Chapter 8, Problem 8.88AP

Interpretation Introduction

Interpretation:

The volume (in milliliters) of the sodium hydroxide solution that is required to neutralize $\text{8}\text{.0}\text{mL}$ of $\text{3}\text{.5}\text{M}$ sulphuric acid has to be calculated.

Concept Introduction:

Molarity:  Molarity is defined as the mass of solute in one liter of solution.  Molarity is the preferred concentration unit for stoichiometry calculations.  The formula is,

  $\text{Molarity=}\frac{\text{Mass}\text{of}\text{solute(in}\text{moles)}}{\text{Volume}\text{of}\text{solution}\text{(in}\text{litres)}}$

The volume of the solution can be calculated as,

  $\text{Volume=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Molarity}\text{of}\text{solution}}$