itamin B 12 , cyancobalamin, is essential for human nutrition. Its molecular formula is C 63 H 88 CoN 14 O 14 P . A lack of this vita min in the diet can lead to anemia. Cyanocohalamin is the form of the vitamin found in vitamin supplements. l type='a'> What is the molar mass of cyanocobalamin to two decimal places? How many moles of cyanocohalamin molecules are present in 250 mg of cyanocobalamin? What is the mass of 0.60 mole of cyanocobalamin? How many atoms of hydrogen are in 1 .0 mole of cyanocobalamin? What is the mass of 1 .0 × 10 7 molecules of cyanocobalamin? What is the mass (in grams) of one molecule of cyanocobalamin?

Question

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Answer 1

Textbook Question

Chapter 8, Problem 128CP

itamin $B 12$ , cyancobalamin, is essential for human nutrition. Its molecular formula is $C 63 H 88 CoN 14 O 14 P$ . A lack of this vita min in the diet can lead to anemia. Cyanocohalamin is the form of the vitamin found in vitamin supplements.

l type='a'>

What is the molar mass of cyanocobalamin to two decimal places?

How many moles of cyanocohalamin molecules are present in 250 mg of cyanocobalamin?

What is the mass of 0.60 mole of cyanocobalamin?

How many atoms of hydrogen are in 1 .0 mole of cyanocobalamin?

What is the mass of

$1 .0 × 10 7$ molecules of cyanocobalamin?

What is the mass (in grams) of one molecule of cyanocobalamin?

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The molar mass of cyanocobalamin upto two decimal places is to be calculated.

Concept Introduction:

A molar mass of a substance is the mass of the substance divided by the number of moles of the substance. The SI unit of molar mass of $kg/mol$ and other unit is $g/mol$ .

The formula to calculate the molar mass is,

$Molar mass of the substance= Mass of the substancegNumber of moles$ .

Answer to Problem 128CP

The molar mass of cyanocobalamin to two decimal places is $1353.76 g/mol$ .

Explanation of Solution

The molecular formula of cyanocobalamnin is $C63H88CoN14O14P$ .

The molar mass of carbon is $12 g/mol$ .

The molar mass of hydrogen is $1 g/mol$ .

The molar mass of oxygen is $15.99 g/mol$ .

The molar mass of nitrogen is $14 g/mol$ .

The molar mass of phosphorus is $30.97 g/mol$ .

The molar mass of cobalt is $58.93 g/mol$ .

The molar mass of cyanocobalamnin is calculated by the expression,

$Molar mass of C63H88CoN14O14P=63×molar mass of C+88×molar mass of H+1×molar mass of Co+14×molar mass of N+14×molar mass of O+1×molar mass of P$

Substitute the respective values of molar mass of each element in the above exopression.

$Molar mass of C63H88CoN14O14P=63×12 g/mol+88×1 g/mol+1×58.93 g/mol+14×14 g/mol+14×15.99 g/mol+1×30.97 g/mol=1353.76 g/mol$

Thus, the molar mass of cyanocobalmaine is $1353.76 g/mol$ .

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The number of moles of cyanaocobalamin molecules present in $250 mg$ of cyanaocobalamin is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The number of moles of cyanocobalamin molecules present in $250 mg$ of cyanocobalamin is $1.85×10−4 mol$ .

Explanation of Solution

The given mass of cyanocobalamin is $250 mg$ .

The conversion of $mg$ to $g$ is done as,

$1 mg=10−3 g$

Thus, the mass of cyanocobalamin is $0.250 g$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

The moles of cyanocobalamin is calculated by the expression,

$Number of moles= Mass of the substancegMolar mass of the substance$

Substitute the value of mass and molar of cyanocobalamin in the above expression.

$Number of moles of cyanocobalamin=0.25 g1353.76 g/mol=1.85×10−4 mol$

The number of moles of cyanocobalamin molecules present in $250 mg$ of cyanocobalamin is $1.85×10−4 mol$ .

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The mass of $0.60 mol$ of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of $0.60 mol$ of cyanocobalamine is $812.26 g$ .

Explanation of Solution

The given moles of cyanocobalamin is $0.60 mol$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

The mass of cyanocobalamin is calculated by the expression,

$Mass of the substanceg=Number of moles×Molar mass of the substance$

Substitute the value of moles and molar of cyanocobalamin in the above expression.

$Mass of cyanocobalamine=0.60×1353.76 g/mol=812.26 g$

Thus, the mass of $0.60 mol$ of cyanocobalamine is $812.26 g$ .

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are $5.29×1025 atoms$ .

Explanation of Solution

The given moles of cyanocobalamin is $0.60 mol$ .

According to the molecular formula of cyanocobalamine that is $C63H88CoN14O14P$ , there are total $88$ atoms of hydrogen present in cyanocobalamine.

If $1.0 mol$ of substance contains $6.02214076×1023$ of atoms then one mole of cyanocobalamine contains $6.02214076×1023×88=5.29×1025 atoms of hydrogen$

Thus, atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are $5.29×1025 atoms$ .

Expert Solution

Interpretation Introduction

(e)

Interpretation:

The mass of $1×107 molecules$ of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of $1×107 molecules$ of cyanocobalamine is $244.80 ×10−16 g$ .

Explanation of Solution

The given number of molecules of cyanocobalamin is $1×107 molecules$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

$1.0 mol$ of substance contains $6.022×1023$ of atoms/molecules.

Thus, the mass of $1×107 molecules$ of cyanocobalamin is,

$Mass=1353.766.022×1023×107=244.80 ×10−16 g$

Thus, the mass of $1×107 molecules$ of cyanocobalamine is $244.80 ×10−16 g$ .

Expert Solution

Interpretation Introduction

(f)

Interpretation:

The mass of one molecule of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of one molecule of cyanocobalamine is $244.80 ×10−23 g$ .

Explanation of Solution

The given number of molecules of cyanocobalamin is $1×107 molecules$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

$1.0 mol$ of substance contains $6.022×1023$ atoms/molecules.

Thus, the mass of $1$ molecule of cyanocobalamin is,

$Mass=1353.766.022×1023×1=244.80 ×10−23 g$

Thus, the mass of $1 molecule$ of cyanocobalamine is $244.80 ×10−23 g$ .

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Answer 2

Textbook Question

Chapter 8, Problem 128CP

itamin $B 12$ , cyancobalamin, is essential for human nutrition. Its molecular formula is $C 63 H 88 CoN 14 O 14 P$ . A lack of this vita min in the diet can lead to anemia. Cyanocohalamin is the form of the vitamin found in vitamin supplements.

l type='a'>

What is the molar mass of cyanocobalamin to two decimal places?

How many moles of cyanocohalamin molecules are present in 250 mg of cyanocobalamin?

What is the mass of 0.60 mole of cyanocobalamin?

How many atoms of hydrogen are in 1 .0 mole of cyanocobalamin?

What is the mass of

$1 .0 × 10 7$ molecules of cyanocobalamin?

What is the mass (in grams) of one molecule of cyanocobalamin?

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The molar mass of cyanocobalamin upto two decimal places is to be calculated.

Concept Introduction:

A molar mass of a substance is the mass of the substance divided by the number of moles of the substance. The SI unit of molar mass of $kg/mol$ and other unit is $g/mol$ .

The formula to calculate the molar mass is,

$Molar mass of the substance= Mass of the substancegNumber of moles$ .

Answer to Problem 128CP

The molar mass of cyanocobalamin to two decimal places is $1353.76 g/mol$ .

Explanation of Solution

The molecular formula of cyanocobalamnin is $C63H88CoN14O14P$ .

The molar mass of carbon is $12 g/mol$ .

The molar mass of hydrogen is $1 g/mol$ .

The molar mass of oxygen is $15.99 g/mol$ .

The molar mass of nitrogen is $14 g/mol$ .

The molar mass of phosphorus is $30.97 g/mol$ .

The molar mass of cobalt is $58.93 g/mol$ .

The molar mass of cyanocobalamnin is calculated by the expression,

$Molar mass of C63H88CoN14O14P=63×molar mass of C+88×molar mass of H+1×molar mass of Co+14×molar mass of N+14×molar mass of O+1×molar mass of P$

Substitute the respective values of molar mass of each element in the above exopression.

$Molar mass of C63H88CoN14O14P=63×12 g/mol+88×1 g/mol+1×58.93 g/mol+14×14 g/mol+14×15.99 g/mol+1×30.97 g/mol=1353.76 g/mol$

Thus, the molar mass of cyanocobalmaine is $1353.76 g/mol$ .

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The number of moles of cyanaocobalamin molecules present in $250 mg$ of cyanaocobalamin is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The number of moles of cyanocobalamin molecules present in $250 mg$ of cyanocobalamin is $1.85×10−4 mol$ .

Explanation of Solution

The given mass of cyanocobalamin is $250 mg$ .

The conversion of $mg$ to $g$ is done as,

$1 mg=10−3 g$

Thus, the mass of cyanocobalamin is $0.250 g$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

The moles of cyanocobalamin is calculated by the expression,

$Number of moles= Mass of the substancegMolar mass of the substance$

Substitute the value of mass and molar of cyanocobalamin in the above expression.

$Number of moles of cyanocobalamin=0.25 g1353.76 g/mol=1.85×10−4 mol$

The number of moles of cyanocobalamin molecules present in $250 mg$ of cyanocobalamin is $1.85×10−4 mol$ .

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The mass of $0.60 mol$ of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of $0.60 mol$ of cyanocobalamine is $812.26 g$ .

Explanation of Solution

The given moles of cyanocobalamin is $0.60 mol$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

The mass of cyanocobalamin is calculated by the expression,

$Mass of the substanceg=Number of moles×Molar mass of the substance$

Substitute the value of moles and molar of cyanocobalamin in the above expression.

$Mass of cyanocobalamine=0.60×1353.76 g/mol=812.26 g$

Thus, the mass of $0.60 mol$ of cyanocobalamine is $812.26 g$ .

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are $5.29×1025 atoms$ .

Explanation of Solution

The given moles of cyanocobalamin is $0.60 mol$ .

According to the molecular formula of cyanocobalamine that is $C63H88CoN14O14P$ , there are total $88$ atoms of hydrogen present in cyanocobalamine.

If $1.0 mol$ of substance contains $6.02214076×1023$ of atoms then one mole of cyanocobalamine contains $6.02214076×1023×88=5.29×1025 atoms of hydrogen$

Thus, atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are $5.29×1025 atoms$ .

Expert Solution

Interpretation Introduction

(e)

Interpretation:

The mass of $1×107 molecules$ of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of $1×107 molecules$ of cyanocobalamine is $244.80 ×10−16 g$ .

Explanation of Solution

The given number of molecules of cyanocobalamin is $1×107 molecules$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

$1.0 mol$ of substance contains $6.022×1023$ of atoms/molecules.

Thus, the mass of $1×107 molecules$ of cyanocobalamin is,

$Mass=1353.766.022×1023×107=244.80 ×10−16 g$

Thus, the mass of $1×107 molecules$ of cyanocobalamine is $244.80 ×10−16 g$ .

Expert Solution

Interpretation Introduction

(f)

Interpretation:

The mass of one molecule of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of one molecule of cyanocobalamine is $244.80 ×10−23 g$ .

Explanation of Solution

The given number of molecules of cyanocobalamin is $1×107 molecules$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

$1.0 mol$ of substance contains $6.022×1023$ atoms/molecules.

Thus, the mass of $1$ molecule of cyanocobalamin is,

$Mass=1353.766.022×1023×1=244.80 ×10−23 g$

Thus, the mass of $1 molecule$ of cyanocobalamine is $244.80 ×10−23 g$ .

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Answer 3

Textbook Question

Chapter 8, Problem 128CP

itamin $B 12$ , cyancobalamin, is essential for human nutrition. Its molecular formula is $C 63 H 88 CoN 14 O 14 P$ . A lack of this vita min in the diet can lead to anemia. Cyanocohalamin is the form of the vitamin found in vitamin supplements.

l type='a'>

What is the molar mass of cyanocobalamin to two decimal places?

How many moles of cyanocohalamin molecules are present in 250 mg of cyanocobalamin?

What is the mass of 0.60 mole of cyanocobalamin?

How many atoms of hydrogen are in 1 .0 mole of cyanocobalamin?

What is the mass of

$1 .0 × 10 7$ molecules of cyanocobalamin?

What is the mass (in grams) of one molecule of cyanocobalamin?

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The molar mass of cyanocobalamin upto two decimal places is to be calculated.

Concept Introduction:

A molar mass of a substance is the mass of the substance divided by the number of moles of the substance. The SI unit of molar mass of $kg/mol$ and other unit is $g/mol$ .

The formula to calculate the molar mass is,

$Molar mass of the substance= Mass of the substancegNumber of moles$ .

Answer to Problem 128CP

The molar mass of cyanocobalamin to two decimal places is $1353.76 g/mol$ .

Explanation of Solution

The molecular formula of cyanocobalamnin is $C63H88CoN14O14P$ .

The molar mass of carbon is $12 g/mol$ .

The molar mass of hydrogen is $1 g/mol$ .

The molar mass of oxygen is $15.99 g/mol$ .

The molar mass of nitrogen is $14 g/mol$ .

The molar mass of phosphorus is $30.97 g/mol$ .

The molar mass of cobalt is $58.93 g/mol$ .

The molar mass of cyanocobalamnin is calculated by the expression,

$Molar mass of C63H88CoN14O14P=63×molar mass of C+88×molar mass of H+1×molar mass of Co+14×molar mass of N+14×molar mass of O+1×molar mass of P$

Substitute the respective values of molar mass of each element in the above exopression.

$Molar mass of C63H88CoN14O14P=63×12 g/mol+88×1 g/mol+1×58.93 g/mol+14×14 g/mol+14×15.99 g/mol+1×30.97 g/mol=1353.76 g/mol$

Thus, the molar mass of cyanocobalmaine is $1353.76 g/mol$ .

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The number of moles of cyanaocobalamin molecules present in $250 mg$ of cyanaocobalamin is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The number of moles of cyanocobalamin molecules present in $250 mg$ of cyanocobalamin is $1.85×10−4 mol$ .

Explanation of Solution

The given mass of cyanocobalamin is $250 mg$ .

The conversion of $mg$ to $g$ is done as,

$1 mg=10−3 g$

Thus, the mass of cyanocobalamin is $0.250 g$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

The moles of cyanocobalamin is calculated by the expression,

$Number of moles= Mass of the substancegMolar mass of the substance$

Substitute the value of mass and molar of cyanocobalamin in the above expression.

$Number of moles of cyanocobalamin=0.25 g1353.76 g/mol=1.85×10−4 mol$

The number of moles of cyanocobalamin molecules present in $250 mg$ of cyanocobalamin is $1.85×10−4 mol$ .

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The mass of $0.60 mol$ of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of $0.60 mol$ of cyanocobalamine is $812.26 g$ .

Explanation of Solution

The given moles of cyanocobalamin is $0.60 mol$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

The mass of cyanocobalamin is calculated by the expression,

$Mass of the substanceg=Number of moles×Molar mass of the substance$

Substitute the value of moles and molar of cyanocobalamin in the above expression.

$Mass of cyanocobalamine=0.60×1353.76 g/mol=812.26 g$

Thus, the mass of $0.60 mol$ of cyanocobalamine is $812.26 g$ .

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are $5.29×1025 atoms$ .

Explanation of Solution

The given moles of cyanocobalamin is $0.60 mol$ .

According to the molecular formula of cyanocobalamine that is $C63H88CoN14O14P$ , there are total $88$ atoms of hydrogen present in cyanocobalamine.

If $1.0 mol$ of substance contains $6.02214076×1023$ of atoms then one mole of cyanocobalamine contains $6.02214076×1023×88=5.29×1025 atoms of hydrogen$

Thus, atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are $5.29×1025 atoms$ .

Expert Solution

Interpretation Introduction

(e)

Interpretation:

The mass of $1×107 molecules$ of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of $1×107 molecules$ of cyanocobalamine is $244.80 ×10−16 g$ .

Explanation of Solution

The given number of molecules of cyanocobalamin is $1×107 molecules$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

$1.0 mol$ of substance contains $6.022×1023$ of atoms/molecules.

Thus, the mass of $1×107 molecules$ of cyanocobalamin is,

$Mass=1353.766.022×1023×107=244.80 ×10−16 g$

Thus, the mass of $1×107 molecules$ of cyanocobalamine is $244.80 ×10−16 g$ .

Expert Solution

Interpretation Introduction

(f)

Interpretation:

The mass of one molecule of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of one molecule of cyanocobalamine is $244.80 ×10−23 g$ .

Explanation of Solution

The given number of molecules of cyanocobalamin is $1×107 molecules$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

$1.0 mol$ of substance contains $6.022×1023$ atoms/molecules.

Thus, the mass of $1$ molecule of cyanocobalamin is,

$Mass=1353.766.022×1023×1=244.80 ×10−23 g$

Thus, the mass of $1 molecule$ of cyanocobalamine is $244.80 ×10−23 g$ .

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Answer 4

Textbook Question

Chapter 8, Problem 128CP

itamin $B 12$ , cyancobalamin, is essential for human nutrition. Its molecular formula is $C 63 H 88 CoN 14 O 14 P$ . A lack of this vita min in the diet can lead to anemia. Cyanocohalamin is the form of the vitamin found in vitamin supplements.

l type='a'>

What is the molar mass of cyanocobalamin to two decimal places?

How many moles of cyanocohalamin molecules are present in 250 mg of cyanocobalamin?

What is the mass of 0.60 mole of cyanocobalamin?

How many atoms of hydrogen are in 1 .0 mole of cyanocobalamin?

What is the mass of

$1 .0 × 10 7$ molecules of cyanocobalamin?

What is the mass (in grams) of one molecule of cyanocobalamin?

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The molar mass of cyanocobalamin upto two decimal places is to be calculated.

Concept Introduction:

A molar mass of a substance is the mass of the substance divided by the number of moles of the substance. The SI unit of molar mass of $kg/mol$ and other unit is $g/mol$ .

The formula to calculate the molar mass is,

$Molar mass of the substance= Mass of the substancegNumber of moles$ .

Answer to Problem 128CP

The molar mass of cyanocobalamin to two decimal places is $1353.76 g/mol$ .

Explanation of Solution

The molecular formula of cyanocobalamnin is $C63H88CoN14O14P$ .

The molar mass of carbon is $12 g/mol$ .

The molar mass of hydrogen is $1 g/mol$ .

The molar mass of oxygen is $15.99 g/mol$ .

The molar mass of nitrogen is $14 g/mol$ .

The molar mass of phosphorus is $30.97 g/mol$ .

The molar mass of cobalt is $58.93 g/mol$ .

The molar mass of cyanocobalamnin is calculated by the expression,

$Molar mass of C63H88CoN14O14P=63×molar mass of C+88×molar mass of H+1×molar mass of Co+14×molar mass of N+14×molar mass of O+1×molar mass of P$

Substitute the respective values of molar mass of each element in the above exopression.

$Molar mass of C63H88CoN14O14P=63×12 g/mol+88×1 g/mol+1×58.93 g/mol+14×14 g/mol+14×15.99 g/mol+1×30.97 g/mol=1353.76 g/mol$

Thus, the molar mass of cyanocobalmaine is $1353.76 g/mol$ .

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The number of moles of cyanaocobalamin molecules present in $250 mg$ of cyanaocobalamin is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The number of moles of cyanocobalamin molecules present in $250 mg$ of cyanocobalamin is $1.85×10−4 mol$ .

Explanation of Solution

The given mass of cyanocobalamin is $250 mg$ .

The conversion of $mg$ to $g$ is done as,

$1 mg=10−3 g$

Thus, the mass of cyanocobalamin is $0.250 g$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

The moles of cyanocobalamin is calculated by the expression,

$Number of moles= Mass of the substancegMolar mass of the substance$

Substitute the value of mass and molar of cyanocobalamin in the above expression.

$Number of moles of cyanocobalamin=0.25 g1353.76 g/mol=1.85×10−4 mol$

The number of moles of cyanocobalamin molecules present in $250 mg$ of cyanocobalamin is $1.85×10−4 mol$ .

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The mass of $0.60 mol$ of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of $0.60 mol$ of cyanocobalamine is $812.26 g$ .

Explanation of Solution

The given moles of cyanocobalamin is $0.60 mol$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

The mass of cyanocobalamin is calculated by the expression,

$Mass of the substanceg=Number of moles×Molar mass of the substance$

Substitute the value of moles and molar of cyanocobalamin in the above expression.

$Mass of cyanocobalamine=0.60×1353.76 g/mol=812.26 g$

Thus, the mass of $0.60 mol$ of cyanocobalamine is $812.26 g$ .

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are $5.29×1025 atoms$ .

Explanation of Solution

The given moles of cyanocobalamin is $0.60 mol$ .

According to the molecular formula of cyanocobalamine that is $C63H88CoN14O14P$ , there are total $88$ atoms of hydrogen present in cyanocobalamine.

If $1.0 mol$ of substance contains $6.02214076×1023$ of atoms then one mole of cyanocobalamine contains $6.02214076×1023×88=5.29×1025 atoms of hydrogen$

Thus, atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are $5.29×1025 atoms$ .

Expert Solution

Interpretation Introduction

(e)

Interpretation:

The mass of $1×107 molecules$ of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of $1×107 molecules$ of cyanocobalamine is $244.80 ×10−16 g$ .

Explanation of Solution

The given number of molecules of cyanocobalamin is $1×107 molecules$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

$1.0 mol$ of substance contains $6.022×1023$ of atoms/molecules.

Thus, the mass of $1×107 molecules$ of cyanocobalamin is,

$Mass=1353.766.022×1023×107=244.80 ×10−16 g$

Thus, the mass of $1×107 molecules$ of cyanocobalamine is $244.80 ×10−16 g$ .

Expert Solution

Interpretation Introduction

(f)

Interpretation:

The mass of one molecule of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of one molecule of cyanocobalamine is $244.80 ×10−23 g$ .

Explanation of Solution

The given number of molecules of cyanocobalamin is $1×107 molecules$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

$1.0 mol$ of substance contains $6.022×1023$ atoms/molecules.

Thus, the mass of $1$ molecule of cyanocobalamin is,

$Mass=1353.766.022×1023×1=244.80 ×10−23 g$

Thus, the mass of $1 molecule$ of cyanocobalamine is $244.80 ×10−23 g$ .

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The molar mass of cyanocobalamin upto two decimal places is to be calculated.

Concept Introduction:

A molar mass of a substance is the mass of the substance divided by the number of moles of the substance. The SI unit of molar mass of $kg/mol$ and other unit is $g/mol$ .

The formula to calculate the molar mass is,

$Molar mass of the substance= Mass of the substancegNumber of moles$ .

Answer to Problem 128CP

The molar mass of cyanocobalamin to two decimal places is $1353.76 g/mol$ .

Explanation of Solution

The molecular formula of cyanocobalamnin is $C63H88CoN14O14P$ .

The molar mass of carbon is $12 g/mol$ .

The molar mass of hydrogen is $1 g/mol$ .

The molar mass of oxygen is $15.99 g/mol$ .

The molar mass of nitrogen is $14 g/mol$ .

The molar mass of phosphorus is $30.97 g/mol$ .

The molar mass of cobalt is $58.93 g/mol$ .

The molar mass of cyanocobalamnin is calculated by the expression,

$Molar mass of C63H88CoN14O14P=63×molar mass of C+88×molar mass of H+1×molar mass of Co+14×molar mass of N+14×molar mass of O+1×molar mass of P$

Substitute the respective values of molar mass of each element in the above exopression.

$Molar mass of C63H88CoN14O14P=63×12 g/mol+88×1 g/mol+1×58.93 g/mol+14×14 g/mol+14×15.99 g/mol+1×30.97 g/mol=1353.76 g/mol$

Thus, the molar mass of cyanocobalmaine is $1353.76 g/mol$ .

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The number of moles of cyanaocobalamin molecules present in $250 mg$ of cyanaocobalamin is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The number of moles of cyanocobalamin molecules present in $250 mg$ of cyanocobalamin is $1.85×10−4 mol$ .

Explanation of Solution

The given mass of cyanocobalamin is $250 mg$ .

The conversion of $mg$ to $g$ is done as,

$1 mg=10−3 g$

Thus, the mass of cyanocobalamin is $0.250 g$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

The moles of cyanocobalamin is calculated by the expression,

$Number of moles= Mass of the substancegMolar mass of the substance$

Substitute the value of mass and molar of cyanocobalamin in the above expression.

$Number of moles of cyanocobalamin=0.25 g1353.76 g/mol=1.85×10−4 mol$

The number of moles of cyanocobalamin molecules present in $250 mg$ of cyanocobalamin is $1.85×10−4 mol$ .

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The mass of $0.60 mol$ of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of $0.60 mol$ of cyanocobalamine is $812.26 g$ .

Explanation of Solution

The given moles of cyanocobalamin is $0.60 mol$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

The mass of cyanocobalamin is calculated by the expression,

$Mass of the substanceg=Number of moles×Molar mass of the substance$

Substitute the value of moles and molar of cyanocobalamin in the above expression.

$Mass of cyanocobalamine=0.60×1353.76 g/mol=812.26 g$

Thus, the mass of $0.60 mol$ of cyanocobalamine is $812.26 g$ .

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are $5.29×1025 atoms$ .

Explanation of Solution

The given moles of cyanocobalamin is $0.60 mol$ .

According to the molecular formula of cyanocobalamine that is $C63H88CoN14O14P$ , there are total $88$ atoms of hydrogen present in cyanocobalamine.

If $1.0 mol$ of substance contains $6.02214076×1023$ of atoms then one mole of cyanocobalamine contains $6.02214076×1023×88=5.29×1025 atoms of hydrogen$

Thus, atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are $5.29×1025 atoms$ .

Expert Solution

Interpretation Introduction

(e)

Interpretation:

The mass of $1×107 molecules$ of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of $1×107 molecules$ of cyanocobalamine is $244.80 ×10−16 g$ .

Explanation of Solution

The given number of molecules of cyanocobalamin is $1×107 molecules$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

$1.0 mol$ of substance contains $6.022×1023$ of atoms/molecules.

Thus, the mass of $1×107 molecules$ of cyanocobalamin is,

$Mass=1353.766.022×1023×107=244.80 ×10−16 g$

Thus, the mass of $1×107 molecules$ of cyanocobalamine is $244.80 ×10−16 g$ .

Expert Solution

Interpretation Introduction

(f)

Interpretation:

The mass of one molecule of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of one molecule of cyanocobalamine is $244.80 ×10−23 g$ .

Explanation of Solution

The given number of molecules of cyanocobalamin is $1×107 molecules$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

$1.0 mol$ of substance contains $6.022×1023$ atoms/molecules.

Thus, the mass of $1$ molecule of cyanocobalamin is,

$Mass=1353.766.022×1023×1=244.80 ×10−23 g$

Thus, the mass of $1 molecule$ of cyanocobalamine is $244.80 ×10−23 g$ .

Answer 8

Expert Solution

Interpretation Introduction

(a)

Interpretation:

The molar mass of cyanocobalamin upto two decimal places is to be calculated.

Concept Introduction:

A molar mass of a substance is the mass of the substance divided by the number of moles of the substance. The SI unit of molar mass of $kg/mol$ and other unit is $g/mol$ .

The formula to calculate the molar mass is,

$Molar mass of the substance= Mass of the substancegNumber of moles$ .

Answer to Problem 128CP

The molar mass of cyanocobalamin to two decimal places is $1353.76 g/mol$ .

Explanation of Solution

The molecular formula of cyanocobalamnin is $C63H88CoN14O14P$ .

The molar mass of carbon is $12 g/mol$ .

The molar mass of hydrogen is $1 g/mol$ .

The molar mass of oxygen is $15.99 g/mol$ .

The molar mass of nitrogen is $14 g/mol$ .

The molar mass of phosphorus is $30.97 g/mol$ .

The molar mass of cobalt is $58.93 g/mol$ .

The molar mass of cyanocobalamnin is calculated by the expression,

$Molar mass of C63H88CoN14O14P=63×molar mass of C+88×molar mass of H+1×molar mass of Co+14×molar mass of N+14×molar mass of O+1×molar mass of P$

Substitute the respective values of molar mass of each element in the above exopression.

$Molar mass of C63H88CoN14O14P=63×12 g/mol+88×1 g/mol+1×58.93 g/mol+14×14 g/mol+14×15.99 g/mol+1×30.97 g/mol=1353.76 g/mol$

Thus, the molar mass of cyanocobalmaine is $1353.76 g/mol$ .

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

(a)

Interpretation:

The molar mass of cyanocobalamin upto two decimal places is to be calculated.

Concept Introduction:

A molar mass of a substance is the mass of the substance divided by the number of moles of the substance. The SI unit of molar mass of $kg/mol$ and other unit is $g/mol$ .

The formula to calculate the molar mass is,

$Molar mass of the substance= Mass of the substancegNumber of moles$ .

Answer 13

Answer to Problem 128CP

The molar mass of cyanocobalamin to two decimal places is $1353.76 g/mol$ .

Answer 14

Explanation of Solution

The molecular formula of cyanocobalamnin is $C63H88CoN14O14P$ .

The molar mass of carbon is $12 g/mol$ .

The molar mass of hydrogen is $1 g/mol$ .

The molar mass of oxygen is $15.99 g/mol$ .

The molar mass of nitrogen is $14 g/mol$ .

The molar mass of phosphorus is $30.97 g/mol$ .

The molar mass of cobalt is $58.93 g/mol$ .

The molar mass of cyanocobalamnin is calculated by the expression,

$Molar mass of C63H88CoN14O14P=63×molar mass of C+88×molar mass of H+1×molar mass of Co+14×molar mass of N+14×molar mass of O+1×molar mass of P$

Substitute the respective values of molar mass of each element in the above exopression.

$Molar mass of C63H88CoN14O14P=63×12 g/mol+88×1 g/mol+1×58.93 g/mol+14×14 g/mol+14×15.99 g/mol+1×30.97 g/mol=1353.76 g/mol$

Thus, the molar mass of cyanocobalmaine is $1353.76 g/mol$ .

Answer 15

Expert Solution

Interpretation Introduction

(b)

Interpretation:

The number of moles of cyanaocobalamin molecules present in $250 mg$ of cyanaocobalamin is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The number of moles of cyanocobalamin molecules present in $250 mg$ of cyanocobalamin is $1.85×10−4 mol$ .

Explanation of Solution

The given mass of cyanocobalamin is $250 mg$ .

The conversion of $mg$ to $g$ is done as,

$1 mg=10−3 g$

Thus, the mass of cyanocobalamin is $0.250 g$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

The moles of cyanocobalamin is calculated by the expression,

$Number of moles= Mass of the substancegMolar mass of the substance$

Substitute the value of mass and molar of cyanocobalamin in the above expression.

$Number of moles of cyanocobalamin=0.25 g1353.76 g/mol=1.85×10−4 mol$

The number of moles of cyanocobalamin molecules present in $250 mg$ of cyanocobalamin is $1.85×10−4 mol$ .

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Interpretation Introduction

(b)

Interpretation:

The number of moles of cyanaocobalamin molecules present in $250 mg$ of cyanaocobalamin is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer 20

Answer to Problem 128CP

The number of moles of cyanocobalamin molecules present in $250 mg$ of cyanocobalamin is $1.85×10−4 mol$ .

Answer 21

Explanation of Solution

The given mass of cyanocobalamin is $250 mg$ .

The conversion of $mg$ to $g$ is done as,

$1 mg=10−3 g$

Thus, the mass of cyanocobalamin is $0.250 g$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

The moles of cyanocobalamin is calculated by the expression,

$Number of moles= Mass of the substancegMolar mass of the substance$

Substitute the value of mass and molar of cyanocobalamin in the above expression.

$Number of moles of cyanocobalamin=0.25 g1353.76 g/mol=1.85×10−4 mol$

The number of moles of cyanocobalamin molecules present in $250 mg$ of cyanocobalamin is $1.85×10−4 mol$ .

Answer 22

Expert Solution

Interpretation Introduction

(c)

Interpretation:

The mass of $0.60 mol$ of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of $0.60 mol$ of cyanocobalamine is $812.26 g$ .

Explanation of Solution

The given moles of cyanocobalamin is $0.60 mol$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

The mass of cyanocobalamin is calculated by the expression,

$Mass of the substanceg=Number of moles×Molar mass of the substance$

Substitute the value of moles and molar of cyanocobalamin in the above expression.

$Mass of cyanocobalamine=0.60×1353.76 g/mol=812.26 g$

Thus, the mass of $0.60 mol$ of cyanocobalamine is $812.26 g$ .

Answer 23

Expert Solution

Answer 24

Expert Solution

Answer 25

Expert Solution

Answer 26

Interpretation Introduction

(c)

Interpretation:

The mass of $0.60 mol$ of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer 27

Answer to Problem 128CP

The mass of $0.60 mol$ of cyanocobalamine is $812.26 g$ .

Answer 28

Explanation of Solution

The given moles of cyanocobalamin is $0.60 mol$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

The mass of cyanocobalamin is calculated by the expression,

$Mass of the substanceg=Number of moles×Molar mass of the substance$

Substitute the value of moles and molar of cyanocobalamin in the above expression.

$Mass of cyanocobalamine=0.60×1353.76 g/mol=812.26 g$

Thus, the mass of $0.60 mol$ of cyanocobalamine is $812.26 g$ .

Answer 29

Expert Solution

Interpretation Introduction

(d)

Interpretation:

The atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are $5.29×1025 atoms$ .

Explanation of Solution

The given moles of cyanocobalamin is $0.60 mol$ .

According to the molecular formula of cyanocobalamine that is $C63H88CoN14O14P$ , there are total $88$ atoms of hydrogen present in cyanocobalamine.

If $1.0 mol$ of substance contains $6.02214076×1023$ of atoms then one mole of cyanocobalamine contains $6.02214076×1023×88=5.29×1025 atoms of hydrogen$

Thus, atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are $5.29×1025 atoms$ .

Answer 30

Expert Solution

Answer 31

Expert Solution

Answer 32

Expert Solution

Answer 33

Interpretation Introduction

(d)

Interpretation:

The atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer 34

Answer to Problem 128CP

The atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are $5.29×1025 atoms$ .

Answer 35

Explanation of Solution

The given moles of cyanocobalamin is $0.60 mol$ .

According to the molecular formula of cyanocobalamine that is $C63H88CoN14O14P$ , there are total $88$ atoms of hydrogen present in cyanocobalamine.

If $1.0 mol$ of substance contains $6.02214076×1023$ of atoms then one mole of cyanocobalamine contains $6.02214076×1023×88=5.29×1025 atoms of hydrogen$

Thus, atoms of hydrogen that are present in $1.0 mol$ of cyanocobalamin are $5.29×1025 atoms$ .

Answer 36

Expert Solution

Interpretation Introduction

(e)

Interpretation:

The mass of $1×107 molecules$ of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of $1×107 molecules$ of cyanocobalamine is $244.80 ×10−16 g$ .

Explanation of Solution

The given number of molecules of cyanocobalamin is $1×107 molecules$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

$1.0 mol$ of substance contains $6.022×1023$ of atoms/molecules.

Thus, the mass of $1×107 molecules$ of cyanocobalamin is,

$Mass=1353.766.022×1023×107=244.80 ×10−16 g$

Thus, the mass of $1×107 molecules$ of cyanocobalamine is $244.80 ×10−16 g$ .

Answer 37

Expert Solution

Answer 38

Expert Solution

Answer 39

Expert Solution

Answer 40

Interpretation Introduction

(e)

Interpretation:

The mass of $1×107 molecules$ of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer 41

Answer to Problem 128CP

The mass of $1×107 molecules$ of cyanocobalamine is $244.80 ×10−16 g$ .

Answer 42

Explanation of Solution

The given number of molecules of cyanocobalamin is $1×107 molecules$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

$1.0 mol$ of substance contains $6.022×1023$ of atoms/molecules.

Thus, the mass of $1×107 molecules$ of cyanocobalamin is,

$Mass=1353.766.022×1023×107=244.80 ×10−16 g$

Thus, the mass of $1×107 molecules$ of cyanocobalamine is $244.80 ×10−16 g$ .

Answer 43

Expert Solution

Interpretation Introduction

(f)

Interpretation:

The mass of one molecule of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer to Problem 128CP

The mass of one molecule of cyanocobalamine is $244.80 ×10−23 g$ .

Explanation of Solution

The given number of molecules of cyanocobalamin is $1×107 molecules$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

$1.0 mol$ of substance contains $6.022×1023$ atoms/molecules.

Thus, the mass of $1$ molecule of cyanocobalamin is,

$Mass=1353.766.022×1023×1=244.80 ×10−23 g$

Thus, the mass of $1 molecule$ of cyanocobalamine is $244.80 ×10−23 g$ .

Answer 44

Expert Solution

Answer 45

Expert Solution

Answer 46

Expert Solution

Answer 47

Interpretation Introduction

(f)

Interpretation:

The mass of one molecule of cyanocobalamine is to be stated.

Concept Introduction:

A mole of a substance contains exactly $6.02214076×1023$ of atoms/molecules. It is used to measure the amount of the substance in SI units.

The formula to calculate the number of moles is:

$Number of moles= Mass of the substancegMolar mass of the substance$ .

Answer 48

Answer to Problem 128CP

The mass of one molecule of cyanocobalamine is $244.80 ×10−23 g$ .

Answer 49

Explanation of Solution

The given number of molecules of cyanocobalamin is $1×107 molecules$ .

The molar mass of cyanocobalamin is $1353.76 g/mol$ .

$1.0 mol$ of substance contains $6.022×1023$ atoms/molecules.

Thus, the mass of $1$ molecule of cyanocobalamin is,

$Mass=1353.766.022×1023×1=244.80 ×10−23 g$

Thus, the mass of $1 molecule$ of cyanocobalamine is $244.80 ×10−23 g$ .

Answer 50

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Answer to Problem 128CP

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Answer to Problem 128CP

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Answer to Problem 128CP

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Answer to Problem 128CP

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