(a).
To find: The interval in cents when the frequency changes from
(a).
Answer to Problem 59PPS
The interval in cents when the frequency changes from
Explanation of Solution
Given information:
One octave is equal to
Calculation:
Consider the difference in cents between the two nodes with frequency a,b is:
Consider the frequency changes from 443 Hz to 415 Hz, therefore consider
Thus, the corresponding difference is cents is:
Use TI 83 calculator to find the value the screenshot is given as below
Hence,
Therefore, the interval in cents when the frequency changes from
(b).
To find: The final frequency if the interval is 55cents and the beginning frequency is
(b).
Answer to Problem 59PPS
The final frequency is
Explanation of Solution
Given information:
The interval is
The frequency is
Calculation:
Consider is the frequency changes from
Therefore, the final frequency is
Chapter 7 Solutions
Glencoe Algebra 2 Student Edition C2014
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