CHEMISTRY IN FOCUS W/ OWL (LL)>IP<
CHEMISTRY IN FOCUS W/ OWL (LL)>IP<
6th Edition
ISBN: 9781337306317
Author: Tro
Publisher: CENGAGE L
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Chapter 8, Problem 8.1YT
Interpretation Introduction

Interpretation:

The nuclear equation that represents alpha decay is to be written.

Concept Introduction:

An alpha particle consists of two protons and two neutrons. It is a He nucleus emitted by a decaying atomic nucleus. Alpha particles can be represented with the symbol, 42He.

Expert Solution & Answer
Check Mark

Answer to Problem 8.1YT

Solution:

22688Ra22286Rn+H24e+γ00

Explanation of Solution

An alpha particle consists of two protons and two neutrons. During alpha decay, reactant reacts and emits an alpha particle and attains an atomic number that is two less than its original atomic number and a mass number that is four less than its original mass number.

Thus, Ra-226 decays through alpha particle emission to form 22286Rn.

It is to be noted that the sum of the numbers present in superscripts, that is the mass numbers of the reactants and the products, should be the same on both side. Also, the sums of number present in subscripts, that is the atomic numbers, should be the same on both sides.

Conclusion

In this reaction, 22688Ra decays via alpha emission to produce 22286Rn. The equation is written as:

22688Ra22286Rn+H24e+γ00

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