(a)
Interpretation: The reason as to why the given reaction does not afford the major product that is given is to be explained and the structure of the major product actually formed is to be drawn.
Concept introduction: In elimination and substitution reactions, the product formed depends on the type of halide used, the base being used and the leaving group present.
(b)
Interpretation: The reason as to why the given reaction does not afford the major product that is given is to be explained and the structure of the major product actually formed is to be drawn.
Concept introduction: In elimination and substitution reactions, the product formed depends on the type of halide in question, the base being used and the leaving group present.
(c)
Interpretation: The reason as to why the given reaction does not afford the major product that is given is to be explained and the structure of the major product actually formed is to be drawn.
Concept introduction: In elimination and substitution reactions, the product formed depends on the type of halide in question, the base being used and the leaving group present.
(d)
Interpretation: The reason as to why the given reaction does not afford the major product that is given is to be explained and the structure of the major product actually formed is to be drawn.
Concept introduction: In elimination and substitution reactions, the product formed depends on the type of halide in question, the base being used and the leaving group present.
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Chapter 8 Solutions
ORG CHEM CONNECT CARD
- 5. Use the MS data to answer the questions on the next page. 14.0 1.4 15.0 8.1 100- MS-IW-5644 26.0 2.8 27.0 6.7 28.0 1.8 29.0 80 4.4 38.0 1.0 39.0 1.5 41.0 1.2 42.0 11.2 43.0 100.0 44.0 4.3 79.0 1.9 80.0 2.6 Relative Intensity 40 81.0 1.9 82.0 2.5 93.0 8.7 20- 95.0 8.2 121.0 2.0 123.0 2.0 136.0 11.8 0 138.0 11.5 20 40 8. 60 a. Br - 0 80 100 120 140 160 180 200 220 m/z Identify the m/z of the base peak and molecular ion. 2 b. Draw structures for each of the following fragments (include electrons and charges): 43.0, 93.0, 95.0, 136.0, and 138.0 m/z. C. Draw a reasonable a-fragmentation mechanism for the fragmentation of the molecular ion to fragment 43.0 m/z. Be sure to include all electrons and formal charges. 6. Using the values provided in Appendix E of your lab manual, calculate the monoisotopic mass for the pyridinium ion (CsH6N) and show your work.arrow_forwardNonearrow_forwardStereochemistry: Three possible answers- diastereomers, enantiomers OH CH₂OH I -c=0 21108 1101 41745 HOR CH₂OH IL Но CH₂OH TIL a. Compounds I and III have this relationship with each other: enantiomers b. Compounds II and IV have this relationship with each other: c. Compounds I and II have this relationship with each other: d. *Draw one structure that is a stereoisomer of II, but neither a diastereomer nor an enantiomer. (more than one correct answer)arrow_forward
- Don't used Ai solutionarrow_forwardDon't used Ai solutionarrow_forwardIn mass spectrometry, alpha cleavages are common in molecules with heteroatoms. Draw the two daughter ions that would be observed in the mass spectrum resulting from an alpha cleavage of this molecule. + NH2 Q Draw Fragment with m/z of 72arrow_forward
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