
Concept explainers
To Solve:
√x+6=5−√x+1

Answer to Problem 25PPS
x = 3
Explanation of Solution
Given Information:
Given equation:
√x+6=5−√x+1
Concept Used :
Solve Radical equations:
- Isolate the radical on one side of the equation.
- Raise each side of the equation to a power equal to the index of the radical to eliminate the radical .
- Solve the resulting polynomial equation.Check your results.
- When solving radical equations, the result may be a number that does not satisfy the original equation . Such a number is called an extraneous solution.
Calculation:
Given √x+6=5−√x+1
√x+6=5−√x+1⇒√x+6+√x+1=5.........................................[Add √x+1 each side]⇒(√x+6+√x+1)2=52...................................[Squaring each side]⇒x+6+x+1+2√x+6⋅√x+1=25.................[Simplify]⇒2x+7+2√x2+7x+6=25⇒2√x2+7x+6=25−7−2x...........................[Subtract (7+2x) from each side]⇒(2√x2+7x+6)2=(18−2x)2.......................[Squaring each side]⇒4(x2+7x+6)=324+4x2−72x⇒4x2+28x+24=324+4x2−72x⇒28x+24=324−72x....................................[Subtract 4x2from each side]⇒100x+24=324...............................................[Add 72x each side]⇒100x = 300...................................................[Subtract 24 from each side]⇒100x100=300100.................................................[Divide each side by 100]⇒x=3Check:Substitute the value in the left hand side and right hand side of the given equation:√x+6=5−√x+1Left hand side = √x+6=√3+6=√9=3Right hand side = 5−√x+1=5−√3+1=5−√4=5−2=3Left hand side=Right hand side=3So, the solution is x=3
Check :
Chapter 7 Solutions
Algebra 2
Additional Math Textbook Solutions
Thinking Mathematically (6th Edition)
University Calculus: Early Transcendentals (4th Edition)
Elementary Statistics (13th Edition)
Algebra and Trigonometry (6th Edition)
Pre-Algebra Student Edition
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