CHEMISTRY IN FOCUS W/ OWL (LL)>IP<
6th Edition
ISBN: 9781337306317
Author: Tro
Publisher: CENGAGE L
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Chapter 8, Problem 58E
Interpretation Introduction
Interpretation:
The best-suited radiation for the given technique is to be determined.
Concept introduction:
Alpha rays are also called alpha radiations. They are composed of two neutrons and two protons, which are tightly bound together by a strong force.
Beta rays are also called beta radiations. They are high-speed electrons and can be emitted by the radioactive decay of an atomic nucleus.
Gamma rays are the type of X-rays that contains
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Please note that it is correct and explains it rightly:The proportion of O, C and H in the graphite oxide is:a) Constant, for the quantities of functional groups of acids, phenols, epoxy, etc. its constantsb) Depending on the preparation method, as much oxidant as the graphite is destroyed and it has less oxygenc) Depends on the structure of the graphic being processed, whether it can be more three-dimensional or with larger crystals, or with smaller crystals and more borders.
The proportion of O, C and H in the graphite oxide is constant, only the cantidades of functional groups of acids, phenols, epoxy, etc. its constants. ¿Is it correct?
The proportion of O, C and H in the graphite oxide depends on the structure of the graph that is processed, which may be more tridimensional or with larger crystals, or with smaller crystals and more borders. ¿Is it correct?
Chapter 8 Solutions
CHEMISTRY IN FOCUS W/ OWL (LL)>IP<
Ch. 8 - Prob. 8.1YTCh. 8 - Prob. 8.2YTCh. 8 - Prob. 8.3YTCh. 8 - Prob. 8.4YTCh. 8 - Prob. 8.5YTCh. 8 - Prob. 1SCCh. 8 - Prob. 2SCCh. 8 - Prob. 3SCCh. 8 - Prob. 4SCCh. 8 - Prob. 5SC
Ch. 8 - Prob. 6SCCh. 8 - Prob. 7SCCh. 8 - Prob. 1ECh. 8 - Prob. 2ECh. 8 - Prob. 3ECh. 8 - Prob. 4ECh. 8 - Prob. 5ECh. 8 - Prob. 6ECh. 8 - Prob. 7ECh. 8 - Prob. 8ECh. 8 - Prob. 9ECh. 8 - Prob. 10ECh. 8 - Prob. 11ECh. 8 - Prob. 12ECh. 8 - Prob. 13ECh. 8 - Prob. 14ECh. 8 - Prob. 15ECh. 8 - Prob. 16ECh. 8 - Prob. 17ECh. 8 - Prob. 18ECh. 8 - Prob. 19ECh. 8 - Prob. 20ECh. 8 - Prob. 21ECh. 8 - Prob. 22ECh. 8 - Prob. 23ECh. 8 - Prob. 24ECh. 8 - Prob. 25ECh. 8 - Prob. 26ECh. 8 - Prob. 27ECh. 8 - Prob. 28ECh. 8 - Prob. 29ECh. 8 - Prob. 30ECh. 8 - Prob. 31ECh. 8 - Prob. 32ECh. 8 - Prob. 33ECh. 8 - Prob. 34ECh. 8 - Prob. 35ECh. 8 - Prob. 36ECh. 8 - Prob. 37ECh. 8 - Prob. 38ECh. 8 - Prob. 39ECh. 8 - Prob. 40ECh. 8 - Prob. 42ECh. 8 - Prob. 43ECh. 8 - Prob. 44ECh. 8 - Prob. 45ECh. 8 - Prob. 46ECh. 8 - Prob. 47ECh. 8 - Prob. 48ECh. 8 - Prob. 49ECh. 8 - Prob. 50ECh. 8 - Prob. 51ECh. 8 - Prob. 52ECh. 8 - Prob. 53ECh. 8 - Prob. 54ECh. 8 - Prob. 55ECh. 8 - Prob. 56ECh. 8 - Prob. 57ECh. 8 - Prob. 58ECh. 8 - Prob. 59ECh. 8 - Prob. 62ECh. 8 - Prob. 63ECh. 8 - Prob. 64ECh. 8 - Prob. 65ECh. 8 - Prob. 66ECh. 8 - Prob. 67ECh. 8 - Prob. 68ECh. 8 - Prob. 69ECh. 8 - Prob. 70E
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- In mixed oxides with superconducting properties, we find Cu:a) Frequentlyb) Alwaysc) Almost neverarrow_forwardThe proportion of O, C and H in the graphite oxide depends on the preparation method, as long as the most oxidant, the most graphite is destroyed and has less O. Is it correct?arrow_forwardWrite the complete common (not IUPAC) name of each molecule below. Note: if a molecule is one of a pair of enantiomers, be sure you start its name with D- or L- so we know which enantiomer it is. molecule C=O H3N CH3 common name (not the IUPAC name) H ☐ C=O H O-C-CH2-CH2 010 NH3 ☐ H3N ☐ HO 5arrow_forward
- Write the systematic name of each organic molecule: structure CI CH3 HO-C-CH-CH-CH2 – CH— CH3 CH3 name X O ☐ CH3-CH-CH2-CH2-C-OH CH3 11 HO-C-CH-CH2-OH CH3 ☐arrow_forwardCheck the box under each a amino acid. If there are no a amino acids at all, check the "none of them" box under the table. Note for advanced students: don't assume every amino acid shown must be found in nature. CH3 CH2 0 C=O + CH-CH3 H₂N C-COOH H₂N H H H3N C COO¯ NH, O HO C C H CH3-CH HO C=O H2N-CH-COOH CH2 NH3 HO CH3 none of them O NH3arrow_forwardhandwritten answer please!arrow_forward
- Consider the following SN 2 reaction: مار + Br H₂O acetone + Br OH What effect would each of the following changes have on the rate of this reaction. Select the single best answer for each part. Part 1 of 3 If the substrate was changed to: The rate would Br O increase O decrease O remain unchanged Part 2 of 3 × S If the nucleophile was changed to OH, the rate would: O increase O decrease O remain unchanged Part 3 of 3 If the solvent was changed to ethanol, the rate would: Increase O decrease O remain unchanged 2 ol Ararrow_forwardConsider the following nucleophilic substitution reaction. The compound listed above the arrow is the solvent for the reaction. If nothing is listed over the arrow, then the nucleophile is also the solvent for the reaction. Part: 0/2 Part 1 of 2 Br acetone + I What is the correct mechanism for the reaction? Select the single best answer. OSN 1 OSN 2 X Part: 1/2 Part 2 of 2 Draw the products for the reaction. Include both the major organic product and the inorganic product. If more than one stereoisomer is possible, draw only one stereoisomer. Include stereochemistry where relevant. Click and drag to start drawing a structure. Х 5 ☐arrow_forwardTriethyloxonium tetrafluoroborate reacts with ethanol (CH3CH2OH) to give diethyl ether (CH3CH2OCH2CH3). BF triethyloxonium tetrafluoroborate Which equation, including the curved arrows, best represents the rate-determining step in the mechanism? Select the single best answer. O OH CH3CH2 OH + H. 0+ CH₂H₂ :0 + 0+ ж + H + :0: 0 Carrow_forward
- CH3CH2CH=CH2 + H₂O − H+arrow_forwardГ C-RSA CHROMATOPAC CH=1 DATA 1: @CHRM1.C00 ATTEN=10 SPEED= 10.0 0.0 b.092 0.797 1.088 1.813 C-RSA CHROMATOPAC CH=1 Report No. =13 ** CALCULATION REPORT ** DATA=1: @CHRM1.000 11/03/05 08:09:52 CH PKNO TIME 1 2 0.797 3 1.088 4 1.813 AREA 1508566 4625442 2180060 HEIGHT 207739 701206 V 287554 V MK IDNO CONC NAME 18.1447 55.6339 26.2213 TOTAL 8314067 1196500 100 C-R8A CHROMATOPAC CH=1 DATA 1: @CHRM1.C00 ATTEN=10 SPEED= 10.0 0. 0 087 337. 0.841 1.150 C-R8A CHROMATOPAC CH=1 Report No. =14 DATA=1: @CHRM1.000 11/03/05 08:12:40 ** CALCULATION REPORT ** CH PKNO TIME AREA 1 3 0.841 1099933 41.15 4039778 HEIGHT MK IDNO 170372 649997¯¯¯ CONC NAME 21.4007 78.5993 TOTAL 5139711 820369 100 3 C-R8A CHROMATOPAC CH=1 DATA 1: @CHRM1.C00 ATTEN=10 SPEED= 10.0 0.100 0:652 5.856 3 1.165 C-RSA CHROMATOPAC CH-1 Report No. =15 DATA=1: @CHRM1.000 11/03/05 08:15:26 ** CALCULATION REPORT ** CH PKNO TIME AREA HEIGHT MK IDNO CONC NAME 1 3 3 0.856 4 1.165 TOTAL 1253386 4838738 175481 708024 V 20.5739 79.4261 6092124…arrow_forwardIndicate the product that is obtained if the benzotriazole reacts with the use of a medium basic product.arrow_forward
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