Chapter 7.5, Problem 47SR

To determine

Convert $\text{32 cm/s}=\_\_\_m\text{/min}$ as decimal.

Answer to Problem 47SR

  $\text{32 cm/s}=\underset{\_}{19.2}m\text{/min}$

Explanation of Solution

Given:

  $\text{32 cm/s}$

Concept Used:

  $1\text{ cm = }\frac{1}{100}\text{ m}$

And

  $1\text{ s = }\frac{1}{60}\text{ min}$

Calculation:

For $\text{32 cm/s}$

Since, $1\text{ cm = }\frac{1}{100}\text{ m}$ and $1\text{ s = }\frac{1}{60}\text{ min}$

Converting

  $\begin{array}{c}\frac{\text{32 cm}}{\text{1 s}}=\left(\frac{\text{32 cm}}{\text{1 s}}\right)\left(\frac{\text{1 m}}{\text{100 cm}}\right)\left(\frac{\text{60 s}}{\text{1 min}}\right)\\ =\left(\frac{32}{\text{1}}\right)\left(\frac{\text{1 m}}{\text{100}}\right)\left(\frac{\text{60}}{\text{1 min}}\right)\\ =\left(\frac{16}{\text{1}}\right)\left(\frac{\text{1 m}}{5}\right)\left(\frac{\text{6}}{\text{1 min}}\right)\\ =\frac{\text{96 m}}{5\text{ min}}\\ \text{=19}\text{.2 m/min}\end{array}$

Therefore, $\text{32 cm/s}=\underset{\_}{19.2}m\text{/min}$

Conclusion:

  $\text{32 cm/s}=\underset{\_}{19.2}m\text{/min}$