Explanation Write the expression for specific exergy based on molar. e ¯ = ( u ¯ − u ¯ o ) + p o ( v ¯ − v ¯ o ) − T o ( s ¯ − s ¯ o ) (I) Here, specific exergy is e ¯ , specific internal energy is u ¯ , specific internal energy at atmospheric temperature is u ¯ o , atmospheric pressure is p o , specific volume is v ¯ , specific volume at atmosphere is v ¯ o , ambient temperature is T o , specific entropy is s ¯ and the specific entropy at ambient condition is s ¯ o . Write the expression for ideal gas. p v ¯ = R ¯ T v ¯ = R ¯ T p Here, the gas constant is R ¯ . Write the expression for ideal gas in ambient conditions. p o v ¯ o = R ¯ T o v ¯ o = R ¯ T o p o Write the expression for specific internal energy at a state. u ¯ = C ¯ v T Here, the specific heat at constant volume is C ¯ v . Write the expression for specific internal energy at ambient condition. u ¯ o = C ¯ v T o Write the expression for change in specific entropy. s ¯ − s ¯ o = C ¯ p ln T T o − R ¯ ln p p o Here, the specific heat at constant pressure is C ¯ p . Write the expression for specific heat at constant pressure for carbon monoxide. C ¯ p , c o = C ¯ v , c o + R ¯ C ¯ v , c o = C ¯ p , c o − R ¯ Here, the specific heat for constant pressure of carbon monoxide is C ¯ p , c o and the specific heat for constant volume of carbon monoxide is C ¯ v , c o . Write the expression for specific heat at constant pressure for neon. C ¯ p , N e = C ¯ v , N e + R ¯ C ¯ v , N e = C ¯ p , N e − R ¯ Here, the specific heat for constant pressure of neon is C ¯ p , N e and the specific heat for constant volume of neon is C ¯ v , N e . Substitute ( R ¯ T p ) for v ¯ , ( R ¯ T o p o ) for v ¯ o , C ¯ v T for u ¯ , C ¯ v T o for u ¯ o and ( C ¯ p ln T T o − R ¯ ln p p o ) for ( s − s o ) in Equation (I). e ¯ = ( C ¯ v T − C ¯ v T o ) + p o { ( R ¯ T p ) − ( R ¯ T o p o ) } − T o ( C ¯ p ln T T o − R ¯ ln p p o ) e ¯ = C ¯ v ( T − T o ) + R ¯ { ( T p o p ) − ( p o T o p o ) } − T o ( C ¯ p ln T T o − R ¯ ln p p o ) e ¯ = C ¯ v ( T − T o ) − C ¯ p T o ln T T o + R ¯ T o { ( T T o ⋅ p o p ) − 1 } + T o R ¯ ln p p o e ¯ = C ¯ v ( T − T o ) − C ¯ p T o ln T T o + R ¯ T o [ { ( T T o ⋅ p o p ) − 1 } + ln p p o ] (II) Substitute e ¯ c o for e ¯ , C ¯ v , c o for C ¯ v and C ¯ p , c o for C ¯ p in Equation (II)

Fundamentals of Engineering Thermodynamics

8th Edition

ISBN: 9781118832301

Author: SHAPIRO

Publisher: JOHN WILEY+SONS,INC.-CONSIGNMENT

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Chapter 7.7, Problem 5P

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The higher value of exergy in between carbon monoxide and neon.

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Fundamentals of Engineering Thermodynamics

Ch. 7.7 - Prob. 1E Ch. 7.7 - Prob. 2E Ch. 7.7 - Prob. 3E Ch. 7.7 - 4. A pail of water initially at 20°C freezes when...Ch. 7.7 - Prob. 5E Ch. 7.7 - Prob. 6E Ch. 7.7 - 7. After a vehicle receives an oil change and lube...Ch. 7.7 - Prob. 8E Ch. 7.7 - Prob. 9E Ch. 7.7 - Prob. 10E

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