A sample survey of 54 discount brokers showed that the mean price charged for a trade of 100 shares at $50 per share was $33.77. The survey is conducted annually. With the historical data available, assume a known population standard deviation of $15. a. Using the sample data, what is the margin of error associated with a 95% confidence interval? b. Develop a 95% confidence interval for the mean price charged by discount brokers for a trade of 100 shares at $50 per share.

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

Chapter 8, Problem 44SE

A sample survey of 54 discount brokers showed that the mean price charged for a trade of 100 shares at $50 per share was $33.77. The survey is conducted annually. With the historical data available, assume a known population standard deviation of $15.

a. Using the sample data, what is the margin of error associated with a 95% confidence interval?
b. Develop a 95% confidence interval for the mean price charged by discount brokers for a trade of 100 shares at $50 per share.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

a.

Expert Solution

To determine

Find the margin of error for 95% confidence level.

Answer to Problem 44SE

The margin of error for 95% confidence level is 4.

Explanation of Solution

Calculation:

The given information is that the sample of 54 discount brokers shows the mean price of the trade is $50 for 100 shares is $33.77 and the population standard deviation is $15.

The formula for margin of error is zα2σn.

From the “Table 8.1 value of zα2”, the value of zα2 for 95% is 1.96.

The value of margin of error is

zα2σn=1.961554=1.96×2.04=4

Thus, the value of margin of error is 4.

b.

Expert Solution

To determine

Find the 95% confidence interval for mean price charged by discount brokers for a trade of 100 shares at $50 per share.

Answer to Problem 44SE

The 95% confidence interval for mean price charged by discount brokers for a trade of 100 shares at $50 per share is ($29.77, $37.77).

Explanation of Solution

Calculation:

From part (a), the margin of error is 4.

The mean value for the 54 broker for trade of 100 shares at $50 per share is $33.77.

The value of confidence interval for population mean is

x¯±zα2σn=33.77±4=(33.77−4,33.77+4)=(29.77,37.77)

Thus, the 99% confidence interval for population mean is ($29.77, $37.77).

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Question 4 An article in Quality Progress (May 2011, pp. 42-48) describes the use of factorial experiments to improve a silver powder production process. This product is used in conductive pastes to manufacture a wide variety of products ranging from silicon wafers to elastic membrane switches. Powder density (g/cm²) and surface area (cm/g) are the two critical characteristics of this product. The experiments involved three factors: reaction temperature, ammonium percentage, stirring rate. Each of these factors had two levels, and the design was replicated twice. The design is shown in Table 3. A222222222222233 Stir Rate (RPM) Ammonium (%) Table 3: Silver Powder Experiment from Exercise 13.23 Temperature (°C) Density Surface Area 100 8 14.68 0.40 100 8 15.18 0.43 30 100 8 15.12 0.42 30 100 17.48 0.41 150 7.54 0.69 150 8 6.66 0.67 30 150 8 12.46 0.52 30 150 8 12.62 0.36 100 40 10.95 0.58 100 40 17.68 0.43 30 100 40 12.65 0.57 30 100 40 15.96 0.54 150 40 8.03 0.68 150 40 8.84 0.75 30 150…

- + ++ Table 2: Crack Experiment for Exercise 2 A B C D Treatment Combination (1) Replicate I II 7.037 6.376 14.707 15.219 |++++ 1 བྱ॰༤༠སྦྱོ སྦྱོཋཏྟཱུ a b ab 11.635 12.089 17.273 17.815 с ас 10.403 10.151 4.368 4.098 bc abc 9.360 9.253 13.440 12.923 d 8.561 8.951 ad 16.867 17.052 bd 13.876 13.658 abd 19.824 19.639 cd 11.846 12.337 acd 6.125 5.904 bcd 11.190 10.935 abcd 15.653 15.053 Question 3 Continuation of Exercise 2. One of the variables in the experiment described in Exercise 2, heat treatment method (C), is a categorical variable. Assume that the remaining factors are continuous. (a) Write two regression models for predicting crack length, one for each level of the heat treatment method variable. What differences, if any, do you notice in these two equations? (b) Generate appropriate response surface contour plots for the two regression models in part (a). (c) What set of conditions would you recommend for the factors A, B, and D if you use heat treatment method C = +? (d) Repeat…

Question 2 A nickel-titanium alloy is used to make components for jet turbine aircraft engines. Cracking is a potentially serious problem in the final part because it can lead to nonrecoverable failure. A test is run at the parts producer to determine the effect of four factors on cracks. The four factors are: pouring temperature (A), titanium content (B), heat treatment method (C), amount of grain refiner used (D). Two replicates of a 24 design are run, and the length of crack (in mm x10-2) induced in a sample coupon subjected to a standard test is measured. The data are shown in Table 2. 1 (a) Estimate the factor effects. Which factor effects appear to be large? (b) Conduct an analysis of variance. Do any of the factors affect cracking? Use a = 0.05. (c) Write down a regression model that can be used to predict crack length as a function of the significant main effects and interactions you have identified in part (b). (d) Analyze the residuals from this experiment. (e) Is there an…

Answer 2

Textbook Question

Chapter 8, Problem 44SE

A sample survey of 54 discount brokers showed that the mean price charged for a trade of 100 shares at $50 per share was $33.77. The survey is conducted annually. With the historical data available, assume a known population standard deviation of $15.

a. Using the sample data, what is the margin of error associated with a 95% confidence interval?
b. Develop a 95% confidence interval for the mean price charged by discount brokers for a trade of 100 shares at $50 per share.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

a.

Expert Solution

To determine

Find the margin of error for 95% confidence level.

Answer to Problem 44SE

The margin of error for 95% confidence level is 4.

Explanation of Solution

Calculation:

The given information is that the sample of 54 discount brokers shows the mean price of the trade is $50 for 100 shares is $33.77 and the population standard deviation is $15.

The formula for margin of error is zα2σn.

From the “Table 8.1 value of zα2”, the value of zα2 for 95% is 1.96.

The value of margin of error is

zα2σn=1.961554=1.96×2.04=4

Thus, the value of margin of error is 4.

b.

Expert Solution

To determine

Find the 95% confidence interval for mean price charged by discount brokers for a trade of 100 shares at $50 per share.

Answer to Problem 44SE

The 95% confidence interval for mean price charged by discount brokers for a trade of 100 shares at $50 per share is ($29.77, $37.77).

Explanation of Solution

Calculation:

From part (a), the margin of error is 4.

The mean value for the 54 broker for trade of 100 shares at $50 per share is $33.77.

The value of confidence interval for population mean is

x¯±zα2σn=33.77±4=(33.77−4,33.77+4)=(29.77,37.77)

Thus, the 99% confidence interval for population mean is ($29.77, $37.77).

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 8, Problem 44SE

A sample survey of 54 discount brokers showed that the mean price charged for a trade of 100 shares at $50 per share was $33.77. The survey is conducted annually. With the historical data available, assume a known population standard deviation of $15.

a. Using the sample data, what is the margin of error associated with a 95% confidence interval?
b. Develop a 95% confidence interval for the mean price charged by discount brokers for a trade of 100 shares at $50 per share.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

a.

Expert Solution

To determine

Find the margin of error for 95% confidence level.

Answer to Problem 44SE

The margin of error for 95% confidence level is 4.

Explanation of Solution

Calculation:

The given information is that the sample of 54 discount brokers shows the mean price of the trade is $50 for 100 shares is $33.77 and the population standard deviation is $15.

The formula for margin of error is zα2σn.

From the “Table 8.1 value of zα2”, the value of zα2 for 95% is 1.96.

The value of margin of error is

zα2σn=1.961554=1.96×2.04=4

Thus, the value of margin of error is 4.

b.

Expert Solution

To determine

Find the 95% confidence interval for mean price charged by discount brokers for a trade of 100 shares at $50 per share.

Answer to Problem 44SE

The 95% confidence interval for mean price charged by discount brokers for a trade of 100 shares at $50 per share is ($29.77, $37.77).

Explanation of Solution

Calculation:

From part (a), the margin of error is 4.

The mean value for the 54 broker for trade of 100 shares at $50 per share is $33.77.

The value of confidence interval for population mean is

x¯±zα2σn=33.77±4=(33.77−4,33.77+4)=(29.77,37.77)

Thus, the 99% confidence interval for population mean is ($29.77, $37.77).

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 8, Problem 44SE

A sample survey of 54 discount brokers showed that the mean price charged for a trade of 100 shares at $50 per share was $33.77. The survey is conducted annually. With the historical data available, assume a known population standard deviation of $15.

a. Using the sample data, what is the margin of error associated with a 95% confidence interval?
b. Develop a 95% confidence interval for the mean price charged by discount brokers for a trade of 100 shares at $50 per share.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

a.

Expert Solution

To determine

Find the margin of error for 95% confidence level.

Answer to Problem 44SE

The margin of error for 95% confidence level is 4.

Explanation of Solution

Calculation:

The given information is that the sample of 54 discount brokers shows the mean price of the trade is $50 for 100 shares is $33.77 and the population standard deviation is $15.

The formula for margin of error is zα2σn.

From the “Table 8.1 value of zα2”, the value of zα2 for 95% is 1.96.

The value of margin of error is

zα2σn=1.961554=1.96×2.04=4

Thus, the value of margin of error is 4.

b.

Expert Solution

To determine

Find the 95% confidence interval for mean price charged by discount brokers for a trade of 100 shares at $50 per share.

Answer to Problem 44SE

The 95% confidence interval for mean price charged by discount brokers for a trade of 100 shares at $50 per share is ($29.77, $37.77).

Explanation of Solution

Calculation:

From part (a), the margin of error is 4.

The mean value for the 54 broker for trade of 100 shares at $50 per share is $33.77.

The value of confidence interval for population mean is

x¯±zα2σn=33.77±4=(33.77−4,33.77+4)=(29.77,37.77)

Thus, the 99% confidence interval for population mean is ($29.77, $37.77).

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

a.

Expert Solution

To determine

Find the margin of error for 95% confidence level.

Answer to Problem 44SE

The margin of error for 95% confidence level is 4.

Explanation of Solution

Calculation:

The given information is that the sample of 54 discount brokers shows the mean price of the trade is $50 for 100 shares is $33.77 and the population standard deviation is $15.

The formula for margin of error is zα2σn.

From the “Table 8.1 value of zα2”, the value of zα2 for 95% is 1.96.

The value of margin of error is

zα2σn=1.961554=1.96×2.04=4

Thus, the value of margin of error is 4.

b.

Expert Solution

To determine

Find the 95% confidence interval for mean price charged by discount brokers for a trade of 100 shares at $50 per share.

Answer to Problem 44SE

The 95% confidence interval for mean price charged by discount brokers for a trade of 100 shares at $50 per share is ($29.77, $37.77).

Explanation of Solution

Calculation:

From part (a), the margin of error is 4.

The mean value for the 54 broker for trade of 100 shares at $50 per share is $33.77.

The value of confidence interval for population mean is

x¯±zα2σn=33.77±4=(33.77−4,33.77+4)=(29.77,37.77)

Thus, the 99% confidence interval for population mean is ($29.77, $37.77).

Answer 8

a.

Expert Solution

To determine

Find the margin of error for 95% confidence level.

Answer to Problem 44SE

The margin of error for 95% confidence level is 4.

Explanation of Solution

Calculation:

The given information is that the sample of 54 discount brokers shows the mean price of the trade is $50 for 100 shares is $33.77 and the population standard deviation is $15.

The formula for margin of error is zα2σn.

From the “Table 8.1 value of zα2”, the value of zα2 for 95% is 1.96.

The value of margin of error is

zα2σn=1.961554=1.96×2.04=4

Thus, the value of margin of error is 4.

Answer 9

a.

Expert Solution

Answer 10

a.

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

Find the margin of error for 95% confidence level.

Answer 13

Answer to Problem 44SE

The margin of error for 95% confidence level is 4.

Answer 14

Explanation of Solution

Calculation:

The given information is that the sample of 54 discount brokers shows the mean price of the trade is $50 for 100 shares is $33.77 and the population standard deviation is $15.

The formula for margin of error is zα2σn.

From the “Table 8.1 value of zα2”, the value of zα2 for 95% is 1.96.

The value of margin of error is

zα2σn=1.961554=1.96×2.04=4

Thus, the value of margin of error is 4.

Answer 15

b.

Expert Solution

To determine

Find the 95% confidence interval for mean price charged by discount brokers for a trade of 100 shares at $50 per share.

Answer to Problem 44SE

The 95% confidence interval for mean price charged by discount brokers for a trade of 100 shares at $50 per share is ($29.77, $37.77).

Explanation of Solution

Calculation:

From part (a), the margin of error is 4.

The mean value for the 54 broker for trade of 100 shares at $50 per share is $33.77.

The value of confidence interval for population mean is

x¯±zα2σn=33.77±4=(33.77−4,33.77+4)=(29.77,37.77)

Thus, the 99% confidence interval for population mean is ($29.77, $37.77).

Answer 16

b.

Expert Solution

Answer 17

b.

Expert Solution

Answer 18

Expert Solution

Answer 19

To determine

Find the 95% confidence interval for mean price charged by discount brokers for a trade of 100 shares at $50 per share.

Answer 20

Answer to Problem 44SE

The 95% confidence interval for mean price charged by discount brokers for a trade of 100 shares at $50 per share is ($29.77, $37.77).

Answer 21

Explanation of Solution

Calculation:

From part (a), the margin of error is 4.

The mean value for the 54 broker for trade of 100 shares at $50 per share is $33.77.

The value of confidence interval for population mean is

x¯±zα2σn=33.77±4=(33.77−4,33.77+4)=(29.77,37.77)

Thus, the 99% confidence interval for population mean is ($29.77, $37.77).

Answer 22

Ch. 8.1 - A simple random sample of 40 items resulted in a...Ch. 8.1 - A simple random sample of 50 items from a...Ch. 8.1 - A simple random sample of 60 items resulted in a...Ch. 8.1 - A 95% confidence interval for a population mean...Ch. 8.1 - Data were collected on the amount spent by 64...Ch. 8.1 - In an attempt to assess total daily travel taxes...Ch. 8.1 - The average annual cost of the first year of...Ch. 8.1 - Studies show that massage therapy has a variety of...Ch. 8.1 - The mean cost to repair the smoke and fire damage...Ch. 8.1 - Costs are rising for all kinds of medical care....

Videos

Answer to Problem 44SE

Explanation of Solution

Answer to Problem 44SE

Explanation of Solution

Want to see more full solutions like this?

Chapter 8 Solutions