PRECALCULUS:...COMMON CORE ED.-W/ACCESS
10th Edition
ISBN: 9780134781839
Author: Demana
Publisher: PEARSON
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Expert Solution & Answer
Chapter 7.4, Problem 3QR
Solution
To calculate: The x and y intercept of a line x20+y50=1 and also draw its graph.
The intercept point are (20,0); (0,50) .
Given Information:
The equation of a line is x20+y50=1 .
Calculation:
Consider the equation of line.
The x -intercept of a line is in the form of (a,0) . To obtain the x -intercept of a line, put y=0 in the given equation of a line and solve for x .
x20+050=1x20=1
Now, multiply both the sides of the obtained equation by 20.
20(x20)=20(1)x=20
The x -intercept of a line is (20,0) .
The y -intercept of a line is in the form of (0,b) . To obtain the y -intercept of a line, put x=0 in the given equation of a line and solve for y .
020+y50=1y50=1
Now, multiply both the sides of the obtained equation by 50.
50(y50)=50(1)y=50
The y -intercept of a line is (0,50) .
Draw the graph of a line x20+y50=1 .
Chapter 7 Solutions
PRECALCULUS:...COMMON CORE ED.-W/ACCESS
Ch. 7.1 - Prob. 1QRCh. 7.1 - Prob. 2QRCh. 7.1 - Prob. 3QRCh. 7.1 - Prob. 4QRCh. 7.1 - Prob. 5QRCh. 7.1 - Prob. 6QRCh. 7.1 - Prob. 7QRCh. 7.1 - Prob. 8QRCh. 7.1 - Prob. 9QRCh. 7.1 - Prob. 10QR
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