Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
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Question
Chapter 7, Problem 29RP
To determine
To find the area of the
Expert Solution & Answer
Answer to Problem 29RP
Explanation of Solution
Given:
The square has the vertices
Calculation:
The following will be the figure after rotating the square
The area is
Chapter 7 Solutions
Geometry For Enjoyment And Challenge
Ch. 7.1 - Prob. 1PSACh. 7.1 - Prob. 2PSACh. 7.1 - Prob. 3PSACh. 7.1 - Prob. 4PSACh. 7.1 - Prob. 5PSACh. 7.1 - Prob. 6PSACh. 7.1 - Prob. 7PSACh. 7.1 - Prob. 8PSACh. 7.1 - Prob. 9PSACh. 7.1 - Prob. 10PSA
Ch. 7.1 - Prob. 11PSACh. 7.1 - Prob. 12PSBCh. 7.1 - Prob. 13PSBCh. 7.1 - Prob. 14PSBCh. 7.1 - Prob. 15PSBCh. 7.1 - Prob. 16PSBCh. 7.1 - Prob. 17PSBCh. 7.1 - Prob. 18PSBCh. 7.1 - Prob. 19PSCCh. 7.1 - Prob. 20PSCCh. 7.1 - Prob. 21PSCCh. 7.1 - Prob. 22PSCCh. 7.1 - Prob. 23PSCCh. 7.2 - Prob. 1PSACh. 7.2 - Prob. 2PSACh. 7.2 - Prob. 3PSACh. 7.2 - Prob. 4PSACh. 7.2 - Prob. 5PSACh. 7.2 - Prob. 6PSACh. 7.2 - Prob. 7PSACh. 7.2 - Prob. 8PSACh. 7.2 - Prob. 9PSACh. 7.2 - Prob. 10PSACh. 7.2 - Prob. 11PSBCh. 7.2 - Prob. 12PSBCh. 7.2 - Prob. 13PSBCh. 7.2 - Prob. 14PSBCh. 7.2 - Prob. 15PSBCh. 7.2 - Prob. 16PSBCh. 7.2 - Prob. 17PSCCh. 7.2 - Prob. 18PSCCh. 7.2 - Prob. 19PSCCh. 7.2 - Prob. 20PSDCh. 7.3 - Prob. 1PSACh. 7.3 - Prob. 2PSACh. 7.3 - Prob. 3PSACh. 7.3 - Prob. 4PSACh. 7.3 - Prob. 5PSACh. 7.3 - Prob. 6PSACh. 7.3 - Prob. 7PSACh. 7.3 - Prob. 8PSBCh. 7.3 - Prob. 9PSBCh. 7.3 - Prob. 10PSBCh. 7.3 - Prob. 11PSBCh. 7.3 - Prob. 12PSBCh. 7.3 - Prob. 13PSBCh. 7.3 - Prob. 14PSBCh. 7.3 - Prob. 15PSBCh. 7.3 - Prob. 16PSBCh. 7.3 - Prob. 17PSBCh. 7.3 - Prob. 18PSBCh. 7.3 - Prob. 19PSBCh. 7.3 - Prob. 20PSCCh. 7.3 - Prob. 21PSCCh. 7.3 - Prob. 22PSCCh. 7.3 - Prob. 23PSCCh. 7.3 - Prob. 24PSDCh. 7.4 - Prob. 1PSACh. 7.4 - Prob. 2PSACh. 7.4 - Prob. 3PSACh. 7.4 - Prob. 4PSACh. 7.4 - Prob. 5PSACh. 7.4 - Prob. 6PSACh. 7.4 - Prob. 7PSACh. 7.4 - Prob. 8PSBCh. 7.4 - Prob. 9PSBCh. 7.4 - Prob. 10PSBCh. 7.4 - Prob. 11PSBCh. 7.4 - Prob. 12PSBCh. 7.4 - Prob. 13PSBCh. 7.4 - Prob. 14PSCCh. 7.4 - Prob. 15PSCCh. 7.4 - Prob. 16PSCCh. 7.4 - Prob. 17PSCCh. 7 - Prob. 1RPCh. 7 - Prob. 2RPCh. 7 - Prob. 3RPCh. 7 - Prob. 4RPCh. 7 - Prob. 5RPCh. 7 - Prob. 6RPCh. 7 - Prob. 7RPCh. 7 - Prob. 8RPCh. 7 - Prob. 9RPCh. 7 - Prob. 10RPCh. 7 - Prob. 11RPCh. 7 - Prob. 12RPCh. 7 - Prob. 13RPCh. 7 - Prob. 14RPCh. 7 - Prob. 15RPCh. 7 - Prob. 16RPCh. 7 - Prob. 17RPCh. 7 - Prob. 18RPCh. 7 - Prob. 19RPCh. 7 - Prob. 20RPCh. 7 - Prob. 21RPCh. 7 - Prob. 22RPCh. 7 - Prob. 23RPCh. 7 - Prob. 24RPCh. 7 - Prob. 25RPCh. 7 - Prob. 26RPCh. 7 - Prob. 27RPCh. 7 - Prob. 28RPCh. 7 - Prob. 29RPCh. 7 - Prob. 30RP
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- Task number: A1.1, A1.7 Topic: Celestial Navigation, Compass - Magnetic and Gyro Activ Determine compass error (magnetic and gyro) using azimuth choosing a suitable celestial body (Sun/ Stars/ Planets/ Moon). Apply variation to find the deviation of the magnetic compass. Minimum number of times that activity should be recorded: 6 (2 each phase) Sample calculation (Azimuth- Planets): On 06th May 2006 at 22h20m 10s UTC, a vessel in position 48°00'N 050°00'E observed Mars bearing 327° by compass. Find the compass error. If variation was 4.0° East, calculate the deviation. GHA Mars (06d 22h): Increment (20m 10s): 089° 55.7' 005° 02.5' v (0.9): (+) 00.3' GHA Mars: 094° 58.5' Longitude (E): (+) 050° 00.0' (plus- since longitude is easterly) LHA Mars: 144° 58.5' Declination (06d 22h): d (0.2): N 024° 18.6' (-) 00.1' Declination Mars: N 024° 18.5' P=144° 58.5' (If LHA<180°, P=LHA) A Tan Latitude/ Tan P A Tan 48° 00' Tan 144° 58.5' A = 1.584646985 N (A is named opposite to latitude, except when…arrow_forwardTask number: A1.1, A1.7 Topic: Celestial Navigation, Compass - Magnetic and Gyro Activ Determine compass error (magnetic and gyro) using azimuth choosing a suitable celestial body (Sun/ Stars/ Planets/ Moon). Apply variation to find the deviation of the magnetic compass. Minimum number of times that activity should be recorded: 6 (2 each phase) Sample calculation (Azimuth- Planets): On 06th May 2006 at 22h20m 10s UTC, a vessel in position 48°00'N 050°00'E observed Mars bearing 327° by compass. Find the compass error. If variation was 4.0° East, calculate the deviation. GHA Mars (06d 22h): Increment (20m 10s): 089° 55.7' 005° 02.5' v (0.9): (+) 00.3' GHA Mars: 094° 58.5' Longitude (E): (+) 050° 00.0' (plus- since longitude is easterly) LHA Mars: 144° 58.5' Declination (06d 22h): d (0.2): N 024° 18.6' (-) 00.1' Declination Mars: N 024° 18.5' P=144° 58.5' (If LHA<180°, P=LHA) A Tan Latitude/ Tan P A Tan 48° 00' Tan 144° 58.5' A = 1.584646985 N (A is named opposite to latitude, except when…arrow_forwardA: Tan Latitude / Tan P A = Tan 04° 30'/ Tan 77° 50.3' A= 0.016960 803 S CA named opposite to latitude, except when hour angle between 090° and 270°) B: Tan Declination | Sin P B Tan 052° 42.1'/ Sin 77° 50.3' B = 1.34 2905601 SCB is alway named same as declination) C = A + B = 1.35 9866404 S CC correction, A+/- B: if A and B have same name - add, If different name- subtract) = Tan Azimuth 1/Ccx cos Latitude) Tan Azimuth = 0.737640253 Azimuth = S 36.4° E CAzimuth takes combined name of C correction and Hour Angle - If LHA is between 0° and 180°, it is named "west", if LHA is between 180° and 360° it is named "east" True Azimuth= 143.6° Compass Azimuth = 145.0° Compass Error = 1.4° West Variation 4.0 East Deviation: 5.4 Westarrow_forward
- Direction: Strictly write in 4 bond paper, because my activity sheet is have 4 spaces. This is actually for maritime. industry course, but I think geometry can do this. use nautical almanac. Sample Calculation (Amplitude- Sun): On 07th May 2006 at Sunset, a vesel in position 10°00'N 0 10°00' W observed the sun bearing 288° by compass. Find the compass error. LMT Sunset 07d 18h 13m (+)00d 00h 40 м LIT: UTC Sunset: 07d 18h 53 m added - since longitude is westerly Declination Co7d 18h): N016° 55.5' d(0.7): (+) 00-6 N016 56.1' Declination Sun: Sin Amplitude Sin Declination (Los Latitude - Sin 016° 56.1'/Cos 10°00' = 0.295780189 Amplitude = WI. 2N (The prefix of amplitude is named easterly if body is rising. and westerly of body is setting. The suffix is named came as declination.) True Bearing: 287.20 Compass Bearing 288.0° Compass Error: 0.8' Westarrow_forwardOnly 100% sure experts solve it correct complete solutions need to get full marks it's my quiz okkkk.take your time but solve full accurate okkk maths expert solve itarrow_forwardSuggest to geometry subject expertsarrow_forward
- Strick handwritten solutions needarrow_forwardOnly 100% sure experts solve it correct complete solutions need to get full marks it's my quiz okkkk.take your time but solve full accurate okkk Geometry expert solve itarrow_forwardOnly 100% sure experts solve it correct complete solutions need to get full marks it's my quiz okkkk.take your time but solve full accurate okkk Geometry expert solve itarrow_forward
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