In Problems 21–26, use the description of the region R to evaluate the indicated integral. 25. ∬ R e x + y d A ; R = { ( x , y ) | − x ≤ y ≤ x , 0 ≤ x ≤ 2 }
In Problems 21–26, use the description of the region R to evaluate the indicated integral. 25. ∬ R e x + y d A ; R = { ( x , y ) | − x ≤ y ≤ x , 0 ≤ x ≤ 2 }
Solution Summary: The author explains the value of the iterated integral, which is e4-52.
In Problems 21–26, use the description of the region R to evaluate the indicated integral.
25.
∬
R
e
x
+
y
d
A
;
R
=
{
(
x
,
y
)
|
−
x
≤
y
≤
x
,
0
≤
x
≤
2
}
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
Female
Male
Totals
Less than High School
Diploma
0.077
0.110
0.187
High School Diploma
0.154
0.201
0.355
Some College/University
0.141
0.129
0.270
College/University Graduate
0.092
0.096
0.188
Totals
0.464
0.536
1.000
Female
Male
Totals
Less than High School
Diploma
0.077
0.110
0.187
High School Diploma
0.154
0.201
0.355
Some College/University
0.141
0.129
0.270
College/University Graduate
0.092
0.096
0.188
Totals
0.464
0.536
1.000
Female
Male
Totals
Less than High School
Diploma
0.077
0.110
0.187
High School Diploma
0.154
0.201
0.355
Some College/University
0.141
0.129
0.270
College/University Graduate
0.092
0.096
0.188
Totals
0.464
0.536
1.000
Chapter 7 Solutions
Calculus for Business Economics Life Sciences and Social Sciences Plus NEW
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Definite Integral Calculus Examples, Integration - Basic Introduction, Practice Problems; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=rCWOdfQ3cwQ;License: Standard YouTube License, CC-BY