Explanation 1) Concept: We have the results of titration of apple cider vinegar (acetic acid) with a strong basic titrant N a O H . We know the volume and concentration of titrant and volume of sample and need to find the concentration of acetic acid in vinegar expressed as percent by mass. We need to fist write the balanced chemical equation between acetic acid and N a O H : N a O H a q + C H 3 C O O H a q → H 2 O l + C H 3 C O O N a a q Acetic acid has one ionizable H , so the mole ratio between acetic acid and the titrant ( N a O H ) is 1 : 1 . Using concentration (molarity) and volume, we will find moles of N a O H . We will convert moles of N a O H into acetic acid using stoichiometry of the reaction. We will convert moles of acetic acid to grams using molar mass of acetic acid. The mass of solution is calculated by using the density and volume of solution. 2) Formula: i) M = n V ii) m a s s % = M a s s o f c o m p o n e n t M a s s o f s a m p l e × 100 iii) 1 L = 1000 m L iv) d = m V 3) Given: i) Molarity of N a O H = 1.002 M ii) Volume of N a O H = 25.00 m L iii) Density of vinegar sample is 1.10 g / m L iv) Volume of vinegar sample is 20.78 m L 4) Calculation: Calculate the mass of vinegar using given volume and density. 20.78 m L × 1.10 g 1 m L = 22.86 g Convert the volume of N a O H in mL to L as 25.00 m L × 1 L 1000 m L = 0.02500 L N a O H Calculate the moles of N a O H using given molarity and volume

14th Edition

ISBN: 9780393912340

Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster

Publisher: W. W. Norton & Company

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Chapter 8, Problem 8.126QA

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The concentration of acetic acid in vinegar as percent by mass.

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Chapter 8, Problem 8.125QA

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Chemistry: An Atoms-Focused Approach

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