Explanation Given information: The altitude range of a satellite is 230 km to 890 km. The satellite moves at 7.23 km/s in its highest point. Calculation: The lowest point refers to perigee and the highest point refers to apogee. The speed at apogee is v a = 7.23 km/s . Refer “Appendix E” in the textbook for the Astrophysical date of Earth. Radius of the Earth is 6.37 × 10 6 m . Mass of the Earth is 5 .97 × 10 24 kg . The distance to perigee measured from the center of the Earth is r p = h p + R E . Here, h p is the altitude at perigee and R E is the radius of the Earth. Therefore, r p = 230 km + 6.37 × 10 6 m = 230 km × 10 3 m 1 km + 6.37 × 10 6 m = 6.6 × 10 6 m The distance to apogee measured from the center of the Earth is r a = h a + R E . Here, h a is the altitude at apogee. Therefore, r a = 890 km + 6.37 × 10 6 m = 890 km × 10 3 m 1 km + 6.37 × 10 6 m = 7.26 × 10 6 m Determine the speed ( v p ) at the perigee using the relation: v p = v a 2 + 2 G M E ( 1 r p − 1 r a ) (1) Here, G is the constant of universal gravitation with the value of 6

Essential University Physics Volume 1, Loose Leaf Edition (4th Edition)

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ISBN: 9780135264669

Author: Richard Wolfson

Publisher: PEARSON

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Chapter 8, Problem 58P

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The speed of the satellite at the lowest point.

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Chapter 8, Problem 57P

Chapter 8, Problem 59P

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Essential University Physics Volume 1, Loose Leaf Edition (4th Edition)

Ch. 8.2 - Suppose the distance between two objects is cut in...Ch. 8.3 - Suppose the paths in Fig. 8.8 are the paths of...Ch. 8.4 - Prob. 8.3GI Ch. 8 - What do Newtons apple and the Moon have in common?Ch. 8 - Prob. 2FTD Ch. 8 - When you stand on Earth, the distance between you...Ch. 8 - The force of gravity on an object is proportional...Ch. 8 - A friend who knows nothing about physics asks what...Ch. 8 - Could you put a satellite in an orbit that keeps...Ch. 8 - Why are satellites generally launched eastward and...

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