CHEMISTRY W/WRKBK AND SMARTWORK (LL)
5th Edition
ISBN: 9780393693447
Author: Gilbert
Publisher: NORTON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 8, Problem 8.22QP
Interpretation Introduction
Interpretation: The difference in the valence electrons and the total electron count is to be determined.
Concept introduction: Valence electrons are the electrons present in the outermost shell of an atom.
Group number is the number that indicates the group to which an element belongs.
To determine: The difference in the valence electrons and the total electron count.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Check
Consider the
13 C NMR spectrum below.
140
120
100
80
60
60
PPM
40
20
0
The spectrum belongs to which one of the following constitutional isomers of the compound C 10H14? Select the single best answer.
✓
Save
© 2025 McGraw Hill LLC. All Rights Reserved.
The structure of compound 1,1,2-trichloropropane is given below.
Cl
Cl
Cl
1
How many signals would you expect to find in the 'H NMR spectrum of 1,1,2-trichloropropane?
×
1,
How many signals do you expect in the H NMR spectrum for this molecule?
Write the answer below.
Also, in each of the drawing areas below is a copy of the molecule, with Hs shown. In each copy, one of the H atoms is colored red. Highlight in red all other H
atoms that would contribute to the same signal as the H already highlighted red.
Note for advanced students: In this question, any multiplet is counted as one signal.
Number of signals in the 'H NMR spectrum.
For the molecule in the top drawing area, highlight in red any other H atoms that will contribute to
the same signal as the H atom already highlighted red.
If no other H atoms will contribute, check the box at right.
No additional Hs to color in top
molecule
For the molecule in the bottom drawing area, highlight in red any other H atoms that will contribute.
to the same signal as the H atom already highlighted red.
If no other H atoms will contribute, check the box at right.
No additional Hs to color in bottom
molecule
Check…
Chapter 8 Solutions
CHEMISTRY W/WRKBK AND SMARTWORK (LL)
Ch. 8.2 - Prob. 1PECh. 8.2 - Prob. 2PECh. 8.2 - Prob. 3PECh. 8.2 - Prob. 4PECh. 8.3 - Prob. 5PECh. 8.4 - Prob. 6PECh. 8.4 - Prob. 7PECh. 8.5 - Prob. 8PECh. 8.6 - Prob. 9PECh. 8.6 - Prob. 10PE
Ch. 8.6 - Prob. 11PECh. 8.7 - Prob. 12PECh. 8 - Prob. 8.1VPCh. 8 - Prob. 8.2VPCh. 8 - Prob. 8.3VPCh. 8 - Prob. 8.4VPCh. 8 - Prob. 8.5VPCh. 8 - Prob. 8.6VPCh. 8 - Prob. 8.7VPCh. 8 - Prob. 8.8VPCh. 8 - Prob. 8.9VPCh. 8 - Prob. 8.10VPCh. 8 - Prob. 8.11VPCh. 8 - Prob. 8.12VPCh. 8 - Prob. 8.13VPCh. 8 - Prob. 8.14VPCh. 8 - Prob. 8.15VPCh. 8 - Prob. 8.16VPCh. 8 - Prob. 8.17VPCh. 8 - Prob. 8.18VPCh. 8 - Prob. 8.19QPCh. 8 - Prob. 8.20QPCh. 8 - Prob. 8.21QPCh. 8 - Prob. 8.22QPCh. 8 - Prob. 8.23QPCh. 8 - Prob. 8.24QPCh. 8 - Prob. 8.25QPCh. 8 - Prob. 8.26QPCh. 8 - Prob. 8.27QPCh. 8 - Prob. 8.28QPCh. 8 - Prob. 8.29QPCh. 8 - Prob. 8.30QPCh. 8 - Prob. 8.31QPCh. 8 - Prob. 8.32QPCh. 8 - Prob. 8.33QPCh. 8 - Prob. 8.34QPCh. 8 - Prob. 8.35QPCh. 8 - Prob. 8.36QPCh. 8 - Prob. 8.37QPCh. 8 - Prob. 8.38QPCh. 8 - Prob. 8.39QPCh. 8 - Prob. 8.40QPCh. 8 - Prob. 8.41QPCh. 8 - Prob. 8.42QPCh. 8 - Prob. 8.43QPCh. 8 - Prob. 8.44QPCh. 8 - Prob. 8.45QPCh. 8 - Prob. 8.46QPCh. 8 - Prob. 8.47QPCh. 8 - Prob. 8.48QPCh. 8 - Prob. 8.49QPCh. 8 - Prob. 8.50QPCh. 8 - Prob. 8.51QPCh. 8 - Prob. 8.52QPCh. 8 - Prob. 8.53QPCh. 8 - Prob. 8.54QPCh. 8 - Prob. 8.55QPCh. 8 - Prob. 8.56QPCh. 8 - Prob. 8.57QPCh. 8 - Prob. 8.58QPCh. 8 - Prob. 8.59QPCh. 8 - Prob. 8.60QPCh. 8 - Prob. 8.61QPCh. 8 - Prob. 8.62QPCh. 8 - Prob. 8.63QPCh. 8 - Prob. 8.64QPCh. 8 - Prob. 8.65QPCh. 8 - Prob. 8.66QPCh. 8 - Prob. 8.67QPCh. 8 - Prob. 8.68QPCh. 8 - Prob. 8.69QPCh. 8 - Prob. 8.70QPCh. 8 - Prob. 8.71QPCh. 8 - Prob. 8.72QPCh. 8 - Prob. 8.73QPCh. 8 - Prob. 8.74QPCh. 8 - Prob. 8.75QPCh. 8 - Prob. 8.76QPCh. 8 - Prob. 8.77QPCh. 8 - Prob. 8.78QPCh. 8 - Prob. 8.79QPCh. 8 - Prob. 8.80QPCh. 8 - Prob. 8.81QPCh. 8 - Prob. 8.82QPCh. 8 - Prob. 8.83QPCh. 8 - Prob. 8.84QPCh. 8 - Prob. 8.85QPCh. 8 - Prob. 8.86QPCh. 8 - Prob. 8.87QPCh. 8 - Prob. 8.88QPCh. 8 - Prob. 8.89QPCh. 8 - Prob. 8.90QPCh. 8 - Prob. 8.91QPCh. 8 - Prob. 8.92QPCh. 8 - Prob. 8.93QPCh. 8 - Prob. 8.94QPCh. 8 - Prob. 8.95QPCh. 8 - Prob. 8.96QPCh. 8 - Prob. 8.97QPCh. 8 - Prob. 8.98QPCh. 8 - Prob. 8.99QPCh. 8 - Prob. 8.100QPCh. 8 - Prob. 8.101QPCh. 8 - Prob. 8.102QPCh. 8 - Prob. 8.103QPCh. 8 - Prob. 8.104QPCh. 8 - Prob. 8.105QPCh. 8 - Prob. 8.106QPCh. 8 - Prob. 8.107QPCh. 8 - Prob. 8.108QPCh. 8 - Prob. 8.109QPCh. 8 - Prob. 8.110QPCh. 8 - Prob. 8.111QPCh. 8 - Prob. 8.112QPCh. 8 - Prob. 8.113QPCh. 8 - Prob. 8.114QPCh. 8 - Prob. 8.115QPCh. 8 - Prob. 8.116QPCh. 8 - Prob. 8.117QPCh. 8 - Prob. 8.118QPCh. 8 - Prob. 8.119QPCh. 8 - Prob. 8.120QPCh. 8 - Prob. 8.121QPCh. 8 - Prob. 8.122QPCh. 8 - Prob. 8.123QPCh. 8 - Prob. 8.124QPCh. 8 - Prob. 8.125QPCh. 8 - Prob. 8.126QPCh. 8 - Prob. 8.127QPCh. 8 - Prob. 8.128QPCh. 8 - Prob. 8.129QPCh. 8 - Prob. 8.130QPCh. 8 - Prob. 8.131QPCh. 8 - Prob. 8.132QPCh. 8 - Prob. 8.133QPCh. 8 - Prob. 8.134QPCh. 8 - Prob. 8.135QPCh. 8 - Prob. 8.136QPCh. 8 - Prob. 8.137QPCh. 8 - Prob. 8.138QPCh. 8 - Prob. 8.139APCh. 8 - Prob. 8.140APCh. 8 - Prob. 8.141APCh. 8 - Prob. 8.142APCh. 8 - Prob. 8.143APCh. 8 - Prob. 8.144APCh. 8 - Prob. 8.145APCh. 8 - Prob. 8.146APCh. 8 - Prob. 8.147APCh. 8 - Prob. 8.148APCh. 8 - Prob. 8.149APCh. 8 - Prob. 8.150APCh. 8 - Prob. 8.151APCh. 8 - Prob. 8.152APCh. 8 - Prob. 8.153APCh. 8 - Prob. 8.154APCh. 8 - Prob. 8.155APCh. 8 - Prob. 8.156APCh. 8 - Prob. 8.157APCh. 8 - Prob. 8.158APCh. 8 - Prob. 8.159APCh. 8 - Prob. 8.160APCh. 8 - Prob. 8.161APCh. 8 - Prob. 8.162APCh. 8 - Prob. 8.163APCh. 8 - Prob. 8.164APCh. 8 - Prob. 8.165APCh. 8 - Prob. 8.166APCh. 8 - Prob. 8.167APCh. 8 - Prob. 8.168APCh. 8 - Prob. 8.169APCh. 8 - Prob. 8.170APCh. 8 - Prob. 8.171APCh. 8 - Prob. 8.172APCh. 8 - Prob. 8.173APCh. 8 - Prob. 8.174APCh. 8 - Prob. 8.175AP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Incorrect Row 2: Your answer is incorrect. Consider this molecule: How many H atoms are in this molecule? 22 How many different signals could be found in its 'H NMR spectrum? 12 Note: A multiplet is considered one signal.arrow_forward13 How many signals would you expect to see in the Check O signal(s) X § 'C NMR spectrum for the following compound? © 2025 McGraw Hillarrow_forward13 Consider the "C NMR spectrum below. 140 120 100 80 60 40 20 20 PPM 0 The spectrum belongs to which one of the following constitutional isomers of the compound C,H12? Select the single best answer. Check ✓ G Save For Later 2025 McGraw Hill LLC. All Rights Reserved. Terms of Usearrow_forward
- The structure of compound 1,3,5-trimethylbenzene (mesitylene) is given below. How many signals would you expect to find in the 'H NMR spectrum of 1,3,5-trimethylbenzene (mesitylene)? Check ×arrow_forward1 How many signals do you expect in the 'H NMR spectrum for this molecule? CI CI Cl Write the answer in the table below. Also, in each of the drawing areas below is a copy of the molecule, with H atoms shown. In each copy, one of the H atoms is highlighted red. Highlight in red all other H atoms that would contribute to the same signal as the H already highlighted red. Note for advanced students: Remember, a multiplet is considered one signal in the 'H NMR spectrum. 1 Number of signals in the 'H NMR spectrum. ☐ For the molecule in the top drawing area, highlight in red any other H atoms that will contribute to the same signal as the H atom already highlighted red. If no other H atoms will contribute, check the box at right. No additional H atoms to highlight in top molecule For the molecule in the bottom drawing area, highlight in red any other H atoms that will contribute to the same signal as the H atom already highlighted red. If no other H atoms will contribute, check the box at…arrow_forwardwrtie the balanced equation and find the E° when the following half- reactions are combined Zn2+(aq) + 2e---> Zn(s) E°= -0.763V Ag+(aq) + e---> Ag (s) E°=+0.799Varrow_forward
- Consider this molecule: How many H atoms are in this molecule? How many different signals could be found in its 'H NMR spectrum? Note: A multiplet is considered one signal. ☐arrow_forwardStudy this 'H NMR spectrum, and then answer the questions about it in the table below. Check 1.0- 0.5- 0.0 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 0.0 What unit symbol should be written on the horizontal axis? What is the chemical shift & of the doublet? If there is no doublet, just check the box instead. Give your answer to 2 significant digits. What is the chemical shift of the signal immediately upfield of the doublet? If there is no doublet, or no signal upfield of it, check the box instead. What is the chemical shift & of the least deshielded proton? If you can't tell without more information, check the box instead. 血 8 = ☐ There is no doublet. 8 = ☐ No such signal. 8 = 0 Need more information.arrow_forwardhow many moles of H2O2 are required to react with 11g of N2H4 according to the following reaction? (atomic weights: N=14.01, H=1.008, O= 16.00) 7H2O2 + N2H4 -> 2HNO3 + 8H20arrow_forward
- calculate the number of moles of H2 produced from 0.78 moles of Ga and 1.92 moles HCL? 2Ga+6HCL->2GaCl3+3H2arrow_forwardan adult human breathes 0.50L of air at 1 atm with each breath. If a 50L air tank at 200 atm is available, how man y breaths will the tank providearrow_forwardWhat are the advantages and/or disadvantages of using the MOHR titration method & AOEC method?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
Calorimetry Concept, Examples and Thermochemistry | How to Pass Chemistry; Author: Melissa Maribel;https://www.youtube.com/watch?v=nSh29lUGj00;License: Standard YouTube License, CC-BY