Unit Operations Of Chemical Engineering
7th Edition
ISBN: 9789339213237
Author: MCCABE, WARREN
Publisher: Tata McGraw-Hill Education India
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Chapter 8, Problem 8.10P
(a)
Interpretation Introduction
Interpretation:
The accuracy of flow measurement is to be determined for gas under heat exposure.
Concept Introduction:
The temperature rise in gases due to heating occurs due to molecular movement. On the other hand, the molecular movement depends on the duct dimensions and flow velocity. Lastly, the heat capacity of gas mixture depends on the mass fraction of constitute gases and its respective heat capacities.
(b)
Interpretation Introduction
Interpretation:
To determine the effect of reduced mass fraction of one of the constituent gases in the mixture.
Concept Introduction:
The heat capacity of gas mixture depends on the mass fraction of constitute gases and its respective heat capacities.
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Only focus on H(3), which the answer is minus 1.26 KJ/mol. This also has the ideal gas of nitrogen gas N2. Two enthalpies need to be calculated for this. The first enthalpy is H = (specific volume) times (pressure difference). For the specific volume of nitrogen, how was 12.089 x10^(-5) m^3/mol obtained? I understand the second enthalpy for the heat capacity for nitrogen gas.
chemical engineering.
The answer for H(3) is minus 1.26 KJ/mol. Demonstrate the reference state to the process state for nitrogen gas. I know that is an ideal gas law for the nitrogen gas. I know how to calculate the heat capacity for this.
Chapter 8 Solutions
Unit Operations Of Chemical Engineering
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- 1. The settling chamber, shown schematically in Figure 2E1.1, is used as a primary separation device in the removal of dust particles of density 1500 kg/m³ from a gas of density 0:7 kg/m³ and viscosity 1.90 x 10-5 Pa s. Gas inlet Elevation Gas Gas exit exit H Collection surface -W Section X-X Dimensions: H=3m L = 10 m W=2m Figure 2E1.1 Schematic diagram of settling chamber Assuming Stokes' law applies, show that the efficiency of collection of particles of size x is given by the expression collection efficiency, x = x²8(pp - Pi)L 18μHU where U is the uniform gas velocity through the parallel-sided section of the chamber. State any other assumptions made. (b) What is the upper limit of particle size for which Stokes' law applies? (c) When the volumetric flow rate of gas is 0.9 m³/s, and the dimensions of the chamber are those shown in Figure 2E1.1, determine the collection efficiency for spherical particles of diameter 30 mm.arrow_forwardCan you answer this sequantially correct like show me the full process. Also, since it is chemical engineering related problem a perry's handbook is used. Thank youarrow_forwardchemical engineering Demonstrate how each specific enthalpy was calculated, from the reference state to the process state. Be thorough to the fullest. This is a material-energy balance. The answers are H(1) = 35.7 KJ/kmol, H(2) = 32.0 KJ/kmol, and H(3) = -1.26 KJ/kmol.arrow_forward
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