Explanation Given data: Refer to the Figure P8.20 in the textbook for the position of the board along with the box on the table. Mass of the box ( m Box ) is 2.0 kg. Mass of the board ( m Board ) is 6.0 kg. Formula used: Write the expression for static equilibrium condition of the torque as follows. ∑ τ = 0 (1) Here, ∑ τ is the sum of the torques acting on any object. Write the expression for torque in terms of force and distance as follows. τ = F d (2) Here, F is the force, and d is the distance. Write the expression for force due to the weight of the object as follows. w = m g (3) Here, m is the mass of the object, and g is the acceleration due to gravity, which is 9.8 m s 2 . Explanation: From the given Figure, the length of the board is 50 cm. The board to be in stable state, the center of gravity of the board must be at its center. Therefore, the center of gravity of the board lies at 25 cm from its any end. From the analysis, the center of the gravity of the board lies at 5.0 cm from the end of the table. The given system to be in the stable state, the net torque must be zero. The clockwise torque in the system is due to the box and the counterclockwise torque in the system is due to the board. Compute the sum of the torque by modifying the expression in equation (1) as follows. τ counter-clock + ( − τ clock ) = 0 (4) Here, τ counter-clock is the counterclockwise torque in the system, which is due to the board, and τ clock is the clockwise torque in the system, which is due to the box. Write the expression for counterclockwise torque in the system by using the equation (2) and given figure as follows. τ counter-clock = w Board L end of table-center of gravity (5) Here, w Board is the force due to weight of the board, and L end of table-center of gravity is the distance between end of the table to the center of gravity of the board, which is 5.0 cm. Calculation of force due to weight of the board: Modify the expression in equation (3) to find the force due to weight of the board as follows. w Board = m Board g Substitute 6.0 kg for m Board , and 9.8 m s 2 for g , w Board = ( 6.0 kg ) ( 9.8 m s 2 ) = 58.8 kg ⋅ m s 2 = 58.8 N { ∵ 1 kg ⋅ m s 2 = 1 N } Calculation of counterclockwise torque in the system: Substitute 58.8 N for w Board , 5.0 cm for L end of table-center of gravity in equation (5), τ counter-clock = ( 58

4th Edition

ISBN: 9780137574728

Author: Knight

Publisher: PEARSON

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Question

Chapter 8, Problem 20P

To determine

To find: The distance from the center of the board to the end of the table before the board begins to tilt.

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Chapter 8, Problem 19P

Chapter 8, Problem 21P

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Chapter 8 Solutions

COLLEGE PHYSICS:STRATEGIC APPR.AP ED.

Ch. 8 - Prob. 1CQ Ch. 8 - Could a ladder on a level floor lean against a...Ch. 8 - Prob. 3CQ Ch. 8 - Prob. 4CQ Ch. 8 - Prob. 5CQ Ch. 8 - Prob. 6CQ Ch. 8 - Prob. 7CQ Ch. 8 - A spring exerts a 10 N force after being stretched...Ch. 8 - Prob. 9CQ Ch. 8 - A typical mattress has a network of springs that...

Ch. 8 - Take a spring and cut it in half to make two...Ch. 8 - A wire is stretched right to its breaking point by...Ch. 8 - Prob. 13CQ Ch. 8 - Prob. 14CQ Ch. 8 - Steel nails are rigid and unbending. Steel wool is...Ch. 8 - Two children hold opposite ends of a lightweight,...Ch. 8 - Prob. 19MCQ Ch. 8 - Prob. 20MCQ Ch. 8 - Prob. 21MCQ Ch. 8 - Prob. 22MCQ Ch. 8 - Prob. 23MCQ Ch. 8 - Prob. 24MCQ Ch. 8 - Prob. 25MCQ Ch. 8 - Prob. 26MCQ Ch. 8 - You have a heavy piece of equipment hanging from a...Ch. 8 - Prob. 1P Ch. 8 - Prob. 2P Ch. 8 - Prob. 3P Ch. 8 - Prob. 4P Ch. 8 - Youre carrying a 3.6-m-long, 25 kg pole to a...Ch. 8 - Prob. 6P Ch. 8 - Prob. 7P Ch. 8 - Prob. 9P Ch. 8 - Prob. 11P Ch. 8 - Prob. 13P Ch. 8 - Prob. 14P Ch. 8 - Prob. 15P Ch. 8 - The stability of a vehicle is often rated by the...Ch. 8 - Prob. 18P Ch. 8 - A car manufacturer claims that you can drive its...Ch. 8 - Prob. 20P Ch. 8 - An orthodontic spring, connected between the upper...Ch. 8 - Prob. 22P Ch. 8 - Experiments using optical tweezers measure the...Ch. 8 - Prob. 24P Ch. 8 - One end of a 10-cm-long spring is attached to the...Ch. 8 - Prob. 26P Ch. 8 - A spring has an unstretched length of 10 cm. It...Ch. 8 - A spring stretches 5.0 cm when a 0.20 kg block is...Ch. 8 - You need to make a spring scale to measure the...Ch. 8 - Prob. 30P Ch. 8 - A force stretches a wire by 1.0 mm. a. A second...Ch. 8 - Prob. 32P Ch. 8 - What hanging mass will stretch a 2.0-m-long,...Ch. 8 - An 80-cm-long, 1.0-mm-diameter steel guitar string...Ch. 8 - A mineshaft has an ore elevator hung from a single...Ch. 8 - The normal force of the ground on the foot can...Ch. 8 - A three-legged wooden bar stool made out of solid...Ch. 8 - Prob. 38P Ch. 8 - Prob. 39P Ch. 8 - Prob. 40P Ch. 8 - A glass optical fiber in a communications system...Ch. 8 - The Achilles tendon connects the muscles in your...Ch. 8 - Prob. 44P Ch. 8 - Prob. 47P Ch. 8 - Prob. 48P Ch. 8 - Prob. 49P Ch. 8 - Prob. 51GP Ch. 8 - Prob. 52GP Ch. 8 - Prob. 53GP Ch. 8 - Prob. 55GP Ch. 8 - Two identical, side-by-side springs with spring...Ch. 8 - Prob. 57GP Ch. 8 - Prob. 58GP Ch. 8 - Prob. 59GP Ch. 8 - A 25 kg child bounces on a pogo stick. The pogo...Ch. 8 - Prob. 61GP Ch. 8 - In the hammer throw, an athlete spins a heavy mass...Ch. 8 - There is a disk of cartilage between each pair of...Ch. 8 - Orb spiders make silk with a typical diameter of...Ch. 8 - Larger animals have sturdier bones than smaller...Ch. 8 - Prob. 67GP Ch. 8 - Prob. 68GP Ch. 8 - Prob. 69MSPP Ch. 8 - Prob. 70MSPP Ch. 8 - Prob. 71MSPP Ch. 8 - Prob. 72MSPP

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