MECHANICS OF MATERIALS
11th Edition
ISBN: 9780137605521
Author: HIBBELER
Publisher: RENT PEARS
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Chapter 7.2, Problem 8P
The shaft is supported by a thrust bearing at A and a journal bearing at B. If the shaft is made from a material having an allowable shear stress of τallow=75 MPa, determine the maximum value for P.
Probs. 7–7/8
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Determine the smallest allowable diameter of the shaft which is subjected to the concentrated forces. The journal bearing at A and B only support vertical forces. The allowable bending stress is σallow= 160 MPa
Bearing A only receives forces in the radial direction of the bearing. Bearing B is a steering bearing and also carries longitudinal loads on the shaft.
F1= 10kN F2=23 kN
L1=420 mm L2= 310mm L3=540mm
The shaft is supported by a thrust bearing at A and a journal bearing at B. If P = 20 kN, determine the absolute maximum shear stress in the shaft.
Determine the smallest allowable diameter of the shaft which is subjected to the concentrated forces. The journal bearing at A and B only support vertical forces. The allowable bending stress is σallow= 160 MPa
F1= 10kN F2=18kN
L1=500 mm L2= 400mm L3=590mm
Chapter 7 Solutions
MECHANICS OF MATERIALS
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- 7-1. The shaft is supported by a smooth thrust bearing at B and a journal bearing at C. Determine the resultant internal loadings acting on the cross section at E. 1800 N 3600 Narrow_forwardThe solid aluminum shaft has a diameter of 50 mm and allowable shear stress of tallow = 60 MPa. Determine the largest torque T1 that can be applied to the shaft if it is also subjected to the other torsional loadings. It is requiredthat T1 act in the direction shown. Also, determine the maximum shear stress within regions CD and DE. 5–7. The solid aluminum shaft has a diameter of 50arrow_forwardThe plastic hexagonal tube is subjected to a torque of 150 N # m. Determine the mean dimension a of its sides if the allowable shear stress is tallow = 60 MPa. Each side has a thickness of t = 3 mm.arrow_forward
- The shaft is made of red brass C83400 and has an elliptical cross section. If it is subjected to the torsional loading, determine the maximum shear stress within regions AC and BC, and the angle of twist f of end B relative to end A.arrow_forwardThe shaft has an outer diameter of 100 mm and an inner diameter of 80 mm. If it is subjected to the three torques, plot the shear stress distribution along a radial line for the cross section within region CD of the shaft. The smooth bearings at A and B do not resist torque.arrow_forwardDetermine the absolute maximum bending stress in the 80-mm-diameter shaft which is subjected to the concentrated forces. There is a journal bearing at A and a thrust bearing at B.arrow_forward
- The shaft is made from a solid steel section AB and a tubular portion made of steel and having a brass core. If it is fixed to a rigid support at A, and a torque of T = 50 lb.ft is applied to it at C, determine the rotation angle that occurs at C relative to A and compute the maximum shear stress and maximum shear strain in the brass and steel. Take Gst = 11500 ksi, Gbr = 5600 Ksi. 3 ft 0.5 in. B 1 in. T = 50 lb•ftarrow_forward2. The solid shaft has a diameter of 0.75 in. If it is subjected to the torques shown, determine the maximum shear stress developed in regions CD and EF of the shaft. The bearings at A and F allow free rotation of the (ANS: point A: 6.04 MPa, point B: 6.04 MPa) shaft. J. -12 (0.75)² = 0.0129 11 B A 25 lb-ft 40 lb-ft 20 lb-ft 35 lb-ftarrow_forwardThe steel shaft is formed by attaching a hollow shaft to a solid shaft. Determine the shear stress (in Pa) in the hollow shaft using the maximum torque T that can be applied to the ends of the shaft without exceeding a shear stress of 70066350 Pa and angle of twist of 2.5° for the whole shaft. Use 6 = 83000000000 Pafor the shaft, x = 2.25 m, and y = 1.63 m. Round off the final answer to two decimal places. T 100 mm 70 mm 70 mm yarrow_forward
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