Explanation Given data: The mass of the seesaw is 30 kg . The length of the seesaw is 3 m . The mass of first person is 60 kg . The mass of second person is 75 kg . Formula used: The expression for torque equilibrium condition is: ∑ τ = 0 Here, τ is the torque about any point. Explanation: Consider the center of mass of the seesaw to be at a distance of x from the end of the 60 kg person. Apply torque equilibrium condition about fulcrum. ∑ τ = 0 ( 60 kg ) ( g ) ( 1.5 m ) + ( 30 kg ) ( g ) ( 1.5 m − x ) − ( 75 kg ) ( g ) ( 1

2nd Edition

ISBN: 9780134601823

Author: ETKINA, Eugenia, Planinšič, G. (gorazd), Van Heuvelen, Alan

Publisher: Pearson,

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Chapter 8, Problem 28P

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The center of mass of a seesaw having mass 30 kg and length 3 m if it is balanced when a 60 kg person sits on one end and a 75 kg person sits on the other end.

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Chapter 8, Problem 27P

Chapter 8, Problem 29P

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The center of mass of a seesaw having mass 30 kg and length 3 m if it is balanced when a 60 kg person sits on one end and a 75 kg person sits on the other end.

Solution Summary: The author explains how to determine the center of mass of a seesaw with mass 30kg and length 3, and the torque equilibrium condition about fulcrum.

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The center of mass of a seesaw having mass 30 kg and length 3 m if it is balanced when a 60 kg person sits on one end and a 75 kg person sits on the other end.

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Chapter 8 Solutions