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Concept explainers
Explanation of Solution
Cryptography and cryptanalysis:
- Cryptography is a technique to convert the plain text to cyber text to protect the data from hackers.
- Cryptanalysis is the art of study to decrypt the cyber text without knowing the key.
Cryptography:
Cryptography is a technique to encrypt and decrypt the data using keys. The user can send or receive data across insecure networks using the cryptography. This system may use same or different keys for sender and receiver.
This technique can be categorized into two types:
- Symmetric key cryptography.
- Asymmetric key cryptography.
Symmetric key cryptography:
This cryptography uses the same secret key for sender and receiver to encrypt and decrypt the message.
Asymmetric key cryptography:
The sender and receiver uses different keys for encryption and decryption. It is otherwise known as public key cryptography.
Cryptanalysis:
Cryptanalysis is a study of retrieving plain text from a cipher text without knowing the encryption key and
- Design the security systems to prevent the vulnerabilities.
- Evaluate and analyze the security systems and algorithm for cryptography.
- Protecting critical data from being modified and deleted.
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Chapter 8 Solutions
Principles of Information Security
- #include int main (void) { int i, *p, count } p = &count; = 10%; for (i = 5; i >= 0; i--) { count++; (*p) ++; } printf("count return 0; = %d, Have a wonderful day.\n", count); 1. [20 pts] What is the output of the program? Please explain why. 2. [15 pts] What is the gdb command to set a breakpoint in line 6 (p = &count;)? 3. [15 pts] Explain in your own words how the [break. need to use such command? ... if expr] command works. When might youarrow_forwardPlease run and debug the following program and answer the questions.arrow_forward(OnlineGDB) #include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} Assume the following codes are added between line 36 (}) and line 38 (return 0;) v0>0 ? ++v1, ++v2 : --v3; Please give the values of v0, v1, v2, v3, and v4 after this line and explain the reason. You can test the program to verify your answer if you like.arrow_forward
- #include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} Output: Exercise 1:====================Go Kean! Have a great semester! Go Kean! Please only modify the initial value of v0, v1, v2, v3 and v4 to get the following output. Youneed to show your program output (in the screenshot) and submit the code that youmodified.Exercise 1:====================Hello OctoberKeanHello Computer Science!arrow_forward(OnlineGDB) 1. Please read and run the following code and answer the questions.#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} What is the output of the program? Please explain why.arrow_forward1.[30 pts] Answer the following questions: a. [10 pts] Write a Boolean equation in sum-of-products canonical form for the truth table shown below: A B C Y 0 0 0 1 0 0 1 0 0 1 0 0 0 1 1 0 1 0 0 1 1 0 1 0 1 1 0 1 1 1 1 0 a. [10 pts] Minimize the Boolean equation you obtained in (a). b. [10 pts] Implement, using Logisim, the simplified logic circuit. Include an image of the circuitarrow_forward
- In the past, encryption and decryption were mostly done by substitution and permutation of letters in a text message. study those classic cryptographic schemes Then, develop an automatic cipher using Javascript The cipher should be able to perform the following tasks: generate keys encrypt a given plaintext message with a key selected from the list of keys generated decrypt a given ciphertext message with a known cipher keyarrow_forwardList reasons why teachers should and shouldn’t be replaced by computers? State your response in a descriptive context. Provide five references from the with internet with your answers.arrow_forwardThe attached picture shows the RTCAPI memory mapped register which has the address 0x180. 1) Program the MCU's registers so that a) SIRC is the clock source b) the clock is divided by 16K c) the clock is enabled d) load is enabledarrow_forward
- What is the ALU result if the 4-bit ALU Control signal is 0100? What happens if the ALU Control signal is 0101?arrow_forwardIn the past, encryption and decryption were mostly done by substitution and permutation of letters in a text message. study those classic cryptographic schemes Then, develop an automatic cipher using a programming language of your choice. The cipher should be able to perform the following tasks: generate keys encrypt a given plaintext message with a key selected from the list of keys generated decrypt a given ciphertext message with a known cipher keyarrow_forwardCase Study Instructions: Offshore Wind Energy in the North Sea For this case study, students will analyze the institutional challenges and social rules surrounding offshore wind energy development in the Dutch North Sea, as explored in the case study from the textbook (pages 44-46). Additional resources in this week’s learning module will provide further perspectives on the impact of wind energy on different stakeholders. Students should refer to the syllabus for specific guidelines regarding length, format, and content requirements. Reflection Questions to Consider: What are the key institutional challenges in implementing offshore wind energy in the North Sea? How do formal and informal social rules shape the use of this shared space? What conflicts arise between different stakeholders (e.g., fishermen, naval transport, military, and wind energy developers)? How can policymakers balance economic, environmental, and social considerations when allocating space for wind energy?…arrow_forward
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