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(a)
Interpretation:
The given word equation has to be converted into formulas equation. The equation has to be balanced. The physical state of the substances has to be indicated with proper symbols.
The given word equation is “When heated, solid magnesium carbonate decomposes into solid magnesium oxide and carbon dioxide gas”.
(b)
Interpretation:
The given word equation has to be converted into formulas equation. The equation has to be balanced. The physical state of the substances has to be indicated with proper symbols.
The given word equation is “solid calcium hydroxide reacts with aqueous chloric acid to form a solution of calcium chlorate along with liquid water”.
(c)
Interpretation:
The given word equation has to be converted into formulas equation. The equation has to be balanced. The physical state of the substances has to be indicated with proper symbols.
The given word equation is “Solutions of iron (III) sulfate and sodium hydroxide are mixed together, forming solid iron (III) hydroxide and a solution of sodium sulfate”.
(d)
Interpretation:
The given word equation has to be converted into formulas equation. The equation has to be balanced. The physical state of the substances has to be indicated with proper symbols.
The given word equation is “Zinc metal is placed into a solution of acetic acid forming aqueous zinc sulfate and hydrogen gas”.
(e)
Interpretation:
The given word equation has to be converted into formulas equation. The equation has to be balanced. The physical state of the substances has to be indicated with proper symbols.
The given word equation is “Gaseous sulfur trioxide reacts with liquid water to form a solution of sulfuric acid”.
(f)
Interpretation:
The given word equation has to be converted into formulas equation. The equation has to be balanced. The physical state of the substances has to be indicated with proper symbols.
The given word equation is “Solutions of sodium carbonate and cobalt (II) chloride react to form solid cobalt (II) carbonate and a solution of sodium chloride”.
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Chapter 8 Solutions
FOUND.OF COLLEGE CHEMISTRY
- 4. Read paragraph 4.15 from your textbook, use your calculated lattice energy values for CuO, CuCO3 and Cu(OH)2 an explain thermal decomposition reaction of malachite: Cu2CO3(OH)2 →2CuO + H2O + CO2 (3 points)arrow_forwardPlease sirrr soollveee these parts pleaseeee and thank youuuuuarrow_forwardIII O Organic Chemistry Using wedges and dashes in skeletal structures Draw a skeletal ("line") structure for each of the molecules below. Be sure your structures show the important difference between the molecules. key O O O O O CHON Cl jiii iiiiiiii You can drag the slider to rotate the molecules. Explanation Check Click and drag to start drawing a structure. Q Search X G ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Use F 3 W C 3/5arrow_forward
- 3. Use Kapustinskii's equation and data from Table 4.10 in your textbook to calculate lattice energies of Cu(OH)2 and CuCO3 (4 points)arrow_forward2. Copper (II) oxide crystalizes in monoclinic unit cell (included below; blue spheres 2+ represent Cu²+, red - O²-). Use Kapustinski's equation (4.5) to calculate lattice energy for CuO. You will need some data from Resource section of your textbook (p.901). (4 points) CuOarrow_forwardWhat is the IUPAC name of the following compound? OH (2S, 4R)-4-chloropentan-2-ol O (2R, 4R)-4-chloropentan-2-ol O (2R, 4S)-4-chloropentan-2-ol O(2S, 4S)-4-chloropentan-2-olarrow_forward
- Use the reaction coordinate diagram to answer the below questions. Type your answers into the answer box for each question. (Watch your spelling) Energy A B C D Reaction coordinate E A) Is the reaction step going from D to F endothermic or exothermic? A F G B) Does point D represent a reactant, product, intermediate or transition state? A/ C) Which step (step 1 or step 2) is the rate determining step? Aarrow_forward1. Using radii from Resource section 1 (p.901) and Born-Lande equation, calculate the lattice energy for PbS, which crystallizes in the NaCl structure. Then, use the Born-Haber cycle to obtain the value of lattice energy for PbS. You will need the following data following data: AH Pb(g) = 196 kJ/mol; AHƒ PbS = −98 kJ/mol; electron affinities for S(g)→S¯(g) is -201 kJ/mol; S¯(g) (g) is 640kJ/mol. Ionization energies for Pb are listed in Resource section 2, p.903. Remember that enthalpies of formation are calculated beginning with the elements in their standard states (S8 for sulfur). The formation of S2, AHF: S2 (g) = 535 kJ/mol. Compare the two values, and explain the difference. (8 points)arrow_forwardIn the answer box, type the number of maximum stereoisomers possible for the following compound. A H H COH OH = H C Br H.C OH CHarrow_forward
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