Chapter 7.4, Problem 2P

To determine

To find: during one year, Honduras had a population of $7.33\times {10}^6$ people. The area of Honduras

is $4.33\times {10}^{4}m{i}^2$ . What was the population density of Honduras that year?

Answer to Problem 2P

The required answer is: population density is about $169.3$ people per square mile

Explanation of Solution

Given information:

The given information: Honduras population is $7.33\times {10}^6$ and area is $4.33\times {10}^{4}m{i}^2$

Calculation:

  $\frac{7.33\times {10}^6}{4.33\times {10}^4}=\frac{7.33}{4.33}\times {10}^{6-4}$

(Subtract exponents when dividing powers with the same base)

  $\begin{array}{l}=\frac{7.33}{4.33}\times {10}^2\\ =1.693\times {10}^2\end{array}$

(Divide and round to the nearest thousandth)

  $\begin{array}{l}=1.693\times 100\\ =169.3\end{array}$

(Simplify)

The population density of Honduras was about $169.3$ people per square mile.