a) Interpretation: The skeletal structure of the compound given in the model is to be drawn and the stereochemistry of the double bond to be assigned as E or Z. Concept introduction: The isomer that has the higher ranked groups on each carbon on the same side of the double bond is said to have Z configuration. If the higher ranked groups are on the opposite sides, the alkene is said to have E configuration. In skeletal structures the carbon and hydrogen atoms are not usually shown. Instead carbon atoms are assumed to be at each intersection of two lines and at the end of each line. Hydrogen atoms required are fitted mentally having in mind the valence of carbon is four. Atoms other than carbon and hydrogen are shown. To draw: The skeletal structure of the compound given in the model and to assign the stereochemistry of the double bond as E or Z.

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need help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal…

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Chapter 7.SE, Problem 23VC

Interpretation Introduction

a)

Interpretation:

The skeletal structure of the compound given in the model is to be drawn and the stereochemistry of the double bond to be assigned as E or Z.

Concept introduction:

The isomer that has the higher ranked groups on each carbon on the same side of the double bond is said to have Z configuration. If the higher ranked groups are on the opposite sides, the alkene is said to have E configuration.

In skeletal structures the carbon and hydrogen atoms are not usually shown. Instead carbon atoms are assumed to be at each intersection of two lines and at the end of each line. Hydrogen atoms required are fitted mentally having in mind the valence of carbon is four. Atoms other than carbon and hydrogen are shown.

To draw:

The skeletal structure of the compound given in the model and to assign the stereochemistry of the double bond as E or Z.

Interpretation Introduction

b)

Interpretation:

The skeletal structure of the compound given in the model is to be drawn and the stereochemistry of the double bond to be assigned as E or Z.

Concept introduction:

The isomer that has the higher ranked groups on each carbon on the same side of the double bond is said to have Z configuration. If the higher ranked groups are on the opposite sides, the alkene is said to have E configuration.

In skeletal structures the carbon and hydrogen atoms are not usually shown. Instead carbon atoms are assumed to be at each intersection of two lines and at the end of each line. Hydrogen atoms required are fitted mentally having in mind the valence of carbon is four. Atoms other than carbon and hydrogen are shown.

To draw:

The skeletal structure of the compound given in the model and to assign the stereochemistry of the double bond as E or Z.

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need help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal…

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