![Organic Chemistry Study Guide and Solutions](https://www.bartleby.com/isbn_cover_images/9781936221868/9781936221868_largeCoverImage.gif)
Concept explainers
(a)
Interpretation:
To identify the given compound as primary, secondary or tertiary alkyl halide and give a common name to the given compound.
Concept introduction:
Alkyl halide refers to those organic compounds that consist of halogen atom as a
In primary alkyl halide, the halogen group is attached to a carbon atom that is connected to two hydrogen atoms and the other carbon atom.
In secondary alkyl halide, the halogen group is attached to a carbon atom that is connected to two carbon atoms and one hydrogen atom.
In tertiary alkyl halide, the halogen group is attached to a carbon atom that is connected to three carbon atoms.
![Check Mark](/static/check-mark.png)
Answer to Problem 8.1P
The common name of the given compound is isobutyl fluoride. It is a primary alkyl halide.
Explanation of Solution
The given compound is
The fluorine atom is attached to a carbon atom that is connected to two hydrogen atoms and the other carbon atom. Therefore, it is a primary alkyl halide.
The common name of the given compound is isobutyl fluoride. It is a primary alkyl halide.
(b)
Interpretation:
To identify the given compound as primary, secondary or tertiary alkyl halide and give a common name to the given compound.
Concept introduction:
Alkyl halide refers to those organic compounds that consist of halogen atom as a functional group attached to the alkyl chain. The general formula is
In primary alkyl halide, the halogen group is attached to a carbon atom that is connected to two hydrogen atoms and the other carbon atom.
In secondary alkyl halide, the halogen group is attached to a carbon atom that is connected to two carbon atoms and one hydrogen atom.
In tertiary alkyl halide, the halogen group is attached to a carbon atom that is connected to three carbon atoms.
![Check Mark](/static/check-mark.png)
Answer to Problem 8.1P
The common name of the given compound is n-hexyl iodide. It is a primary alkyl halide.
Explanation of Solution
The given compound is
The iodine atom is attached to a carbon atom that is connected to two hydrogen atoms and the other carbon atom. Therefore, it is a primary alkyl halide.
The common name of the given compound is n-hexyl iodide. It is a primary alkyl halide.
(c)
Interpretation:
To identify the given compound as primary, secondary or tertiary alkyl halide and give a common name to the given compound.
Concept introduction:
Alkyl halide refers to those organic compounds that consist of halogen atom as a functional group attached to the alkyl chain. The general formula is
In primary alkyl halide, the halogen group is attached to a carbon atom that is connected to two hydrogen atoms and the other carbon atom.
In secondary alkyl halide, the halogen group is attached to a carbon atom that is connected to two carbon atoms and one hydrogen atom.
In tertiary alkyl halide, the halogen group is attached to a carbon atom that is connected to three carbon atoms.
![Check Mark](/static/check-mark.png)
Answer to Problem 8.1P
The common name of the given compound is cyclopentyl bromide. It is a secondary alkyl halide.
Explanation of Solution
The given compound is shown below.
Figure 1
It contains a ring of five carbon atoms. Bromine is attached to the second carbon atom. Therefore, the common name of this compound is cyclopentyl bromide.
The bromine atom is attached to a carbon atom that is connected to two carbon atoms and one hydrogen atom. Therefore, it is a secondary alkyl halide.
The common name of the given compound is cyclopentyl bromide. It is a secondary alkyl halide.
(d)
Interpretation:
To identify the given compound as primary, secondary or tertiary alkyl halide and give a common name to the given compound.
Concept introduction:
Alkyl halide refers to those organic compounds that consist of halogen atom as a functional group attached to the alkyl chain. The general formula is
In primary alkyl halide, the halogen group is attached to a carbon atom that is connected to two hydrogen atoms and the other carbon atom.
In secondary alkyl halide, the halogen group is attached to a carbon atom that is connected to two carbon atoms and one hydrogen atom.
In tertiary alkyl halide, the halogen group is attached to a carbon atom that is connected to three carbon atoms.
![Check Mark](/static/check-mark.png)
Answer to Problem 8.1P
The common name of the given compound is neopentyl chloride. It is a primary alkyl halide.
Explanation of Solution
The given compound is shown below.
Figure 2
It contains five carbon atoms. Chlorine is attached to the first carbon atom and three methyl groups are attached to the second carbon atom. Therefore, the prefix –neo is used before the name of an alkyl halide. Therefore, the common name of this compound is neopentyl chloride.
The chloride atom is attached to a carbon atom that is connected to two hydrogen atoms and the other carbon atom. Therefore, it is a primary alkyl halide.
The common name of the given compound is neopentyl chloride. It is a primary alkyl halide.
Want to see more full solutions like this?
Chapter 8 Solutions
Organic Chemistry Study Guide and Solutions
- Nonearrow_forward3. A molecular form of "dicarbon", C2, can be generated in gas phase. Its bond dissociation energy has been determined at 599 kJ/mol. Use molecular orbital theory to explain why energy of dissociation for C₂+ is 513 kJ/mol, and that for C2² is 818 kJ/mol. (10 points)arrow_forward9.73 g of lead(IV) chloride contains enough Cl- ions to make ____ g of magnesium chloride.arrow_forward
- 6. a) C2's. Phosphorus pentafluoride PF5 belongs to D3h symmetry group. Draw the structure of the molecule, identify principal axis of rotation and perpendicular (4 points) b) assume that the principal axis of rotation is aligned with z axis, assign symmetry labels (such as a1, b2, etc.) to the following atomic orbitals of the P atom. (character table for this group is included in the Supplemental material). 3s 3pz (6 points) 3dz²arrow_forward2. Construct Lewis-dot structures, and draw VESPR models for the ions listed below. a) SiF5 (4 points) b) IOF4 (4 points)arrow_forward5. Complex anion [AuCl2]¯ belongs to Doh symmetry point group. What is the shape of this ion? (4 points)arrow_forward
- 4. Assign the following molecules to proper point groups: Pyridine N 1,3,5-triazine N Narrow_forward7. a) Under normal conditions (room temperature & atmospheric pressure) potassium assumes bcc lattice. Atomic radius for 12-coordinate K atom is listed as 235 pm. What is the radius of potassium atom under normal conditions? (3 points) b) Titanium metal crystallyzes in hcp lattice. Under proper conditions nitrogen can be absorbed into the lattice of titanium resulting in an alloy of stoichiometry TiNo.2. Is this compound likely to be a substitutional or an interstitial alloy? (Radius of Ti (12-coordinate) is 147 pm; radius of N atom is 75 pm. (3 points)arrow_forwardcan someone answer the questions and draw out the complete mechanismarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781259911156/9781259911156_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305577213/9781305577213_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780078021558/9780078021558_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305079373/9781305079373_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781118431221/9781118431221_smallCoverImage.gif)