
EBK ESSENTIALS OF MIS,
13th Edition
ISBN: 8220106778494
Author: LAUDON
Publisher: PEARSON
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Question
Chapter 8, Problem 1IQ
Program Plan Intro
System vulnerability:
- When huge data amounts are been kept in electronic form, it becomes susceptible to many threats.
- The
information systems in many locations are been interconnected through communication networks. - The unauthorized access can occur at many access points in network and is not limited to single location.
- The data flowing over networks could be accessed; valuable information could be stolen while transmission or data could be altered without authorization.
- The denial-of-service attacks are launched by intruders to disrupt website operations.
- Internets are vulnerable than internal networks as it is open to everyone.
Expert Solution & Answer

Explanation of Solution
Authentication and Identity management:
- The Identity management (ID management) denotes an organizational process to identify, authenticate and authorize individuals to have access to information.
- The information includes applications, networks with user rights and other company information.
- It includes authenticating of users and to determine whether they are allowed access to particular system.
- It determines whether a user has access to systems but also sets access level and permission level for users.
- It includes control over process of authorizing system or network permissions for existing users.
- It includes off boarding of users who are no longer authorized for access to organization system.
- Authentication denotes a process of recognizing identity of a user.
- It denotes a method to associate an inbound request with identifying credential set.
- The credentials delivered are compared with values of file in a
database of authorized information of user within authentication server. - It has two different phases, identification as well as actual authentication.
- The identification phase would provide a user identity to security system.
- This identity is been provided in form of a user ID.
Working with IT security systems:
- Yes, have worked with IT security systems and identity management.
- The job nature was to ensure proper working of systems in an organization.
Nature of work with software:
- The job nature was to ensure proper working of systems in an organization.
- The proper updating of virus protection software and system updates was a responsibility.
- The scheduled back up schemes is to be controlled and managed.
- To ensure proper working of software present in organization.
- To ensure credentials provided by user matches with that of access file database.
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Students have asked these similar questions
I need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place.
My code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2 * pi * f; % Angular frequency
% Parameters for the filters - let's adjust these to get more reasonable cutoffs
R = 1e3; % Resistance in ohms (1 kΩ)
C = 1e-6; % Capacitance in farads (1 μF)
% For bandpass, we need appropriate L value for desired cutoffs
L = 0.1; % Inductance in henries - adjusted for better bandpass response
% Calculate cutoff frequencies first to verify they're in desired range
f_cutoff_RC = 1 / (2 * pi * R * C);
f_resonance = 1 / (2 * pi * sqrt(L * C));
Q_factor = (1/R) * sqrt(L/C);
f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor));
f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));
% Transfer functions
% Low-pass filter (RC)
H_low = 1 ./ (1 + 1i * w *…
My code is experincing minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place.
My code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2 * pi * f; % Angular frequency
% Parameters for the filters - let's adjust these to get more reasonable cutoffs
R = 1e3; % Resistance in ohms (1 kΩ)
C = 1e-6; % Capacitance in farads (1 μF)
% For bandpass, we need appropriate L value for desired cutoffs
L = 0.1; % Inductance in henries - adjusted for better bandpass response
% Calculate cutoff frequencies first to verify they're in desired range
f_cutoff_RC = 1 / (2 * pi * R * C);
f_resonance = 1 / (2 * pi * sqrt(L * C));
Q_factor = (1/R) * sqrt(L/C);
f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor));
f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));
% Transfer functions
% Low-pass filter (RC)
H_low = 1 ./ (1 + 1i * w *…
I would like to know the main features about the following three concepts:
1. Default forwarded
2. WINS Server
3. IP Security (IPSec).
Chapter 8 Solutions
EBK ESSENTIALS OF MIS,
Ch. 8.1 - Prob. 1CQ1Ch. 8.1 - Prob. 2CQ1Ch. 8.1 - Prob. 3CQ1Ch. 8.1 - Prob. 4CQ1Ch. 8.4 - Prob. 1CQ2Ch. 8.4 - Prob. 2CQ2Ch. 8.4 - Prob. 3CQ2Ch. 8.4 - Prob. 4CQ2Ch. 8 - Prob. 1IQCh. 8 - Prob. 2IQ
Ch. 8 - Prob. 3IQCh. 8 - Prob. 4IQCh. 8 - Prob. 5IQCh. 8 - Prob. 1RQCh. 8 - Prob. 2RQCh. 8 - Prob. 3RQCh. 8 - Prob. 4RQCh. 8 - Prob. 5DQCh. 8 - Prob. 6DQCh. 8 - Prob. 7DQCh. 8 - Prob. 8HMPCh. 8 - Prob. 9HMPCh. 8 - Prob. 11CTPCh. 8 - Prob. 12CTPCh. 8 - Prob. 13CSQCh. 8 - Prob. 14CSQCh. 8 - Prob. 15CSQCh. 8 - Prob. 16CSQCh. 8 - Prob. 17MLMCh. 8 - Prob. 18MLM
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