Thestructural formula for the carbocation intermediate formed in the dehydration of each of the alcohols is to be written. By using Curved arrows the way in which carbocation is deprotonated by water to give a mixture of alkenes , is to be discussed. Concept introduction: > The dehydration of alcohol results in the loss of H 2 O molecule and formation of the corresponding alkene. > The H and OH are lost from adjacent carbons. > The dehydration of primary alcohols proceeds through E2 the mechanism. > The dehydration of secondary and tertiary alcohols proceeds through E1 the mechanism. > The E1 mechanism involves the formation of carbocation. > The carbocation is formed at the carbon where the hydroxyl group is attached. > The secondary and tertiary alcohols can produce more than one product if the hydroxyl-bearing carbon has nonequivalent adjacent carbons.

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Answer 1

Question

Chapter 7.12, Problem 19P

Interpretation Introduction

Interpretation:

Thestructural formula for the carbocation intermediate formed in the dehydration of each of the alcohols is to be written. By using Curved arrows the way in which carbocation is deprotonated by water to give a mixture of alkenes, is to be discussed.

Concept introduction:
>
The dehydration of alcohol results in the loss of H2O molecule and formation of the corresponding alkene.
>
The H and OH are lost from adjacent carbons.
>
The dehydration of primary alcohols proceeds through E2 the mechanism.
>
The dehydration of secondary and tertiary alcohols proceeds through E1 the mechanism.
>
The E1 mechanism involves the formation of carbocation.
>
The carbocation is formed at the carbon where the hydroxyl group is attached.
>
The secondary and tertiary alcohols can produce more than one product if the hydroxyl-bearing carbon has nonequivalent adjacent carbons.

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Answer 2

Question

Chapter 7.12, Problem 19P

Interpretation Introduction

Interpretation:

Thestructural formula for the carbocation intermediate formed in the dehydration of each of the alcohols is to be written. By using Curved arrows the way in which carbocation is deprotonated by water to give a mixture of alkenes, is to be discussed.

Concept introduction:
>
The dehydration of alcohol results in the loss of H2O molecule and formation of the corresponding alkene.
>
The H and OH are lost from adjacent carbons.
>
The dehydration of primary alcohols proceeds through E2 the mechanism.
>
The dehydration of secondary and tertiary alcohols proceeds through E1 the mechanism.
>
The E1 mechanism involves the formation of carbocation.
>
The carbocation is formed at the carbon where the hydroxyl group is attached.
>
The secondary and tertiary alcohols can produce more than one product if the hydroxyl-bearing carbon has nonequivalent adjacent carbons.

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Answer 3

Question

Chapter 7.12, Problem 19P

Interpretation Introduction

Interpretation:

Thestructural formula for the carbocation intermediate formed in the dehydration of each of the alcohols is to be written. By using Curved arrows the way in which carbocation is deprotonated by water to give a mixture of alkenes, is to be discussed.

Concept introduction:
>
The dehydration of alcohol results in the loss of H2O molecule and formation of the corresponding alkene.
>
The H and OH are lost from adjacent carbons.
>
The dehydration of primary alcohols proceeds through E2 the mechanism.
>
The dehydration of secondary and tertiary alcohols proceeds through E1 the mechanism.
>
The E1 mechanism involves the formation of carbocation.
>
The carbocation is formed at the carbon where the hydroxyl group is attached.
>
The secondary and tertiary alcohols can produce more than one product if the hydroxyl-bearing carbon has nonequivalent adjacent carbons.

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Answer 4

Question

Chapter 7.12, Problem 19P

Interpretation Introduction

Interpretation:

Thestructural formula for the carbocation intermediate formed in the dehydration of each of the alcohols is to be written. By using Curved arrows the way in which carbocation is deprotonated by water to give a mixture of alkenes, is to be discussed.

Concept introduction:
>
The dehydration of alcohol results in the loss of H2O molecule and formation of the corresponding alkene.
>
The H and OH are lost from adjacent carbons.
>
The dehydration of primary alcohols proceeds through E2 the mechanism.
>
The dehydration of secondary and tertiary alcohols proceeds through E1 the mechanism.
>
The E1 mechanism involves the formation of carbocation.
>
The carbocation is formed at the carbon where the hydroxyl group is attached.
>
The secondary and tertiary alcohols can produce more than one product if the hydroxyl-bearing carbon has nonequivalent adjacent carbons.

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Answer 5

Chapter 7.12, Problem 19P

Interpretation Introduction

Interpretation:

Thestructural formula for the carbocation intermediate formed in the dehydration of each of the alcohols is to be written. By using Curved arrows the way in which carbocation is deprotonated by water to give a mixture of alkenes, is to be discussed.

Concept introduction:
>
The dehydration of alcohol results in the loss of H2O molecule and formation of the corresponding alkene.
>
The H and OH are lost from adjacent carbons.
>
The dehydration of primary alcohols proceeds through E2 the mechanism.
>
The dehydration of secondary and tertiary alcohols proceeds through E1 the mechanism.
>
The E1 mechanism involves the formation of carbocation.
>
The carbocation is formed at the carbon where the hydroxyl group is attached.
>
The secondary and tertiary alcohols can produce more than one product if the hydroxyl-bearing carbon has nonequivalent adjacent carbons.

Answer 6

Chapter 7.12, Problem 19P

Interpretation Introduction

Interpretation:

Thestructural formula for the carbocation intermediate formed in the dehydration of each of the alcohols is to be written. By using Curved arrows the way in which carbocation is deprotonated by water to give a mixture of alkenes, is to be discussed.

Concept introduction:
>
The dehydration of alcohol results in the loss of H2O molecule and formation of the corresponding alkene.
>
The H and OH are lost from adjacent carbons.
>
The dehydration of primary alcohols proceeds through E2 the mechanism.
>
The dehydration of secondary and tertiary alcohols proceeds through E1 the mechanism.
>
The E1 mechanism involves the formation of carbocation.
>
The carbocation is formed at the carbon where the hydroxyl group is attached.
>
The secondary and tertiary alcohols can produce more than one product if the hydroxyl-bearing carbon has nonequivalent adjacent carbons.

Answer 7

Chapter 7.12, Problem 19P

Interpretation Introduction

Interpretation:

Thestructural formula for the carbocation intermediate formed in the dehydration of each of the alcohols is to be written. By using Curved arrows the way in which carbocation is deprotonated by water to give a mixture of alkenes, is to be discussed.

Concept introduction:
>
The dehydration of alcohol results in the loss of H2O molecule and formation of the corresponding alkene.
>
The H and OH are lost from adjacent carbons.
>
The dehydration of primary alcohols proceeds through E2 the mechanism.
>
The dehydration of secondary and tertiary alcohols proceeds through E1 the mechanism.
>
The E1 mechanism involves the formation of carbocation.
>
The carbocation is formed at the carbon where the hydroxyl group is attached.
>
The secondary and tertiary alcohols can produce more than one product if the hydroxyl-bearing carbon has nonequivalent adjacent carbons.

Answer 8

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Answer 10

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Answer 11

Ch. 7.1 - Name each of the following using IUPAC...Ch. 7.1 - Prob. 2P Ch. 7.2 - How many carbon atoms are sp2-hybridized in the...Ch. 7.3 - Prob. 4P Ch. 7.3 - Are cis-2-hexene and trans-3-hexene stereoisomers?...Ch. 7.4 - Prob. 6P Ch. 7.4 - Prob. 7P Ch. 7.4 - Give the IUPAC name of each of the compounds in...Ch. 7.5 - Arrange the following in order of increasing...Ch. 7.6 - Prob. 10P

Solution Summary: The author explains how carbocation is deprotonated by water to form a mixture of alkenes by using Curved arrows.

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