Program Description: Purpose of the problem is to show that position function for the spring mass system is defined by the differential equation x ″ + x = ∑ n = 0 ∞ δ ( t − 2 n π ) ; x ( 0 ) = x ′ ( 0 ) = 0 and the solution is x ( t ) = ( n + 1 ) sin t for 2 n π < t < 2 ( n + 1 ) π .

Question

Want to see the full answer?

Answer 1

Question

Chapter 7.6, Problem 22P

Program Plan Intro

Program Description: Purpose of the problem is to show that position function for the spring mass system is defined by the differential equation x″+x=∑n=0∞δ(t−2nπ);x(0)=x′(0)=0 and the solution is x(t)=(n+1)sint for 2nπ<t<2(n+1)π .

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

2. calculates the trajectory r(t) and stores the coordinates for time steps At as a nested list trajectory that contains [[xe, ye, ze], [x1, y1, z1], [x2, y2, z2], ...]. Start from time t = 0 and use a time step At = 0.01; the last data point in the trajectory should be the time when the oscillator "hits the ground", i.e., when z(t) ≤ 0; 3. stores the time for hitting the ground (i.e., the first time t when z(t) ≤ 0) in the variable t_contact and the corresponding positions in the variables x_contact, y_contact, and z_contact. Print t_contact = 1.430 X_contact = 0.755 y contact = -0.380 z_contact = (Output floating point numbers with 3 decimals using format (), e.g., "t_contact = {:.3f}" .format(t_contact).) The partial example output above is for ze = 10. 4. calculates the average x- and y-coordinates 1 y = Yi N where the x, y, are the x(t), y(t) in the trajectory and N is the number of data points that you calculated. Store the result as a list in the variable center = [x_avg, y_avg]…

A tube 1.30 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.357 m long and has a mass of 9.50 g. It is fixed at both ends and oscillates in its fundamental mode. By resonance, it sets the air column in the tube into oscillation at that column's fundamental frequency. Assume that the speed of sound in air is 343 m/s, find (a) that frequency and (b) the tension in the wire. (a) Number i 66.0 (b) Number i Units Hz Units

V Obtain the expression for y(t) which is satisfying the differential equation ÿ + 3y+ 2y = et y(0)=0 and y(0)=0

Answer 2

Question

Chapter 7.6, Problem 22P

Program Plan Intro

Program Description: Purpose of the problem is to show that position function for the spring mass system is defined by the differential equation x″+x=∑n=0∞δ(t−2nπ);x(0)=x′(0)=0 and the solution is x(t)=(n+1)sint for 2nπ<t<2(n+1)π .

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 7.6, Problem 22P

Program Plan Intro

Program Description: Purpose of the problem is to show that position function for the spring mass system is defined by the differential equation x″+x=∑n=0∞δ(t−2nπ);x(0)=x′(0)=0 and the solution is x(t)=(n+1)sint for 2nπ<t<2(n+1)π .

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 7.6, Problem 22P

Program Plan Intro

Program Description: Purpose of the problem is to show that position function for the spring mass system is defined by the differential equation x″+x=∑n=0∞δ(t−2nπ);x(0)=x′(0)=0 and the solution is x(t)=(n+1)sint for 2nπ<t<2(n+1)π .

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 7.6, Problem 22P

Program Plan Intro

Program Description: Purpose of the problem is to show that position function for the spring mass system is defined by the differential equation x″+x=∑n=0∞δ(t−2nπ);x(0)=x′(0)=0 and the solution is x(t)=(n+1)sint for 2nπ<t<2(n+1)π .

Answer 6

Chapter 7.6, Problem 22P

Program Plan Intro

Program Description: Purpose of the problem is to show that position function for the spring mass system is defined by the differential equation x″+x=∑n=0∞δ(t−2nπ);x(0)=x′(0)=0 and the solution is x(t)=(n+1)sint for 2nπ<t<2(n+1)π .

Answer 7

Chapter 7.6, Problem 22P

Program Plan Intro

Program Description: Purpose of the problem is to show that position function for the spring mass system is defined by the differential equation x″+x=∑n=0∞δ(t−2nπ);x(0)=x′(0)=0 and the solution is x(t)=(n+1)sint for 2nπ<t<2(n+1)π .

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 11

Ch. 7.1 - Apply the definition in (1) to find directly tile...Ch. 7.1 - Prob. 2P Ch. 7.1 - Prob. 3P Ch. 7.1 - Prob. 4P Ch. 7.1 - Prob. 5P Ch. 7.1 - Prob. 6P Ch. 7.1 - Prob. 7P Ch. 7.1 - Prob. 8P Ch. 7.1 - Prob. 9P Ch. 7.1 - Prob. 10P

Program Description: Purpose of the problem is to show that position function for the spring mass system is defined by the differential equation x ″ + x = ∑ n = 0 ∞ δ ( t − 2 n π ) ; x ( 0 ) = x ′ ( 0 ) = 0 and the solution is x ( t ) = ( n + 1 ) sin t for 2 n π < t < 2 ( n + 1 ) π .

Solution Summary: The author explains that the position function for the spring mass system is defined by the differential equation.

Concept explainers

Program Description: Purpose of the problem is to show that position function for the spring mass system is defined by the differential equation x″+x=∑n=0∞δ(t−2nπ);x(0)=x′(0)=0 and the solution is x(t)=(n+1)sint for 2nπ<t<2(n+1)π .

Want to see the full answer?

Chapter 7 Solutions