In Problems 21–26, use the description of the region R to evaluate the indicated
23.
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- Set up the integral that represents the area of the region enclosed by the graphs y (x) = x −− √, and y (x) = - x + 6 the x axis by adding along the y axis.arrow_forward5. Evaluate the integral of 1 y¹/³ (x³ + 1) over the region which is bounded by the x axis, the line x = -y¹/3 and the line x = 3. f(x, y) =arrow_forward10. The region is bounded by y = x³, y = 2x + 4 and y = -1. Then Arearegion = [*f(x) dx + [° g(x) dx, where aarrow_forward9. Write as a single integral in the form f(x) dx. 2 5 -1 f(x) dx -3 f(x) dx - , f(x) dx f(x) dxarrow_forward3. Use the graph and the actual areas of the indicated regions to evaluate the integrals in the following problems. a. b. C. d f(x) dx = f(x) [*1x) dx = 5 'b d f(x) dx = f(x) A a B b с \y = f(x) Area A = 1 Area B = 2 Area C = 2 →x Area D = 0.6arrow_forward4. Write both the integrals from Green's theorm for F = and y = 0 for 0 ≤ x ≤ T. (3y, 4x) with the region R bounded by y = sin aarrow_forward40. Evaluate O (x2 – 2xy) dx + (2y +3)dy around the boundary of the region defined by y? = 8x and x = 2 (a ) directly, (b) by using Green's the orem. Ans. 128/5arrow_forward1. The region bounded by the graph of y = 2x and the x-axis over the interval [-3, 3] consists of two right triangles. One has area (3)(6) = 9 below the axis, and the other has area (3)(6) = 9 above the axis. Hence, 2x dx = 9 – 9 = 0 6. -3 -2 2 3arrow_forward15. Use the indicated change of variables to evaluate the double integral ||18xy ||18xy dA where R is the rectangle with vertices (0,1),(1,2),(2,1),(1,0) R 1 X = 2 1 y =- (u +v) 2arrow_forward14. Evaluate the integral: (x² + 3x)° dx A. (x* + 30)' + C 3 x* + 3x' + C C. ( + 3x) + C В. +C D.arrow_forwardCTION 5.e • Evaluate the integral ſf * ds, where f (x,y) = yсos(2лx) and the value of "C" is represented by a triangle with the following vertices: (0,1), (1,0), (0,0)arrow_forward33. The graph of f is shown. Evaluate each integral by inter- preting it in terms of areas. (a) ff(x) dx (c) ff(x) dx yk 2 0 2 (b) f(x) dx (d) ff(x) dx y=f(x) 4 6 X² 8 xarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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