Introduction to Business Statistics
7th Edition
ISBN: 9781111792374
Author: WEIERS
Publisher: Cengage Learning
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Textbook Question
Chapter 7.4, Problem 7.48E
Repeat Exercise 7.46, but without using the correction for continuity (i.e., the discrete random variable,
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A researcher wishes to estimate, with 90% confidence, the population proportion of adults who support labeling
legislation for genetically modified organisms (GMOs). Her estimate must be accurate within 4% of the true proportion.
(a) No preliminary estimate is available. Find the minimum sample size needed.
(b) Find the minimum sample size needed, using a prior study that found that 65% of the respondents said they support
labeling legislation for GMOs.
(c) Compare the results from parts (a) and (b).
...
(a) What is the minimum sample size needed assuming that no prior information is available?
n =
(Round up to the nearest whole number as needed.)
The table available below shows the costs per mile (in cents) for a sample of automobiles. At a = 0.05, can you conclude that at least one mean
cost per mile is different from the others?
Click on the icon to view the data table.
Let Hss, HMS, HLS, Hsuv and Hмy represent the mean costs per mile for small sedans, medium sedans, large sedans, SUV 4WDs, and minivans
respectively. What are the hypotheses for this test?
OA. Ho: Not all the means are equal.
Ha Hss HMS HLS HSUV HMV
B. Ho Hss HMS HLS HSUV = μMV
Ha: Hss *HMS *HLS*HSUV * HMV
C. Ho Hss HMS HLS HSUV =μMV
= =
H: Not all the means are equal.
D. Ho Hss HMS
HLS HSUV HMV
Ha Hss HMS
HLS =HSUV = HMV
Question: A company launches two different marketing campaigns to promote the same product in two different regions. After one month, the company collects the sales data (in units sold) from both regions to compare the effectiveness of the campaigns.
The company wants to determine whether there is a significant difference in the mean sales between the two regions. Perform a two sample T-test
You can provide your answer by inserting a text box and the answer must include:
Null hypothesis,
Alternative hypothesis,
Show answer (output table/summary table), and
Conclusion based on the P value.
(2 points = 0.5 x 4 Answers)
Each of these is worth 0.5 points. However, showing the calculation is must. If calculation is missing, the whole answer won't get any credit.
Chapter 7 Solutions
Introduction to Business Statistics
Ch. 7.1 - What is the difference between a continuous...Ch. 7.1 - What is a probability density function and how is...Ch. 7.1 - Why is the total area beneath a probability...Ch. 7.1 - Prob. 7.4ECh. 7.2 - It has been stated that the nomal distribution is...Ch. 7.2 - Prob. 7.6ECh. 7.2 - Prob. 7.7ECh. 7.2 - Prob. 7.8ECh. 7.2 - Prob. 7.9ECh. 7.2 - The Canada Urban Transit Association has reported...
Ch. 7.2 - Prob. 7.11ECh. 7.2 - In 2009, the average charge for tax preparation by...Ch. 7.2 - It has been reported that the average hotel...Ch. 7.2 - The average American family of four spends $5000...Ch. 7.2 - Prob. 7.15ECh. 7.3 - The normal distribution is really a family of...Ch. 7.3 - In the standard normal distribution, approximately...Ch. 7.3 - A Continuous random variable, x, is normally...Ch. 7.3 - Prob. 7.19ECh. 7.3 - Prob. 7.20ECh. 7.3 - Prob. 7.21ECh. 7.3 - Prob. 7.22ECh. 7.3 - Prob. 7.23ECh. 7.3 - Prob. 7.24ECh. 7.3 - Prob. 7.25ECh. 7.3 - Prob. 7.26ECh. 7.3 - For the normal distribution described in Exercise...Ch. 7.3 - Prob. 7.28ECh. 7.3 - For the normal distribution described in Exercise...Ch. 7.3 - For the normal distribution described in Exercise...Ch. 7.3 - For the normal distribution described in Exercise...Ch. 7.3 - Prob. 7.32ECh. 7.3 - It has been reported that households in the West...Ch. 7.3 - Andre is a fearless circus performer who gets shot...Ch. 7.3 - Drying times for newly painted microwave oven...Ch. 7.3 - KleerCo supplies an under-hood, emissionscontrol...Ch. 7.3 - Prob. 7.37ECh. 7.3 - Prob. 7.38ECh. 7.4 - What is the correction for continuity and why is...Ch. 7.4 - Under what circumstances is it permissible to use...Ch. 7.4 - In a certain binomial distribution, =0.25 and n=40...Ch. 7.4 - In a certain binomial distribution, =0.30 and n=20...Ch. 7.4 - Prob. 7.43ECh. 7.4 - Prob. 7.44ECh. 7.4 - Prob. 7.45ECh. 7.4 - Prob. 7.46ECh. 7.4 - Prob. 7.47ECh. 7.4 - Repeat Exercise 7.46, but without using the...Ch. 7.5 - What is the relationship between the Poisson...Ch. 7.5 - Every day, drivers arrive at a tollbooth. If the...Ch. 7.5 - The main switchboard at the Home Shopping Network...Ch. 7.5 - A random variable is Poision distributed with =1.5...Ch. 7.5 - A random variable is Poision distributed with...Ch. 7.5 - A random variable is Poision distributed with...Ch. 7.5 - The owner of a self-service carwash has found that...Ch. 7.5 - A taxi dispatcher has found that successive calls...Ch. 7.5 - During 2008, U.S. general aviation pilots had 1.20...Ch. 7.5 - The Bureau of Labor Statistics reports the...Ch. 7.6 - A computer statistical package has simulated 1000...Ch. 7.6 - Prob. 7.60ECh. 7.6 - Prob. 7.61ECh. 7.6 - Prob. 7.62ECh. 7 - According to a recent survey, 35% of the adult...Ch. 7 - Prob. 7.64CECh. 7 - Prob. 7.65CECh. 7 - During an annual heating season, the average gas...Ch. 7 - It has been reported that the average monthly cell...Ch. 7 - During 2004, the average number of flying hours...Ch. 7 - During fiscal 2008, the average daily volume for...Ch. 7 - For itemized tax returns in the $60,000—$75,000...Ch. 7 - Of the 1.0 million persons of voting age in Maine,...Ch. 7 - A public relations agency tells its client that...Ch. 7 - Given the results of Exercise 7.72, evaluate the...Ch. 7 - A researcher is studying a particular process and...Ch. 7 - A safety researcher has found that fourth to sixth...Ch. 7 - The number of defects in rolls of aluminum sheet...Ch. 7 - The mileage death rate for motorcycle riders has...Ch. 7 - The “20-ounce” package of mozzarella cheese...Ch. 7 - State Police Academy graduates from a large gradua...Ch. 7 - The trainer for a professional football team has...Ch. 7 - The precooked weight of hamburgers at a gourmet...Ch. 7 - Boxes are filled with sugar by a machine that is...Ch. 7 - In Exercise 7.82, the company would like to put in...Ch. 7 - Discount Micros, a computer mail-order company,...Ch. 7 - The U-Drive car rental corporation has found that...Ch. 7 - Ronnie Rogers, the customer relations manager for...Ch. 7 - A storage warehouse in a relatively remote part of...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- Binomial Prob. Question: A new teaching method claims to improve student engagement. A survey reveals that 60% of students find this method engaging. If 15 students are randomly selected, what is the probability that: a) Exactly 9 students find the method engaging?b) At least 7 students find the method engaging? (2 points = 1 x 2 answers) Provide answers in the yellow cellsarrow_forwardIn a survey of 2273 adults, 739 say they believe in UFOS. Construct a 95% confidence interval for the population proportion of adults who believe in UFOs. A 95% confidence interval for the population proportion is ( ☐, ☐ ). (Round to three decimal places as needed.)arrow_forwardFind the minimum sample size n needed to estimate μ for the given values of c, σ, and E. C=0.98, σ 6.7, and E = 2 Assume that a preliminary sample has at least 30 members. n = (Round up to the nearest whole number.)arrow_forward
- In a survey of 2193 adults in a recent year, 1233 say they have made a New Year's resolution. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. The 90% confidence interval for the population proportion p is (Round to three decimal places as needed.) J.D) .arrow_forwardLet p be the population proportion for the following condition. Find the point estimates for p and q. In a survey of 1143 adults from country A, 317 said that they were not confident that the food they eat in country A is safe. The point estimate for p, p, is (Round to three decimal places as needed.) ...arrow_forward(c) Because logistic regression predicts probabilities of outcomes, observations used to build a logistic regression model need not be independent. A. false: all observations must be independent B. true C. false: only observations with the same outcome need to be independent I ANSWERED: A. false: all observations must be independent. (This was marked wrong but I have no idea why. Isn't this a basic assumption of logistic regression)arrow_forward
- Business discussarrow_forwardSpam filters are built on principles similar to those used in logistic regression. We fit a probability that each message is spam or not spam. We have several variables for each email. Here are a few: to_multiple=1 if there are multiple recipients, winner=1 if the word 'winner' appears in the subject line, format=1 if the email is poorly formatted, re_subj=1 if "re" appears in the subject line. A logistic model was fit to a dataset with the following output: Estimate SE Z Pr(>|Z|) (Intercept) -0.8161 0.086 -9.4895 0 to_multiple -2.5651 0.3052 -8.4047 0 winner 1.5801 0.3156 5.0067 0 format -0.1528 0.1136 -1.3451 0.1786 re_subj -2.8401 0.363 -7.824 0 (a) Write down the model using the coefficients from the model fit.log_odds(spam) = -0.8161 + -2.5651 + to_multiple + 1.5801 winner + -0.1528 format + -2.8401 re_subj(b) Suppose we have an observation where to_multiple=0, winner=1, format=0, and re_subj=0. What is the predicted probability that this message is spam?…arrow_forwardConsider an event X comprised of three outcomes whose probabilities are 9/18, 1/18,and 6/18. Compute the probability of the complement of the event. Question content area bottom Part 1 A.1/2 B.2/18 C.16/18 D.16/3arrow_forward
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