Write a balanced equation for the preparation of (a) molecular oxygen, (b) ammonia, (c) carbon dioxide, (d) molecular hydrogen, (e) calcium oxide. Indicate the physical state of the reactants and products in each equation.
(a)
Interpretation:
The balanced equation for the preparation of molecular oxygen has to be given indicating the physical state of the reactants and products.
Concept Introduction:
- Chemical equation is the representation of a chemical reaction, in which the reactants and products of the reactions are represented left and right side of an arrow respectively by using their respective chemical formulas.
- Reactant of a chemical reaction is the substrate compounds or the compounds which undergo a chemical reaction.
- Product of a chemical reaction is the produced compounds or the compounds formed after a chemical reaction.
- Balanced chemical equation of a reaction is written according to law of conservation of mass.
Answer to Problem 8.117QP
The balanced equation for the preparation of molecular oxygen can be given as:
Explanation of Solution
Molecular oxygen is prepared from
Here, the number of each element on both sides is made equal by giving the coefficient 2 for the reactant
Therefore,
The balanced equation for the preparation of molecular oxygen can be given as:
(b)
Interpretation:
The balanced equation for the preparation of ammonia has to be given indicating the physical state of the reactants and products.
Concept Introduction:
- Chemical equation is the representation of a chemical reaction, in which the reactants and products of the reactions are represented left and right side of an arrow respectively by using their respective chemical formulas.
- Reactant of a chemical reaction is the substrate compounds or the compounds which undergo a chemical reaction.
- Product of a chemical reaction is the produced compounds or the compounds formed after a chemical reaction.
- Balanced chemical equation of a reaction is written according to law of conservation of mass.
Answer to Problem 8.117QP
The balanced equation for the preparation of ammonia can be given as:
Explanation of Solution
Ammonia is prepared by the reaction between nitrogen and hydrogen. Reaction for the preparation of ammonia can be given as:
Here, the number of each element on both sides is made equal by giving the coefficient 2 for the product
Therefore,
The balanced equation for the preparation of ammonia can be given as:
(c)
Interpretation:
The balanced equation for the preparation of carbon dioxide has to be given indicating the physical state of the reactants and products.
Concept Introduction:
- Chemical equation is the representation of a chemical reaction, in which the reactants and products of the reactions are represented left and right side of an arrow respectively by using their respective chemical formulas.
- Reactant of a chemical reaction is the substrate compounds or the compounds which undergo a chemical reaction.
- Product of a chemical reaction is the produced compounds or the compounds formed after a chemical reaction.
- Balanced chemical equation of a reaction is written according to law of conservation of mass.
Answer to Problem 8.117QP
The balanced equation for the preparation of carbon dioxide can be given as:
Explanation of Solution
Carbon dioxide is prepared from
Here, the number of each element on both sides is equal.
Therefore,
The balanced equation for the preparation of carbon dioxide can be given as:
(d)
Interpretation:
The balanced equation for the preparation of molecular hydrogen has to be given indicating the physical state of the reactants and products.
Concept Introduction:
- Chemical equation is the representation of a chemical reaction, in which the reactants and products of the reactions are represented left and right side of an arrow respectively by using their respective chemical formulas.
- Reactant of a chemical reaction is the substrate compounds or the compounds which undergo a chemical reaction.
- Product of a chemical reaction is the produced compounds or the compounds formed after a chemical reaction.
- Balanced chemical equation of a reaction is written according to law of conservation of mass.
Answer to Problem 8.117QP
The balanced equation for the preparation of molecular hydrogen can be given as:
Explanation of Solution
Molecular hydrogen is prepared by the reaction between
Here, the number of each element on both sides is equal.
Therefore,
The balanced equation for the preparation of molecular hydrogen can be given as:
(e)
Interpretation:
The balanced equation for the preparation of calcium oxide has to be given indicating the physical state of the reactants and products.
Concept Introduction:
- Chemical equation is the representation of a chemical reaction, in which the reactants and products of the reactions are represented left and right side of an arrow respectively by using their respective chemical formulas.
- Reactant of a chemical reaction is the substrate compounds or the compounds which undergo a chemical reaction.
- Product of a chemical reaction is the produced compounds or the compounds formed after a chemical reaction.
- Balanced chemical equation of a reaction is written according to law of conservation of mass.
Answer to Problem 8.117QP
The balanced equation for the preparation of calcium oxide can be given as:
Explanation of Solution
Calcium oxide is prepared from
Here, the number of each element on both sides is equal.
Therefore,
The balanced equation for the preparation of calcium oxide can be given as:
Want to see more full solutions like this?
Chapter 8 Solutions
Chemistry
Additional Science Textbook Solutions
HUMAN ANATOMY
College Physics: A Strategic Approach (3rd Edition)
Human Biology: Concepts and Current Issues (8th Edition)
Microbiology: An Introduction
General, Organic, and Biological Chemistry - 4th edition
Campbell Essential Biology (7th Edition)
- Complete the following synthesis. (d). H+ ง сarrow_forwardCan the target compound be efficiently synthesized in good yield from the substituted benzene of the starting material? If yes, draw the synthesis. Include all steps and all reactants.arrow_forwardThis is a synthesis question. Why is this method wrong or worse than the "correct" method? You could do it thiss way, couldn't you?arrow_forward
- Try: Draw the best Lewis structure showing all non-bonding electrons and all formal charges if any: (CH3)3CCNO NCO- HN3 [CH3OH2]*arrow_forwardWhat are the major products of the following reaction? Draw all the major products. If there are no major products, then there is no reaction that will take place. Use wedge and dash bonds when necessary.arrow_forwardZeolites. State their composition and structure. Give an example.arrow_forward
- Don't used hand raiting and show all reactionsarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardIX) By writing the appropriate electron configurations and orbital box diagrams briefly EXPLAIN in your own words each one of the following questions: a) The bond length of the Br2 molecule is 2.28 Å, while the bond length of the compound KBr is 3.34 Å. The radius of K✶ is 1.52 Å. Determine the atomic radius in Å of the bromine atom and of the bromide ion. Br = Br b) Explain why there is a large difference in the atomic sizes or radius of the two (Br and Br). Tarrow_forward
- When 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol.arrow_forwardWhen 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol. Which experimental number must be initialled by the Lab TA for the first run of Part 1 of the experiment? a) the heat capacity of the calorimeter b) Mass of sample c) Ti d) The molarity of the HCl e) Tfarrow_forwardPredict products for the Following organic rxn/s by writing the structurels of the correct products. Write above the line provided" your answer D2 ①CH3(CH2) 5 CH3 + D₂ (adequate)" + 2 mited) 19 Spark Spark por every item. 4 CH 3 11 3 CH 3 (CH2) 4 C-H + CH3OH CH2 CH3 + CH3 CH2OH 0 CH3 fou + KMnDy→ C43 + 2 KMn Dy→→ C-OH ") 0 C-OH 1110 (4.) 9+3 =C CH3 + HNO 3 0 + Heat> + CH3 C-OH + Heat CH2CH3 - 3 2 + D Heat H 3 CH 3 CH₂ CH₂ C = CH + 2 H₂ → 2 2arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
- Chemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStaxChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning