Pre-Algebra

1st Edition

ISBN: 9780618800766

Author: Ron Larson, Lee Stiff, Laurie Boswell, Timothy Kanold

Publisher: Houghton Mifflin-High School

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Question

Chapter 7.2, Problem 25E

To determine

The percentage of Spaniel dogs that competed.

The percentage of Sheepdog dogs that competed.

Expert Solution

Answer to Problem 25E

The percentage of Spaniel dogs that competed = $20%$

The percentage of Sheepdog dogs that competed = $62.5%$

Explanation of Solution

Given:

In a dog agility competition, dogs are tested in their ability to get pass obstacles.

The table given in the question:

Pre-Algebra, Chapter 7.2, Problem 25E , additional homework tip 1

Calculation:

As per the problem

Consider the table,

Pre-Algebra, Chapter 7.2, Problem 25E , additional homework tip 2

Number of Sheepdogs that competed= $75$

Number of Spaniel dogs that competed= $24$

Number of terrierdogs that competed= $14$

Number of other breeddogs that competed= $7$

Total number of dogs that competed = $75+24+14+7=120$

Percent of Spaniel dogs that competed= $number of Spaniel dogstotal number of dogs×100$ $=24120×100=20%.$ [Put the values and simplify]

Percent of Sheepdogs that competed $= number of Sheepdog dogstotal number of dogs×100$ $=75120×100=62.5%.$ [Put the values and simplify]

Hence,

The percentage of Spaniel dogs that competed = $20%$

The percentage of Sheepdogs that competed = $62.5%$

Conclusion:

The percentage of Spaniel dogs that competed = $20%$

The percentage of Sheepdogs that competed = $62.5%$

To determine

The percent of the sheepdogs that finished in the top half.

Expert Solution

Answer to Problem 25E

$56% of sheepdogs finished in the top 60.$

Explanation of Solution

Given:

Number of Sheepdogs that competed= $75$

Total number of dogs that competed = $120$

$70% of the dogs that finished in the top half are sheepdogs.$

Calculation:

As per the given problem

Number of Sheepdogs that competed= $75$

Total number of dogs that competed = $120$

Among the top $60$ , $70% are sheepdogs$ , that is , $70% of 60 are sheepdogs$ .

Therefore,

$70% of 60=70100⋅60=42$ [Write the percentage in fraction form and simplify]

Therefore,

$42 sheepdogs finished in the top 60.$

Percent of sheepdogs that finished in the top half $= number of Sheepdogs in the top halftotal number of sheepdogs×100$ $=4275×100=56%.$ [Put the values and simplify]

Conclusion:

$56% of sheepdogs finished in the top 60.$

Chapter 7.2, Problem 24E

Chapter 7.2, Problem 26E

Chapter 7 Solutions

Pre-Algebra

Ch. 7.1 - Prob. 1C Ch. 7.1 - Prob. 2C Ch. 7.1 - Prob. 3C Ch. 7.1 - Prob. 4C Ch. 7.1 - Prob. 5C Ch. 7.1 - Prob. 6C Ch. 7.1 - Prob. 7C Ch. 7.1 - Prob. 8C Ch. 7.1 - Prob. 9C Ch. 7.1 - Prob. 1E

Ch. 7.1 - Prob. 2E Ch. 7.1 - Prob. 3E Ch. 7.1 - Prob. 4E Ch. 7.1 - Prob. 5E Ch. 7.1 - Prob. 6E Ch. 7.1 - Prob. 7E Ch. 7.1 - Prob. 8E Ch. 7.1 - Prob. 9E Ch. 7.1 - Prob. 10E Ch. 7.1 - Prob. 11E Ch. 7.1 - Prob. 12E Ch. 7.1 - Prob. 13E Ch. 7.1 - Prob. 14E Ch. 7.1 - Prob. 15E Ch. 7.1 - Prob. 16E Ch. 7.1 - Prob. 17E Ch. 7.1 - Prob. 18E Ch. 7.1 - Prob. 19E Ch. 7.1 - Prob. 20E Ch. 7.1 - Prob. 21E Ch. 7.1 - Prob. 22E Ch. 7.1 - Prob. 23E Ch. 7.1 - Prob. 24E Ch. 7.1 - Prob. 25E Ch. 7.1 - Prob. 26E Ch. 7.1 - Prob. 27E Ch. 7.1 - Prob. 28E Ch. 7.1 - Prob. 29E Ch. 7.1 - Prob. 30E Ch. 7.1 - Prob. 31E Ch. 7.1 - Prob. 32E Ch. 7.1 - Prob. 33E Ch. 7.1 - Prob. 34E Ch. 7.1 - Prob. 35E Ch. 7.1 - Prob. 36E Ch. 7.1 - Prob. 37E Ch. 7.1 - Prob. 38E Ch. 7.1 - Prob. 39E Ch. 7.1 - Prob. 40E Ch. 7.1 - Prob. 41E Ch. 7.1 - Prob. 42E Ch. 7.1 - Prob. 43E Ch. 7.1 - Prob. 44E Ch. 7.1 - Prob. 45E Ch. 7.1 - Prob. 46E Ch. 7.1 - Prob. 47E Ch. 7.1 - Prob. 48E Ch. 7.1 - Prob. 49E Ch. 7.1 - Prob. 50E Ch. 7.1 - Prob. 51E Ch. 7.1 - 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