The reason for lower intensity of atomic line for Li in a natural gas flame, 1800 o C in comparison to the hydrogen-oxygen flame, 2700 o C should be determined. Concept introduction: Spectral lines are lines which help in identifying the atoms and molecules. These are a result of absorption or emission of light in a comparatively narrower frequency range compared to the frequencies nearby. With the increase in temperature, there are more atoms excited and more electron transition happens from ground state to excited state. This results in more intensity of the emission line.

Question

> You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: 1. ☑ CI 2. H3O+ O Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. Explanation Check ? DO 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility

Answer 1

Question

Chapter 8, Problem 8.6QAP

Interpretation Introduction

Interpretation:

The reason for lower intensity of atomic line for Li in a natural gas flame, 1800 ^oC in comparison to the hydrogen-oxygen flame, 2700 ^oC should be determined.

Concept introduction:

Spectral lines are lines which help in identifying the atoms and molecules. These are a result of absorption or emission of light in a comparatively narrower frequency range compared to the frequencies nearby.

With the increase in temperature, there are more atoms excited and more electron transition happens from ground state to excited state. This results in more intensity of the emission line.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

> You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: 1. ☑ CI 2. H3O+ O Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. Explanation Check ? DO 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility

Don't use ai to answer I will report you answer

Consider a solution of 0.00304 moles of 4-nitrobenzoic acid (pKa = 3.442) dissolved in 25 mL water and titrated with 0.0991 M NaOH. Calculate the pH at the equivalence point