Chapter 7.1, Problem 70PPE

To determine

To simplify: The expression $\frac{2x^{-5}{y}^3}{n^2}÷\frac{r^2{y}^5}{2n}$ .

Answer to Problem 70PPE

The simplified form of the expression $\frac{2x^{-5}{y}^3}{n^2}÷\frac{r^2{y}^5}{2n}$ is .

Explanation of Solution

Given information:

The given expression is $\frac{2x^{-5}{y}^3}{n^2}÷\frac{r^2{y}^5}{2n}$ .

Calculation:

Simplify the expression.

  $\begin{array}{c}\frac{2x^{-5}{y}^3}{n^2}÷\frac{r^2{y}^5}{2n}=\frac{2x^{-5}{y}^3}{n^2}\times \frac{2n}{r^2{y}^5}\\ =\frac{2x^{-5}\times 2}{n{r}^2{y}^2}\\ =\frac{4}{n{r}^2{y}^2{x}^5}\end{array}$

Hence, the simplified form of the expression $\frac{2x^{-5}{y}^3}{n^2}÷\frac{r^2{y}^5}{2n}$ is $\frac{4}{n{r}^2{y}^2{x}^5}$ .

Conclusion:

Therefore, the simplified form of the expression $\frac{2x^{-5}{y}^3}{n^2}÷\frac{r^2{y}^5}{2n}$ is $\frac{4}{n{r}^2{y}^2{x}^5}$ .