Chapter 8, Problem 8.34QP

When copper(II) sulfate pentahydrate (CuSO₄ · 5H₂O) is heated in air above 100°C, it loses the water molecules and its blue color.

${\text{CuSO}}_{\text{4}}\cdot {\text{5H}}_{\text{2}}\text{O}\to {\text{CuSO}}_{\text{4}}{\text{+5H}}_{\text{2}}\text{O}$

If 9.60 g of CuSO₄ are left after heating 15.01 g of the blue compound, calculate the number of moles of H₂O originally present in the compound.