Chapter 8, Problem 25E

Interpretation Introduction

(a)

Interpretation:

The density of argon $\text{Ar}$ at STP is to be calculated.

Concept introduction:

The density of a substance is defined as the ratio of mass and volume. It is a characteristic property of a substance that relates the mass of that substance with the space it occupies. The SI unit of density is $\text{kg}/{\text{m}}^3$.

Answer to Problem 25E

The density of argon $\text{Ar}$ at STP is $1.78\text{g}/\text{L}$.

Explanation of Solution

The density of argon $\text{Ar}$ at STP is calculated by the formula shown below.

$\text{Density}=M_{\text{Ar}}\times \frac{\text{1}\text{mole}}{\text{22}\text{.4}\text{L}}$ …(1)

Where,

• $M_{\text{Ar}}$ is molar mass of argon.

Molar mass of the argon $\left(M_{\text{Ar}}\right)$ is $\text{39}\text{.948}\text{g}/\text{mol}$.

Substitute the value of $M_{\text{Ar}}$ in equation (1).

$\begin{array}{rll}\text{Density}& =& M_{\text{Ar}}\times \frac{\text{1}\text{mole}}{\text{22}\text{.4}\text{L}}\\ & =& \text{39}\text{.948}\text{g}/\text{mol}\times \frac{\text{1}\text{mole}}{\text{22}\text{.4}\text{L}}\\ & =& \frac{\text{39}\text{.948}}{\text{22}\text{.4}}\text{g}/\text{L}\\ & =& 1.78\text{g}/\text{L}\end{array}$

Conclusion

The density of argon $\text{Ar}$ at STP is $1.78\text{g}/\text{L}$.

Interpretation Introduction

(b)

Interpretation:

The density of fluorine, ${\text{F}}_{\text{2}}$ at STP is to be calculated.

Concept introduction:

The density of a substance is defined as the ratio of mass and volume. It is a characteristic property of a substance that relates the mass of that substance with the space it occupies. The SI unit of density is $\text{kg}/{\text{m}}^3$.

Answer to Problem 25E

The density of fluorine, ${\text{F}}_{\text{2}}$ at STP is $1.70\text{g}/\text{L}$.

Explanation of Solution

The density of fluorine, ${\text{F}}_{\text{2}}$ at STP is calculated by the formula shown below.

$\text{Density}=M_{{\text{F}}_2}\times \frac{\text{1}\text{mole}}{\text{22}\text{.4}\text{L}}$ …(1)

Where,

• $M_{{\text{F}}_2}$ is molar mass of fluorine.

Molar mass of the fluorine $\left(M_{{\text{F}}_2}\right)$ is $\text{37}\text{.9968}\text{g}/\text{mol}$.

Substitute the value of $M_{{\text{F}}_2}$ in equation (1).

$\begin{array}{rll}\text{Density}& =& M_{{\text{F}}_2}\times \frac{\text{1}\text{mole}}{\text{22}\text{.4}\text{L}}\\ & =& \text{37}\text{.9968}\text{g}/\text{mol}\times \frac{\text{1}\text{mole}}{\text{22}\text{.4}\text{L}}\\ & =& \frac{\text{37}\text{.9968}}{\text{22}\text{.4}}\text{g}/\text{L}\\ & =& 1.70\text{g}/\text{L}\end{array}$

Conclusion

The density of fluorine, ${\text{F}}_{\text{2}}$ at STP is $1.70\text{g}/\text{L}$.

Interpretation Introduction

(c)

Interpretation:

The density of methane, ${\text{CH}}_{\text{4}}$ at STP is to be calculated.

Concept introduction:

The density of a substance is defined as the ratio of mass and volume. It is a characteristic property of a substance that relates the mass of that substance with the space it occupies. The SI unit of density is $\text{kg}/{\text{m}}^3$.

Answer to Problem 25E

The density of methane, ${\text{CH}}_{\text{4}}$ at STP is $0.716\text{g}/\text{L}$.

Explanation of Solution

The density of methane ${\text{CH}}_{\text{4}}$ at STP is calculated by the formula shown below.

$\text{Density}=M_{{\text{CH}}_{\text{4}}}\times \frac{\text{1}\text{mole}}{\text{22}\text{.4}\text{L}}$ …(1)

Where,

• $M_{{\text{CH}}_{\text{4}}}$ is molar mass of methane.

Molar mass of the methane $\left(M_{{\text{CH}}_{\text{4}}}\right)$ is $\text{16}\text{.04}\text{g}/\text{mol}$.

Substitute the value of $M_{{\text{CH}}_{\text{4}}}$ in equation (1).

$\begin{array}{rll}\text{Density}& =& M_{{\text{CH}}_{\text{4}}}\times \frac{\text{1}\text{mole}}{\text{22}\text{.4}\text{L}}\\ & =& \text{16}\text{.04}\text{g}/\text{mol}\times \frac{\text{1}\text{mole}}{\text{22}\text{.4}\text{L}}\\ & =& \frac{\text{16}\text{.04}}{\text{22}\text{.4}}\text{g}/\text{L}\\ & =& 0.716\text{g}/\text{L}\end{array}$

Conclusion

The density of methane, ${\text{CH}}_{\text{4}}$ at STP is $0.716\text{g}/\text{L}$.

Interpretation Introduction

(d)

Interpretation:

The density of propane, ${\text{C}}_{\text{3}}{\text{H}}_{\text{8}}$ at STP is to be calculated.

Concept introduction:

The density of a substance is defined as the ratio of mass and volume. It is a characteristic property of a substance that relates the mass of that substance with the space it occupies. The SI unit of density is $\text{kg}/{\text{m}}^3$.

Answer to Problem 25E

The density of propane, ${\text{C}}_{\text{3}}{\text{H}}_{\text{8}}$ at STP is $1.97\text{g}/\text{L}$.

Explanation of Solution

The density of propane ${\text{C}}_{\text{3}}{\text{H}}_{\text{8}}$ at STP is calculated by the formula shown below.

$\text{Density}=M_{{\text{C}}_{\text{3}}{\text{H}}_{\text{8}}}\times \frac{\text{1}\text{mole}}{\text{22}\text{.4}\text{L}}$ …(1)

Where,

• $M_{{\text{C}}_{\text{3}}{\text{H}}_{\text{8}}}$ is molar mass of propane.

Molar mass of the propane $\left(M_{{\text{C}}_{\text{3}}{\text{H}}_{\text{8}}}\right)$ is $\text{44}\text{.1}\text{g}/\text{mol}$.

Substitute the value of $M_{{\text{C}}_{\text{3}}{\text{H}}_{\text{8}}}$ in equation (1).

$\begin{array}{rll}\text{Density}& =& M_{{\text{C}}_{\text{3}}{\text{H}}_{\text{8}}}\times \frac{\text{1}\text{mole}}{\text{22}\text{.4}\text{L}}\\ & =& \text{44}\text{.1}\text{g}/\text{mol}\times \frac{\text{1}\text{mole}}{\text{22}\text{.4}\text{L}}\\ & =& \frac{\text{44}\text{.1}}{\text{22}\text{.4}}\text{g}/\text{L}\\ & =& 1.97\text{g}/\text{L}\end{array}$

Conclusion

The density of propane, ${\text{C}}_{\text{3}}{\text{H}}_{\text{8}}$ at STP is $1.97\text{g}/\text{L}$.