Explanation Given: P R = P S ; R V → Bisects ∠ P R S and S V → Bisects ∠ P S T Calculation :- Let m ∠ P = 4 x ∠ P S T = ∠ P + ∠ P R S = 4 x + 2 a ∠ V S T = ∠ V + ∠ V R S ∠ V = 2 x + a − a = 2 x This means m ∠ V = 1 2 ( m ∠ P )

91st Edition

ISBN: 9780866099653

Author: Richard Rhoad, George Milauskas, Robert Whipple

Publisher: McDougal Littell

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Question

Chapter 7, Problem 27RP

To determine

To prove that m∠V=12(m∠P)

Expert Solution & Answer

Explanation of Solution

Given:

PR=PS;RV→ Bisects ∠PRS and SV→ Bisects ∠PST

Geometry For Enjoyment And Challenge, Chapter 7, Problem 27RP

Calculation:-

Let m∠P=4x

∠PST=∠P+∠PRS=4x+2a∠VST=∠V+∠VRS∠V=2x+a−a=2x

This means m∠V=12(m∠P)

Chapter 7, Problem 26RP

Chapter 7, Problem 28RP

Chapter 7 Solutions

Geometry For Enjoyment And Challenge

Ch. 7.1 - Prob. 1PSA Ch. 7.1 - Prob. 2PSA Ch. 7.1 - Prob. 3PSA Ch. 7.1 - Prob. 4PSA Ch. 7.1 - Prob. 5PSA Ch. 7.1 - Prob. 6PSA Ch. 7.1 - Prob. 7PSA Ch. 7.1 - Prob. 8PSA Ch. 7.1 - Prob. 9PSA Ch. 7.1 - Prob. 10PSA

Ch. 7.1 - Prob. 11PSA Ch. 7.1 - Prob. 12PSB Ch. 7.1 - Prob. 13PSB Ch. 7.1 - Prob. 14PSB Ch. 7.1 - Prob. 15PSB Ch. 7.1 - Prob. 16PSB Ch. 7.1 - Prob. 17PSB Ch. 7.1 - Prob. 18PSB Ch. 7.1 - Prob. 19PSC Ch. 7.1 - Prob. 20PSC Ch. 7.1 - Prob. 21PSC Ch. 7.1 - Prob. 22PSC Ch. 7.1 - Prob. 23PSC Ch. 7.2 - Prob. 1PSA Ch. 7.2 - Prob. 2PSA Ch. 7.2 - Prob. 3PSA Ch. 7.2 - Prob. 4PSA Ch. 7.2 - Prob. 5PSA Ch. 7.2 - Prob. 6PSA Ch. 7.2 - Prob. 7PSA Ch. 7.2 - Prob. 8PSA Ch. 7.2 - Prob. 9PSA Ch. 7.2 - Prob. 10PSA Ch. 7.2 - Prob. 11PSB Ch. 7.2 - Prob. 12PSB Ch. 7.2 - Prob. 13PSB Ch. 7.2 - Prob. 14PSB Ch. 7.2 - Prob. 15PSB Ch. 7.2 - Prob. 16PSB Ch. 7.2 - Prob. 17PSC Ch. 7.2 - Prob. 18PSC Ch. 7.2 - Prob. 19PSC Ch. 7.2 - Prob. 20PSD Ch. 7.3 - Prob. 1PSA Ch. 7.3 - Prob. 2PSA Ch. 7.3 - Prob. 3PSA Ch. 7.3 - Prob. 4PSA Ch. 7.3 - Prob. 5PSA Ch. 7.3 - Prob. 6PSA Ch. 7.3 - Prob. 7PSA Ch. 7.3 - Prob. 8PSB Ch. 7.3 - Prob. 9PSB Ch. 7.3 - Prob. 10PSB Ch. 7.3 - Prob. 11PSB Ch. 7.3 - Prob. 12PSB Ch. 7.3 - Prob. 13PSB Ch. 7.3 - Prob. 14PSB Ch. 7.3 - Prob. 15PSB Ch. 7.3 - Prob. 16PSB Ch. 7.3 - Prob. 17PSB Ch. 7.3 - Prob. 18PSB Ch. 7.3 - Prob. 19PSB Ch. 7.3 - Prob. 20PSC Ch. 7.3 - Prob. 21PSC Ch. 7.3 - Prob. 22PSC Ch. 7.3 - Prob. 23PSC Ch. 7.3 - Prob. 24PSD Ch. 7.4 - Prob. 1PSA Ch. 7.4 - Prob. 2PSA Ch. 7.4 - Prob. 3PSA Ch. 7.4 - Prob. 4PSA Ch. 7.4 - Prob. 5PSA Ch. 7.4 - Prob. 6PSA Ch. 7.4 - Prob. 7PSA Ch. 7.4 - Prob. 8PSB Ch. 7.4 - Prob. 9PSB Ch. 7.4 - Prob. 10PSB Ch. 7.4 - Prob. 11PSB Ch. 7.4 - Prob. 12PSB Ch. 7.4 - Prob. 13PSB Ch. 7.4 - Prob. 14PSC Ch. 7.4 - Prob. 15PSC Ch. 7.4 - Prob. 16PSC Ch. 7.4 - Prob. 17PSC Ch. 7 - Prob. 1RP Ch. 7 - Prob. 2RP Ch. 7 - Prob. 3RP Ch. 7 - Prob. 4RP Ch. 7 - Prob. 5RP Ch. 7 - Prob. 6RP Ch. 7 - Prob. 7RP Ch. 7 - Prob. 8RP Ch. 7 - Prob. 9RP Ch. 7 - Prob. 10RP Ch. 7 - Prob. 11RP Ch. 7 - Prob. 12RP Ch. 7 - Prob. 13RP Ch. 7 - Prob. 14RP Ch. 7 - Prob. 15RP Ch. 7 - Prob. 16RP Ch. 7 - Prob. 17RP Ch. 7 - Prob. 18RP Ch. 7 - Prob. 19RP Ch. 7 - Prob. 20RP Ch. 7 - Prob. 21RP Ch. 7 - Prob. 22RP Ch. 7 - Prob. 23RP Ch. 7 - Prob. 24RP Ch. 7 - Prob. 25RP Ch. 7 - Prob. 26RP Ch. 7 - Prob. 27RP Ch. 7 - Prob. 28RP Ch. 7 - Prob. 29RP Ch. 7 - Prob. 30RP

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To prove that m ∠ V = 1 2 ( m ∠ P )

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To prove that m∠V=12(m∠P)

Explanation of Solution

Chapter 7 Solutions

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