The products of the given reaction which takes place via E1 mechanism are to be predicted. Concept introduction: An E1 reaction is a two-step, unimolecular elimination reaction. The first, rate-determining step, involves only the substrate. The leaving group departs along with the electron pair from its bond with the carbon atom, generating a carbocation. The carbocation produced may rearrange if it produces a more stable carbocation, in which case, a mixture of constitutional isomers is produced.

Question

13.84. Chlorine atoms react with methane, forming HCI and CH3. The rate constant for the reaction is 6.0 × 107 M¹ s¹ at 298 K. When the experiment was run at three other temperatures, the following data were collected: T (K) k (M-1 s-1) 303 6.5 × 107 308 7.0 × 107 313 7.5 x 107 a. Calculate the values of the activation energy and the frequency factor for the reaction. b. What is the value of the rate constant in the lower stratosphere, where T = 218 K?

Answer 1

Question

Chapter 8, Problem 8.28P

Interpretation Introduction

Interpretation:

The products of the given reaction which takes place via E1 mechanism are to be predicted.

Concept introduction:

An E1 reaction is a two-step, unimolecular elimination reaction. The first, rate-determining step, involves only the substrate. The leaving group departs along with the electron pair from its bond with the carbon atom, generating a carbocation. The carbocation produced may rearrange if it produces a more stable carbocation, in which case, a mixture of constitutional isomers is produced.

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13.84. Chlorine atoms react with methane, forming HCI and CH3. The rate constant for the reaction is 6.0 × 107 M¹ s¹ at 298 K. When the experiment was run at three other temperatures, the following data were collected: T (K) k (M-1 s-1) 303 6.5 × 107 308 7.0 × 107 313 7.5 x 107 a. Calculate the values of the activation energy and the frequency factor for the reaction. b. What is the value of the rate constant in the lower stratosphere, where T = 218 K?

My Organic Chemistry textbook says about the formation of cyclic hemiacetals, "Such intramolecular reactions to form five- and six-membered rings are faster than the corresponding intermolecular reactions. The two reacting functional groups, in this case OH and C=O, are held in close proximity, increasing the probability of reaction."According to the book, the formation of cyclic hemiacetals occurs in acidic conditions. So my question is whether the carbonyl group in this reaction reacts first with the end alcohol on the same molecule or with the ethylene glycol. And, given the explanation in the book, if it reacts first with ethylene glycol before its own end alcohol, why would it? I don't need to know the final answer. I need to know WHY it would not undergo an intermolecular reaction prior to reacting with the ethylene glycol if that is the case. Please do not use an AI answer.

Don't used hand raiting and don't used Ai solution