Unit of pressure has to be converted from m m Hg to a t m . Concept Introduction: Pressure of gas is the force applied on a unit area. Pressure = Force Area Pressure can be expressed in different units. General unit conversions: 1 Pa = 1Nm − 2 = 1 kgm − 1 s − 2 ; 1 kPa = 10 3 Pa 1 bar = 10 5 Pa = 10 3 kPa; mbar = 10 2 Pa 1 atm = 1.01325 × 10 5 Pa = 101 .325 kPa 1 atm = 760 Torr = 760 mm Hg 1 atm = 14 .7 lb/in 2 ( p s i ) = 1 .01325 bar

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Answer 1

Question

Chapter 8, Problem 11QRT

(a)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $mmHg$ to $atm.$

Concept Introduction:

Pressure of gas is the force applied on a unit area.

$Pressure = ForceArea$

Pressure can be expressed in different units.

General unit conversions:

$1 Pa = 1Nm−2 = 1 kgm−1s−2; 1 kPa = 103 Pa1 bar = 105 Pa = 103 kPa; mbar = 102 Pa1 atm = 1.01325×105 Pa = 101.325 kPa1 atm = 760 Torr = 760 mm Hg1 atm = 14.7 lb/in2(psi) = 1.01325 bar$

(a)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $0.158 atm.$

Explanation of Solution

Given that pressure is $120 mmHg.$

Convert the unit of pressure from $mmHg$ to $atm$ as follows,

$P= 120 mmHg ×1 atm760 mmHg= 0.158 atm$

Hence, pressure in $atm$ is $0.158 atm.$

(b)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $atm$ to $mmHg.$

Concept Introduction:

Refer to part (a)

(b)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $1.52×103 mmHg.$

Explanation of Solution

Given that pressure is $2.00 atm.$

Convert the unit of pressure from $atm$ to $mmHg$ as follows,

$P= 2.00 atm ×760 mmHg1 atm= 1.52×103 mmHg$

Hence, pressure in $mmHg$ is $1.52×103 mmHg.$

(c)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $100.0 kPa.$

Concept Introduction:

Refer to part (a)

(c)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $750.0 mmHg.$

Explanation of Solution

Given that pressure is $100.0 kPa.$

Convert the unit of pressure from $kPa$ to $mmHg$ as follows,

$P= 100.0 kPa×1 atm101.325 kPa×760 mmHg1 atm= 750.0 mmHg$

Hence, pressure in $mmHg$ is $750.0 mmHg.$

(d)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $200.0 kPa.$

Concept Introduction:

Refer to part (a)

(d)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $1.97 atm.$

Explanation of Solution

Given that pressure is $200.0 kPa.$

Convert the unit of pressure from $kPa$ to $atm$ as follows,

$P= 200.0 kPa×1 atm101.325 kPa= 1.97 atm$

Hence, pressure in $atm$ is $1.97 atm.$

(e)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $36 kPa.$

Concept Introduction:

Refer to part (a)

(e)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $0.36 atm.$

Explanation of Solution

Given that pressure is $36 kPa.$

Convert the unit of pressure from $kPa$ to $atm$ as follows,

$P= 36 kPa×1 atm101.325 kPa= 0.36 atm$

Hence, pressure in $atm$ is $0.36 atm.$

(e)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $600.0 kPa.$

Concept Introduction:

Refer to part (a)

(e)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $4.50×103 mmHg.$

Explanation of Solution

Given that pressure is $600.0 kPa.$

Convert the unit of pressure from $kPa$ to $mmHg$ as follows,

$P= 600.0 kPa×1 atm101.325 kPa×760 mmHg1 atm= 4.50×103 mmHg$

Hence, pressure in $mmHg$ is $4.50×103 mmHg.$

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Answer 2

Question

Chapter 8, Problem 11QRT

(a)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $mmHg$ to $atm.$

Concept Introduction:

Pressure of gas is the force applied on a unit area.

$Pressure = ForceArea$

Pressure can be expressed in different units.

General unit conversions:

$1 Pa = 1Nm−2 = 1 kgm−1s−2; 1 kPa = 103 Pa1 bar = 105 Pa = 103 kPa; mbar = 102 Pa1 atm = 1.01325×105 Pa = 101.325 kPa1 atm = 760 Torr = 760 mm Hg1 atm = 14.7 lb/in2(psi) = 1.01325 bar$

(a)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $0.158 atm.$

Explanation of Solution

Given that pressure is $120 mmHg.$

Convert the unit of pressure from $mmHg$ to $atm$ as follows,

$P= 120 mmHg ×1 atm760 mmHg= 0.158 atm$

Hence, pressure in $atm$ is $0.158 atm.$

(b)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $atm$ to $mmHg.$

Concept Introduction:

Refer to part (a)

(b)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $1.52×103 mmHg.$

Explanation of Solution

Given that pressure is $2.00 atm.$

Convert the unit of pressure from $atm$ to $mmHg$ as follows,

$P= 2.00 atm ×760 mmHg1 atm= 1.52×103 mmHg$

Hence, pressure in $mmHg$ is $1.52×103 mmHg.$

(c)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $100.0 kPa.$

Concept Introduction:

Refer to part (a)

(c)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $750.0 mmHg.$

Explanation of Solution

Given that pressure is $100.0 kPa.$

Convert the unit of pressure from $kPa$ to $mmHg$ as follows,

$P= 100.0 kPa×1 atm101.325 kPa×760 mmHg1 atm= 750.0 mmHg$

Hence, pressure in $mmHg$ is $750.0 mmHg.$

(d)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $200.0 kPa.$

Concept Introduction:

Refer to part (a)

(d)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $1.97 atm.$

Explanation of Solution

Given that pressure is $200.0 kPa.$

Convert the unit of pressure from $kPa$ to $atm$ as follows,

$P= 200.0 kPa×1 atm101.325 kPa= 1.97 atm$

Hence, pressure in $atm$ is $1.97 atm.$

(e)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $36 kPa.$

Concept Introduction:

Refer to part (a)

(e)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $0.36 atm.$

Explanation of Solution

Given that pressure is $36 kPa.$

Convert the unit of pressure from $kPa$ to $atm$ as follows,

$P= 36 kPa×1 atm101.325 kPa= 0.36 atm$

Hence, pressure in $atm$ is $0.36 atm.$

(e)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $600.0 kPa.$

Concept Introduction:

Refer to part (a)

(e)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $4.50×103 mmHg.$

Explanation of Solution

Given that pressure is $600.0 kPa.$

Convert the unit of pressure from $kPa$ to $mmHg$ as follows,

$P= 600.0 kPa×1 atm101.325 kPa×760 mmHg1 atm= 4.50×103 mmHg$

Hence, pressure in $mmHg$ is $4.50×103 mmHg.$

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Answer 3

Question

Chapter 8, Problem 11QRT

(a)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $mmHg$ to $atm.$

Concept Introduction:

Pressure of gas is the force applied on a unit area.

$Pressure = ForceArea$

Pressure can be expressed in different units.

General unit conversions:

$1 Pa = 1Nm−2 = 1 kgm−1s−2; 1 kPa = 103 Pa1 bar = 105 Pa = 103 kPa; mbar = 102 Pa1 atm = 1.01325×105 Pa = 101.325 kPa1 atm = 760 Torr = 760 mm Hg1 atm = 14.7 lb/in2(psi) = 1.01325 bar$

(a)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $0.158 atm.$

Explanation of Solution

Given that pressure is $120 mmHg.$

Convert the unit of pressure from $mmHg$ to $atm$ as follows,

$P= 120 mmHg ×1 atm760 mmHg= 0.158 atm$

Hence, pressure in $atm$ is $0.158 atm.$

(b)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $atm$ to $mmHg.$

Concept Introduction:

Refer to part (a)

(b)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $1.52×103 mmHg.$

Explanation of Solution

Given that pressure is $2.00 atm.$

Convert the unit of pressure from $atm$ to $mmHg$ as follows,

$P= 2.00 atm ×760 mmHg1 atm= 1.52×103 mmHg$

Hence, pressure in $mmHg$ is $1.52×103 mmHg.$

(c)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $100.0 kPa.$

Concept Introduction:

Refer to part (a)

(c)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $750.0 mmHg.$

Explanation of Solution

Given that pressure is $100.0 kPa.$

Convert the unit of pressure from $kPa$ to $mmHg$ as follows,

$P= 100.0 kPa×1 atm101.325 kPa×760 mmHg1 atm= 750.0 mmHg$

Hence, pressure in $mmHg$ is $750.0 mmHg.$

(d)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $200.0 kPa.$

Concept Introduction:

Refer to part (a)

(d)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $1.97 atm.$

Explanation of Solution

Given that pressure is $200.0 kPa.$

Convert the unit of pressure from $kPa$ to $atm$ as follows,

$P= 200.0 kPa×1 atm101.325 kPa= 1.97 atm$

Hence, pressure in $atm$ is $1.97 atm.$

(e)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $36 kPa.$

Concept Introduction:

Refer to part (a)

(e)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $0.36 atm.$

Explanation of Solution

Given that pressure is $36 kPa.$

Convert the unit of pressure from $kPa$ to $atm$ as follows,

$P= 36 kPa×1 atm101.325 kPa= 0.36 atm$

Hence, pressure in $atm$ is $0.36 atm.$

(e)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $600.0 kPa.$

Concept Introduction:

Refer to part (a)

(e)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $4.50×103 mmHg.$

Explanation of Solution

Given that pressure is $600.0 kPa.$

Convert the unit of pressure from $kPa$ to $mmHg$ as follows,

$P= 600.0 kPa×1 atm101.325 kPa×760 mmHg1 atm= 4.50×103 mmHg$

Hence, pressure in $mmHg$ is $4.50×103 mmHg.$

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Answer 4

Question

Chapter 8, Problem 11QRT

(a)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $mmHg$ to $atm.$

Concept Introduction:

Pressure of gas is the force applied on a unit area.

$Pressure = ForceArea$

Pressure can be expressed in different units.

General unit conversions:

$1 Pa = 1Nm−2 = 1 kgm−1s−2; 1 kPa = 103 Pa1 bar = 105 Pa = 103 kPa; mbar = 102 Pa1 atm = 1.01325×105 Pa = 101.325 kPa1 atm = 760 Torr = 760 mm Hg1 atm = 14.7 lb/in2(psi) = 1.01325 bar$

(a)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $0.158 atm.$

Explanation of Solution

Given that pressure is $120 mmHg.$

Convert the unit of pressure from $mmHg$ to $atm$ as follows,

$P= 120 mmHg ×1 atm760 mmHg= 0.158 atm$

Hence, pressure in $atm$ is $0.158 atm.$

(b)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $atm$ to $mmHg.$

Concept Introduction:

Refer to part (a)

(b)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $1.52×103 mmHg.$

Explanation of Solution

Given that pressure is $2.00 atm.$

Convert the unit of pressure from $atm$ to $mmHg$ as follows,

$P= 2.00 atm ×760 mmHg1 atm= 1.52×103 mmHg$

Hence, pressure in $mmHg$ is $1.52×103 mmHg.$

(c)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $100.0 kPa.$

Concept Introduction:

Refer to part (a)

(c)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $750.0 mmHg.$

Explanation of Solution

Given that pressure is $100.0 kPa.$

Convert the unit of pressure from $kPa$ to $mmHg$ as follows,

$P= 100.0 kPa×1 atm101.325 kPa×760 mmHg1 atm= 750.0 mmHg$

Hence, pressure in $mmHg$ is $750.0 mmHg.$

(d)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $200.0 kPa.$

Concept Introduction:

Refer to part (a)

(d)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $1.97 atm.$

Explanation of Solution

Given that pressure is $200.0 kPa.$

Convert the unit of pressure from $kPa$ to $atm$ as follows,

$P= 200.0 kPa×1 atm101.325 kPa= 1.97 atm$

Hence, pressure in $atm$ is $1.97 atm.$

(e)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $36 kPa.$

Concept Introduction:

Refer to part (a)

(e)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $0.36 atm.$

Explanation of Solution

Given that pressure is $36 kPa.$

Convert the unit of pressure from $kPa$ to $atm$ as follows,

$P= 36 kPa×1 atm101.325 kPa= 0.36 atm$

Hence, pressure in $atm$ is $0.36 atm.$

(e)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $600.0 kPa.$

Concept Introduction:

Refer to part (a)

(e)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $4.50×103 mmHg.$

Explanation of Solution

Given that pressure is $600.0 kPa.$

Convert the unit of pressure from $kPa$ to $mmHg$ as follows,

$P= 600.0 kPa×1 atm101.325 kPa×760 mmHg1 atm= 4.50×103 mmHg$

Hence, pressure in $mmHg$ is $4.50×103 mmHg.$

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Answer 5

Chapter 8, Problem 11QRT

(a)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $mmHg$ to $atm.$

Concept Introduction:

Pressure of gas is the force applied on a unit area.

$Pressure = ForceArea$

Pressure can be expressed in different units.

General unit conversions:

$1 Pa = 1Nm−2 = 1 kgm−1s−2; 1 kPa = 103 Pa1 bar = 105 Pa = 103 kPa; mbar = 102 Pa1 atm = 1.01325×105 Pa = 101.325 kPa1 atm = 760 Torr = 760 mm Hg1 atm = 14.7 lb/in2(psi) = 1.01325 bar$

(a)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $0.158 atm.$

Explanation of Solution

Given that pressure is $120 mmHg.$

Convert the unit of pressure from $mmHg$ to $atm$ as follows,

$P= 120 mmHg ×1 atm760 mmHg= 0.158 atm$

Hence, pressure in $atm$ is $0.158 atm.$

(b)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $atm$ to $mmHg.$

Concept Introduction:

Refer to part (a)

(b)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $1.52×103 mmHg.$

Explanation of Solution

Given that pressure is $2.00 atm.$

Convert the unit of pressure from $atm$ to $mmHg$ as follows,

$P= 2.00 atm ×760 mmHg1 atm= 1.52×103 mmHg$

Hence, pressure in $mmHg$ is $1.52×103 mmHg.$

(c)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $100.0 kPa.$

Concept Introduction:

Refer to part (a)

(c)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $750.0 mmHg.$

Explanation of Solution

Given that pressure is $100.0 kPa.$

Convert the unit of pressure from $kPa$ to $mmHg$ as follows,

$P= 100.0 kPa×1 atm101.325 kPa×760 mmHg1 atm= 750.0 mmHg$

Hence, pressure in $mmHg$ is $750.0 mmHg.$

(d)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $200.0 kPa.$

Concept Introduction:

Refer to part (a)

(d)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $1.97 atm.$

Explanation of Solution

Given that pressure is $200.0 kPa.$

Convert the unit of pressure from $kPa$ to $atm$ as follows,

$P= 200.0 kPa×1 atm101.325 kPa= 1.97 atm$

Hence, pressure in $atm$ is $1.97 atm.$

(e)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $36 kPa.$

Concept Introduction:

Refer to part (a)

(e)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $0.36 atm.$

Explanation of Solution

Given that pressure is $36 kPa.$

Convert the unit of pressure from $kPa$ to $atm$ as follows,

$P= 36 kPa×1 atm101.325 kPa= 0.36 atm$

Hence, pressure in $atm$ is $0.36 atm.$

(e)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $600.0 kPa.$

Concept Introduction:

Refer to part (a)

(e)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $4.50×103 mmHg.$

Explanation of Solution

Given that pressure is $600.0 kPa.$

Convert the unit of pressure from $kPa$ to $mmHg$ as follows,

$P= 600.0 kPa×1 atm101.325 kPa×760 mmHg1 atm= 4.50×103 mmHg$

Hence, pressure in $mmHg$ is $4.50×103 mmHg.$

Answer 6

Chapter 8, Problem 11QRT

(a)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $mmHg$ to $atm.$

Concept Introduction:

Pressure of gas is the force applied on a unit area.

$Pressure = ForceArea$

Pressure can be expressed in different units.

General unit conversions:

$1 Pa = 1Nm−2 = 1 kgm−1s−2; 1 kPa = 103 Pa1 bar = 105 Pa = 103 kPa; mbar = 102 Pa1 atm = 1.01325×105 Pa = 101.325 kPa1 atm = 760 Torr = 760 mm Hg1 atm = 14.7 lb/in2(psi) = 1.01325 bar$

(a)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $0.158 atm.$

Explanation of Solution

Given that pressure is $120 mmHg.$

Convert the unit of pressure from $mmHg$ to $atm$ as follows,

$P= 120 mmHg ×1 atm760 mmHg= 0.158 atm$

Hence, pressure in $atm$ is $0.158 atm.$

Answer 7

Chapter 8, Problem 11QRT

(a)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $mmHg$ to $atm.$

Concept Introduction:

Pressure of gas is the force applied on a unit area.

$Pressure = ForceArea$

Pressure can be expressed in different units.

General unit conversions:

$1 Pa = 1Nm−2 = 1 kgm−1s−2; 1 kPa = 103 Pa1 bar = 105 Pa = 103 kPa; mbar = 102 Pa1 atm = 1.01325×105 Pa = 101.325 kPa1 atm = 760 Torr = 760 mm Hg1 atm = 14.7 lb/in2(psi) = 1.01325 bar$

Answer 8

(a)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $0.158 atm.$

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given that pressure is $120 mmHg.$

Convert the unit of pressure from $mmHg$ to $atm$ as follows,

$P= 120 mmHg ×1 atm760 mmHg= 0.158 atm$

Hence, pressure in $atm$ is $0.158 atm.$

Answer 13

(b)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $atm$ to $mmHg.$

Concept Introduction:

Refer to part (a)

(b)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $1.52×103 mmHg.$

Explanation of Solution

Given that pressure is $2.00 atm.$

Convert the unit of pressure from $atm$ to $mmHg$ as follows,

$P= 2.00 atm ×760 mmHg1 atm= 1.52×103 mmHg$

Hence, pressure in $mmHg$ is $1.52×103 mmHg.$

Answer 14

(b)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $atm$ to $mmHg.$

Concept Introduction:

Refer to part (a)

Answer 15

(b)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $1.52×103 mmHg.$

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Given that pressure is $2.00 atm.$

Convert the unit of pressure from $atm$ to $mmHg$ as follows,

$P= 2.00 atm ×760 mmHg1 atm= 1.52×103 mmHg$

Hence, pressure in $mmHg$ is $1.52×103 mmHg.$

Answer 20

(c)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $100.0 kPa.$

Concept Introduction:

Refer to part (a)

(c)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $750.0 mmHg.$

Explanation of Solution

Given that pressure is $100.0 kPa.$

Convert the unit of pressure from $kPa$ to $mmHg$ as follows,

$P= 100.0 kPa×1 atm101.325 kPa×760 mmHg1 atm= 750.0 mmHg$

Hence, pressure in $mmHg$ is $750.0 mmHg.$

Answer 21

(c)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $100.0 kPa.$

Concept Introduction:

Refer to part (a)

Answer 22

(c)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $750.0 mmHg.$

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Given that pressure is $100.0 kPa.$

Convert the unit of pressure from $kPa$ to $mmHg$ as follows,

$P= 100.0 kPa×1 atm101.325 kPa×760 mmHg1 atm= 750.0 mmHg$

Hence, pressure in $mmHg$ is $750.0 mmHg.$

Answer 27

(d)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $200.0 kPa.$

Concept Introduction:

Refer to part (a)

(d)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $1.97 atm.$

Explanation of Solution

Given that pressure is $200.0 kPa.$

Convert the unit of pressure from $kPa$ to $atm$ as follows,

$P= 200.0 kPa×1 atm101.325 kPa= 1.97 atm$

Hence, pressure in $atm$ is $1.97 atm.$

Answer 28

(d)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $200.0 kPa.$

Concept Introduction:

Refer to part (a)

Answer 29

(d)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $1.97 atm.$

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Given that pressure is $200.0 kPa.$

Convert the unit of pressure from $kPa$ to $atm$ as follows,

$P= 200.0 kPa×1 atm101.325 kPa= 1.97 atm$

Hence, pressure in $atm$ is $1.97 atm.$

Answer 34

(e)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $36 kPa.$

Concept Introduction:

Refer to part (a)

(e)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $0.36 atm.$

Explanation of Solution

Given that pressure is $36 kPa.$

Convert the unit of pressure from $kPa$ to $atm$ as follows,

$P= 36 kPa×1 atm101.325 kPa= 0.36 atm$

Hence, pressure in $atm$ is $0.36 atm.$

Answer 35

(e)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $36 kPa.$

Concept Introduction:

Refer to part (a)

Answer 36

(e)

Expert Solution

Answer to Problem 11QRT

Pressure in $atm$ is $0.36 atm.$

Answer 37

(e)

Expert Solution

Answer 38

(e)

Expert Solution

Answer 39

Expert Solution

Answer 40

Explanation of Solution

Given that pressure is $36 kPa.$

Convert the unit of pressure from $kPa$ to $atm$ as follows,

$P= 36 kPa×1 atm101.325 kPa= 0.36 atm$

Hence, pressure in $atm$ is $0.36 atm.$

Answer 41

(e)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $600.0 kPa.$

Concept Introduction:

Refer to part (a)

(e)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $4.50×103 mmHg.$

Explanation of Solution

Given that pressure is $600.0 kPa.$

Convert the unit of pressure from $kPa$ to $mmHg$ as follows,

$P= 600.0 kPa×1 atm101.325 kPa×760 mmHg1 atm= 4.50×103 mmHg$

Hence, pressure in $mmHg$ is $4.50×103 mmHg.$

Answer 42

(e)

Interpretation Introduction

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $600.0 kPa.$

Concept Introduction:

Refer to part (a)

Answer 43

(e)

Expert Solution

Answer to Problem 11QRT

Pressure in $mmHg$ is $4.50×103 mmHg.$

Answer 44

(e)

Expert Solution

Answer 45

(e)

Expert Solution

Answer 46

Expert Solution

Answer 47

Explanation of Solution

Given that pressure is $600.0 kPa.$

Convert the unit of pressure from $kPa$ to $mmHg$ as follows,

$P= 600.0 kPa×1 atm101.325 kPa×760 mmHg1 atm= 4.50×103 mmHg$

Hence, pressure in $mmHg$ is $4.50×103 mmHg.$

Answer 48

Ch. 8.1 - Prob. 8.1PSP Ch. 8.1 - Prob. 8.1E Ch. 8.1 - Prob. 8.2E Ch. 8.2 - Prob. 8.3CE Ch. 8.2 - Prob. 8.4CE Ch. 8.3 - Prob. 8.6CE Ch. 8.3 - Prob. 8.2PSP Ch. 8.3 - Prob. 8.3PSP Ch. 8.3 - Prob. 8.4PSP Ch. 8.3 - Prob. 8.7CE

Concept explainers

Answer to Problem 11QRT

Explanation of Solution

Interpretation:

Unit of pressure has to be converted from $atm$ to $mmHg.$

Concept Introduction:

Refer to part (a)

Answer to Problem 11QRT

Explanation of Solution

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $100.0 kPa.$

Concept Introduction:

Refer to part (a)

Answer to Problem 11QRT

Explanation of Solution

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $200.0 kPa.$

Concept Introduction:

Refer to part (a)

Answer to Problem 11QRT

Explanation of Solution

Interpretation:

Unit of pressure has to be converted from $kPa$ to $atm$ where the given pressure is $36 kPa.$

Concept Introduction:

Refer to part (a)

Answer to Problem 11QRT

Explanation of Solution

Interpretation:

Unit of pressure has to be converted from $kPa$ to $mmHg$ where the given pressure is $600.0 kPa.$

Concept Introduction:

Refer to part (a)

Answer to Problem 11QRT

Explanation of Solution

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Chapter 8 Solutions

Concept explainers

Answer to Problem 11QRT

Explanation of Solution

Interpretation: Unit of pressure has to be converted from atm<m:math><m:mrow><m:mi>a</m:mi><m:mi>t</m:mi><m:mi>m</m:mi></m:mrow></m:math> to mmHg.<m:math><m:mrow><m:mi>m</m:mi><m:mi>m</m:mi><m:mi>H</m:mi><m:mi>g</m:mi><m:mo>.</m:mo></m:mrow></m:math> Concept Introduction: Refer to part (a)

Answer to Problem 11QRT

Explanation of Solution

Answer to Problem 11QRT

Explanation of Solution

Answer to Problem 11QRT

Explanation of Solution

Answer to Problem 11QRT

Explanation of Solution

Answer to Problem 11QRT

Explanation of Solution

Want to see more full solutions like this?

Chapter 8 Solutions

Interpretation:

Unit of pressure has to be converted from $atm$ to $mmHg.$

Concept Introduction:

Refer to part (a)