Research Methods for the Behavioral Sciences (MindTap Course List)
5th Edition
ISBN: 9781305104136
Author: Frederick J Gravetter, Lori-Ann B. Forzano
Publisher: Wadsworth Publishing
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Chapter 8, Problem 4E
Briefly explain how a participant characteristic, such as personality, could be a confounding variable in a between subjects experiment.
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The U.S. Postal Service will ship a Priority Mail® Large Flat Rate Box (12" 3 12" 3 5½") any
where in the United States for a fixed price, regardless of weight. The weights (ounces) of 20 ran
domly chosen boxes are shown below. (a) Make a stem-and-leaf diagram. (b) Make a histogram.
(c) Describe the shape of the distribution. Weights
72 86 28 67 64 65 45 86 31 32
39 92 90 91 84 62 80 74 63 86
(a) What is a bimodal histogram? (b) Explain the difference between left-skewed, symmetric, and right-skewed histograms. (c) What is an outlier
(a) Test the hypothesis.
Consider the hypothesis test Ho
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against H₁o < 02. Suppose that the sample sizes aren₁ =
7 and n₂
= 13 and that
$²
= 22.4 and $22
= 28.2. Use α = 0.05.
Ho
is not
✓ rejected.
9-9
IV
(b) Find a 95% confidence interval on of 102. Round your answer to two decimal places (e.g. 98.76).
Chapter 8 Solutions
Research Methods for the Behavioral Sciences (MindTap Course List)
Ch. 8.1 - Describe, compare, and contrast the defining...Ch. 8.1 - Explain the general advantages and disadvantages...Ch. 8.2 - Define individual differences and explain how...Ch. 8.3 - Identify the three primary techniques for limiting...Ch. 8.4 - Describe how individual differences influence...Ch. 8.4 - Identify the options for reducing or controlling...Ch. 8.5 - Describe how differential attrition and...Ch. 8.6 - Describe how between-subjects designs are used to...Ch. 8 - In addition to the key words, you should also be...Ch. 8 - Identify the basic features of a between-subjects...
Ch. 8 - In a between-subjects design, each individual...Ch. 8 - Briefly explain how a participant characteristic,...Ch. 8 - Briefly explain how random assignment attempts to...Ch. 8 - Explain the advantages and disadvantages of using...Ch. 8 - Briefly explain why large variance within...Ch. 8 - Explain how holding a participant variable such as...Ch. 8 - Explain how holding a participant variable such as...Ch. 8 - Describe some of the problems that can arise when...Ch. 8 - Describe the advantages of a two-group design...Ch. 8 - A researcher has a sample of 30 rats that are all...Ch. 8 - A recent survey at a major corporation found that...
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- Let us suppose we have some article reported on a study of potential sources of injury to equine veterinarians conducted at a university veterinary hospital. Forces on the hand were measured for several common activities that veterinarians engage in when examining or treating horses. We will consider the forces on the hands for two tasks, lifting and using ultrasound. Assume that both sample sizes are 6, the sample mean force for lifting was 6.2 pounds with standard deviation 1.5 pounds, and the sample mean force for using ultrasound was 6.4 pounds with standard deviation 0.3 pounds. Assume that the standard deviations are known. Suppose that you wanted to detect a true difference in mean force of 0.25 pounds on the hands for these two activities. Under the null hypothesis, 40 = 0. What level of type II error would you recommend here? Round your answer to four decimal places (e.g. 98.7654). Use a = 0.05. β = i What sample size would be required? Assume the sample sizes are to be equal.…arrow_forward= Consider the hypothesis test Ho: μ₁ = μ₂ against H₁ μ₁ μ2. Suppose that sample sizes are n₁ = 15 and n₂ = 15, that x1 = 4.7 and X2 = 7.8 and that s² = 4 and s² = 6.26. Assume that o and that the data are drawn from normal distributions. Use απ 0.05. (a) Test the hypothesis and find the P-value. (b) What is the power of the test in part (a) for a true difference in means of 3? (c) Assuming equal sample sizes, what sample size should be used to obtain ẞ = 0.05 if the true difference in means is - 2? Assume that α = 0.05. (a) The null hypothesis is 98.7654). rejected. The P-value is 0.0008 (b) The power is 0.94 . Round your answer to four decimal places (e.g. Round your answer to two decimal places (e.g. 98.76). (c) n₁ = n2 = 1 . Round your answer to the nearest integer.arrow_forwardConsider the hypothesis test Ho: = 622 against H₁: 6 > 62. Suppose that the sample sizes are n₁ = 20 and n₂ = 8, and that = 4.5; s=2.3. Use a = 0.01. (a) Test the hypothesis. Round your answers to two decimal places (e.g. 98.76). The test statistic is fo = i The critical value is f = Conclusion: i the null hypothesis at a = 0.01. (b) Construct the confidence interval on 02/022 which can be used to test the hypothesis: (Round your answer to two decimal places (e.g. 98.76).) iarrow_forward
- 2011 listing by carmax of the ages and prices of various corollas in a ceratin regionarrow_forwardس 11/ أ . اذا كانت 1 + x) = 2 x 3 + 2 x 2 + x) هي متعددة حدود محسوبة باستخدام طريقة الفروقات المنتهية (finite differences) من جدول البيانات التالي للدالة (f(x . احسب قيمة . ( 2 درجة ) xi k=0 k=1 k=2 k=3 0 3 1 2 2 2 3 αarrow_forward1. Differentiate between discrete and continuous random variables, providing examples for each type. 2. Consider a discrete random variable representing the number of patients visiting a clinic each day. The probabilities for the number of visits are as follows: 0 visits: P(0) = 0.2 1 visit: P(1) = 0.3 2 visits: P(2) = 0.5 Using this information, calculate the expected value (mean) of the number of patient visits per day. Show all your workings clearly. Rubric to follow Definition of Random variables ( clearly and accurately differentiate between discrete and continuous random variables with appropriate examples for each) Identification of discrete random variable (correctly identifies "number of patient visits" as a discrete random variable and explains reasoning clearly.) Calculation of probabilities (uses the probabilities correctly in the calculation, showing all steps clearly and logically) Expected value calculation (calculate the expected value (mean)…arrow_forward
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