Chapter 7.4, Problem 31PPE

To determine

To find: the density of deer population when the data from a deer count in a forested area show

that an estimated $3.16\times {10}^3$ deer inhabit $7.228\times {10}^4$ acres of land.

Answer to Problem 31PPE

The required answer is: density of deer population is 4.37 per acre of land

Explanation of Solution

Given information:

The given information: $3.16\times {10}^3$ deer inhabit $7.228\times {10}^4$ acres of land

Calculation:

  $\frac{3.16\times {10}^3}{7.228\times {10}^4}=\frac{3.16}{7.228}\times {10}^{3-4}$

(Subtract exponents when dividing powers with the same base)

  $\begin{array}{l}=\frac{3.16}{7.228}\times {10}^{-1}\\ =0.437\times {10}^{-1}\end{array}$

(Divide and round to the nearest thousandth)

  $=0.437\times \frac{1}{{10}^1}$

(Rewrite using positive exponents)

  $\begin{array}{l}=\frac{0.437}{10}\\ =4.37\end{array}$

(Simplify)

The density of deer population is 4.37 per acre of land