To Prove: ABCD is a rectangle.
Given information:
Proof: Here, EF is median to AC
So that, AF=FC
And,
Hence, DC=AB (sides opposite to equal angles are equal)
And,
So, FD=FC
AF=FC
So that, AF=FD=FC
So that, here diagonals bisect at same point.
Hence, AD=BC and AB=CD
So that, ABCD is a rectangle.
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