. What is the DU? (show your work) b. Solve the structure and assign each of the following spectra. 8 6 2 ō (ppm) 4 2 0 200 150 100 50 ō (ppm) LOD D 4000 3000 2000 1500 1000 500 HAVENUMBERI -11arrow_forward
- 16. The proton NMR spectral information shown in this problem is for a compound with formula CioH,N. Expansions are shown for the region from 8.7 to 7.0 ppm. The normal carbon-13 spec- tral results, including DEPT-135 and DEPT-90 results, are tabulated: 7 J Normal Carbon DEPT-135 DEPT-90 19 ppm Positive No peak 122 Positive Positive cus и 124 Positive Positive 126 Positive Positive 128 No peak No peak 4° 129 Positive Positive 130 Positive Positive (144 No peak No peak 148 No peak No peak 150 Positive Positive してしarrow_forward3. Propose a synthesis for the following transformation. Do not draw an arrow-pushing mechanism below, but make sure to draw the product of each proposed step (3 points). + En CN CNarrow_forwardShow work..don't give Ai generated solution...arrow_forward
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