Figure 8.18 shows a system used to spray polluted water into the air to increase the water's oxygen content and to cause volatile solvents in the water to vaporize. The pressure at point B just ahead of the nozzle must be 25.0 psig for proper nozzle performance. The pressure at point A (the pump inlet) is − 3.50 psig. The volume flow rate is 0.50 f t 3 / s . The dynamic viscosity of the fluid is 4.0 x 10 − 5 I b s / f t 2 . The specific gravity of the fluid is 1.026 . Compute the power delivered by the pump to the fluid, considering friction energy loss in the discharge line.
Figure 8.18 shows a system used to spray polluted water into the air to increase the water's oxygen content and to cause volatile solvents in the water to vaporize. The pressure at point B just ahead of the nozzle must be 25.0 psig for proper nozzle performance. The pressure at point A (the pump inlet) is − 3.50 psig. The volume flow rate is 0.50 f t 3 / s . The dynamic viscosity of the fluid is 4.0 x 10 − 5 I b s / f t 2 . The specific gravity of the fluid is 1.026 . Compute the power delivered by the pump to the fluid, considering friction energy loss in the discharge line.
Solution Summary: The author explains the power delivered by the pump to the fluid.
Figure 8.18 shows a system used to spray polluted water into the air to increase the water's oxygen content and to cause volatile solvents in the water to vaporize. The pressure at point B just ahead of the nozzle must be
25.0
psig for proper nozzle performance. The pressure at point A (the pump inlet) is
−
3.50
psig. The volume flow rate is
0.50
f
t
3
/
s
. The dynamic viscosity of the fluid is
4.0
x
10
−
5
I
b
s
/
f
t
2
. The specific gravity of the fluid is
1.026
. Compute the power delivered by the pump to the fluid, considering friction energy loss in the discharge line.
Two springs and two masses are attached in a straight vertical line as shown in Figure Q3. The system is set
in motion by holding the mass m₂ at its equilibrium position and pushing the mass m₁ downwards of its
equilibrium position a distance 2 m and then releasing both masses. if m₁ = m₂ = 1 kg, k₁ = 3 N/m and
k₂ = 2 N/m.
www.m
k₁ = 3
(y₁ = 0).
m₁ = 1
k2=2
(y₂ = 0)
|m₂ = 1
Y2
y 2
System in
static
equilibrium
(Net change in
spring length
=32-31)
System in
motion
Figure Q3 - Coupled mass-spring system
Determine the equations of motion y₁(t) and y₂(t) for the two masses m₁ and m₂ respectively:
Analytically (hand calculations)
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