Connect hosted by ALEKS Access Card 52-Week for Elementary Statistics: A Step by Step Approach
10th Edition
ISBN: 9781260041798
Author: Allan G. Bluman
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 7.1, Problem 7E
Find each.
a. zα/2 for the 99% confidence interval
b. zα/2 for the 98% confidence interval
c. zα/2 for the 95% confidence interval
d. zα/2 for the 90% confidence interval
e. zα/2 for the 94% confidence interval
(a)
Expert Solution
To determine
To find: The value of
Answer to Problem 7E
The value of
Explanation of Solution
Given info:
The confidence level is 99%.
Calculation:
Since the 99% confidence interval is to be used.
Software procedure:
Step by step procedure to obtain the critical value using the MINITAB software:
- Choose Graph > Probability Distribution Plot choose View Probability > OK.
- From Distribution, choose ‘Normal’ distribution.
- Click the Shaded Area tab.
- Choose Probability Value and Both Tail for the region of the curve to shade.
- Enter the Probability value as 0.01.
- Click OK.
Output using the MINITAB software is given below:
From the output, the value of
(b)
Expert Solution
To determine
To find: The value of
Answer to Problem 7E
The value of
Explanation of Solution
Given info:
The confidence level is 98%.
Calculation:
Critical value:
Since the 98% confidence interval is to be used.
Software procedure:
Step by step procedure to obtain the critical value using the MINITAB software:
- Choose Graph > Probability Distribution Plot choose View Probability > OK.
- From Distribution, choose ‘Normal’ distribution.
- Click the Shaded Area tab.
- Choose Probability Value and Both Tail for the region of the curve to shade.
- Enter the Probability value as 0.02.
- Click OK.
Output using the MINITAB software is given below:
From the output, the value of
(c)
Expert Solution
To determine
To find: The value of
Answer to Problem 7E
The value of
Explanation of Solution
Given info:
The confidence level is 95%.
Calculation:
Critical value:
Since the 95% confidence interval is to be used.
Software procedure:
Step by step procedure to obtain the critical value using the MINITAB software:
- Choose Graph > Probability Distribution Plot choose View Probability> OK.
- From Distribution, choose ‘Normal’ distribution.
- Click the Shaded Area tab.
- Choose Probability Value and Both Tail for the region of the curve to shade.
- Enter the Probability value as 0.05.
- Click OK.
Output using the MINITAB software is given below:
From the output, the value of
(d)
Expert Solution
To determine
To find: The value of
Answer to Problem 7E
The value of
Explanation of Solution
Given info:
The confidence level is 90%.
Calculation:
Critical value:
Since the 90% confidence interval is to be used.
Software procedure:
Step by step procedure to obtain the critical value using the MINITAB software:
- Choose Graph > Probability Distribution Plot choose View Probability> OK.
- From Distribution, choose ‘Normal’ distribution.
- Click the Shaded Area tab.
- Choose Probability Value and Both Tail for the region of the curve to shade.
- Enter the Probability value as 0.10.
- Click OK.
Output using the MINITAB software is given below:
From the output, the value of
(e)
Expert Solution
To determine
To find: The value of
Answer to Problem 7E
The value of
Explanation of Solution
Given info:
The confidence level is 94%.
Calculation:
Critical value:
Since the 94% confidence interval is to be used.
Software procedure:
Step by step procedure to obtain the critical value using the MINITAB software:
- Choose Graph > Probability Distribution Plot choose View Probability> OK.
- From Distribution, choose ‘Normal’ distribution.
- Click the Shaded Area tab.
- Choose Probability Value and Both Tail for the region of the curve to shade.
- Enter the Probability value as 0.06.
- Click OK.
Output using the MINITAB software is given below:
From the output, the value of
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
If n1 = 120, x1 = 45, n2 80, x2 = 35. Calculate the 98%
confidence interval for p1-p2.
O (-0.172,0.144)
O (-0.197,0.111)
O (-0.227,0.101)
O (-0.379, -0.021)
Construct both a 80% and a 98% confidence interval for ,.
B =
= 50, s = 8.8, Spa = 45, n= 21
80% :
< B1<
98% :
s is the square root of the mean squared error VMSE and Sr is the sum of the squared deviations from mean for , Spz = (x; – x)².
A 95% confidence interval for the difference in proportions of rotted fruit between Orchard A and Orchard B is (0.03,
0.11). What does this mean?
X
Previous
C
95% of the fruit at Orchard A and B are between 3% and 11% rotted.
We are 95% confident that the difference in the percentages of rotted fruit at these orchards is between 3 and 11
percentage points.
The percentage of rotted fruit at Orchard B is between 3 and 11 percentage points higher than Orchard A.
4
r
We are 95% confident that the Orchard A has between 3% and 11% rotted fruit.
f
5
%
5
t
g
Oll
A
6
b
y
h
&
7
n
O
u
j
8
m
i
k
(
9
V
O
alt
1
e
A
ctrl
[
Next
G
backspac
}
Chapter 7 Solutions
Connect hosted by ALEKS Access Card 52-Week for Elementary Statistics: A Step by Step Approach
Ch. 7.1 - What is the difference between a point estimate...Ch. 7.1 - What information is necessary to calculate a...Ch. 7.1 - What is the margin of error?Ch. 7.1 - What is meant by the 95% confidence interval of...Ch. 7.1 - What are three properties of a good estimator?Ch. 7.1 - What statistic best estimates ?Ch. 7.1 - Find each. a. z/2 for the 99% confidence interval...Ch. 7.1 - What is necessary to determine the sample size?Ch. 7.1 - Fuel Efficiency of Cars and Trucks Since 1975 the...Ch. 7.1 - Fast-Food Bills for Drive-Thru Customers A random...
Ch. 7.1 - Overweight Men For a random sample of 60...Ch. 7.1 - Number of Jobs A sociologist found that in a...Ch. 7.1 - Number of Faculty The numbers of faculty at 32...Ch. 7.1 - Freshmen GPAs First-semester GPAs for a random...Ch. 7.1 - Carbohydrate Grams in Commercial Subs The number...Ch. 7.1 - Number of Farms A random sample of the number of...Ch. 7.1 - Gasoline Use A random sample of 36 drivers used on...Ch. 7.1 - Day Care Tuition A random sample of 50...Ch. 7.1 - Hospital Noise Levels Noise levels at various area...Ch. 7.1 - Length of Growing Seasons The growing seasons for...Ch. 7.1 - Christmas Presents How large a sample is needed to...Ch. 7.1 - Hospital Noise Levels In the hospital study cited...Ch. 7.1 - Internet Viewing A researcher wishes to estimate...Ch. 7.1 - Cost of Pizzas A pizza shop owner wishes to find...Ch. 7.1 - Water Temperature If the variance of the water...Ch. 7.1 - Undergraduate GPAs It is desired to estimate the...Ch. 7.2 - Sport Drink Decision Assume you get a new job as a...Ch. 7.2 - What are the properties of the t distribution?Ch. 7.2 - What is meant by degrees of freedom?Ch. 7.2 - Find the values for each. a. t/2 and n = 18 for...Ch. 7.2 - When should the t distribution be used to find a...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - For Exercises 5 through 20, assume that all...Ch. 7.2 - Parking Meter Revenue A one-sided confidence...Ch. 7.3 - Contracting Influenza To answer the questions, use...Ch. 7.3 - In each case, find p and q. a. n = 80 and X = 40...Ch. 7.3 - Find p and q for each situation. a. n = 60 and X =...Ch. 7.3 - Cyber Monday Shopping A survey of 1000 U.S. adults...Ch. 7.3 - Manual Transmission Automobiles In 2014, six...Ch. 7.3 - Holiday Gifts A survey of 100 Americans found that...Ch. 7.3 - Belief in Haunted Places A random sample of 205...Ch. 7.3 - Work Interruptions Research by Steelcase found the...Ch. 7.3 - Travel to Outer Space A CBS News/New York Times...Ch. 7.3 - High School Graduates Who Take the SAT The...Ch. 7.3 - Educational Television In a random sample of 200...Ch. 7.3 - Wi-Fi Access A survey of 50 students in grades 4...Ch. 7.3 - Students Who Major in Business It has been...Ch. 7.3 - Smartphone Ownership A recent survey of 349 people...Ch. 7.3 - Home Internet Access According to a study, 96% of...Ch. 7.3 - Overseas Travel A researcher wishes to be 95%...Ch. 7.3 - Widows A recent study indicated that 29% of the...Ch. 7.3 - Direct Satellite Television It is believed that...Ch. 7.3 - Obesity Obesity is defined as a body mass index...Ch. 7.3 - U.S. Fitness Guidelines According to the World...Ch. 7.3 - Diet Habits A federal report indicated that 27% of...Ch. 7.3 - Gun Control If a random sample of 600 people is...Ch. 7.3 - Survey on Politics In a study, 68% of 1015...Ch. 7.4 - Ages of Presidents at the Time of Their Deaths...Ch. 7.4 - What distribution must be used when computing...Ch. 7.4 - What assumption must be made when computing...Ch. 7.4 - Using Table G, find the values for 2 left and 2...Ch. 7.4 - Lifetimes of Wristwatches Find the 90% confidence...Ch. 7.4 - Carbohydrates in Yogurt The number of...Ch. 7.4 - Carbon Monoxide Deaths A study of...Ch. 7.4 - Pacemaker Batteries A manufacturer of pacemakers...Ch. 7.4 - Age of College Students Find the 90% confidence...Ch. 7.4 - Prob. 9ECh. 7.4 - Stock Prices A random sample of stock prices per...Ch. 7.4 - Cost of an Operation A medical researcher surveyed...Ch. 7.4 - Home Ownership Rates The percentage rates of home...Ch. 7.4 - Calories in a Standard Size Candy Bar Estimate the...Ch. 7.4 - SAT Scores Estimate the variance in mean...Ch. 7.4 - Daily Cholesterol Intake The American Heart...Ch. 7.4 - Calculator Battery Lifetimes A confidence interval...Ch. 7 - Eye Blinks A survey of 49 individuals found that...Ch. 7 - Vacation Days A U.S. Travel Data Center survey...Ch. 7 - Blood Pressure A researcher wishes to estimate...Ch. 7 - Shopping Survey A random sample of 49 shoppers...Ch. 7 - Lengths of Childrens Animated Films The lengths...Ch. 7 - Dog Bites to Postal Workers For a certain urban...Ch. 7 - Number of Credit Cards In a recent survey of 1000...Ch. 7 - Vacation Sites A U.S. Travel Data Centers survey...Ch. 7 - Prob. 7.3.9RECh. 7 - Adult Educational Activities A local county has a...Ch. 7 - Prob. 7.3.11RECh. 7 - Child Care Programs A study found that 73% of...Ch. 7 - Baseball Diameters The standard deviation of the...Ch. 7 - Cost of an Operation A medical researcher surveyed...Ch. 7 - Lifetimes of Snowmobiles A random sample of 15...Ch. 7 - Length of Childrens Animated Films Use the data...Ch. 7 - From the Data Bank choose a variable, find the...Ch. 7 - Repeat Exercise 1, using a different variable and...Ch. 7 - Repeat Exercise 1, using a proportion. For...Ch. 7 - From Data Set III in Appendix B, select a sample...Ch. 7 - From Data Set VI in Appendix B, select a sample of...Ch. 7 - Select a random sample of 20 of the record high...Ch. 7 - Determine whether each statement is true or false....Ch. 7 - Determine whether each statement is true or false....Ch. 7 - Determine whether each statement is true or false....Ch. 7 - Determine whether each statement is true or false....Ch. 7 - When a 99% confidence interval is calculated...Ch. 7 - The best point estimate of the population mean is...Ch. 7 - When the population standard deviation is unknown...Ch. 7 - Complete the following statements with the best...Ch. 7 - Complete the following statements with the best...Ch. 7 - Complete the following statements with the best...Ch. 7 - Complete the following statements with the best...Ch. 7 - Cost of Texts An irate student complained that the...Ch. 7 - Doctor Visit Costs An irate patient complained...Ch. 7 - Weights of Minivans The average weight of 40...Ch. 7 - Ages of Insurance Representatives In a study of 10...Ch. 7 - Prob. 16CQCh. 7 - Burglaries For a certain urban area, it was found...Ch. 7 - Hours Spent Studying A university dean wishes to...Ch. 7 - Prob. 19CQCh. 7 - Prob. 20CQCh. 7 - Prob. 21CQCh. 7 - Prob. 22CQCh. 7 - Prob. 23CQCh. 7 - Prob. 24CQCh. 7 - Prob. 25CQCh. 7 - Prob. 26CQCh. 7 - Critical Thinking Challenges A confidence interval...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- For each example, choose the confidence interval that has a larger margin of error. 1) OA 90% confidence interval for a mean contructed from a sample of 55 OA 90% confidence interval for a mean contructed from a sample of 45 2) OA 90% confidence interval for a mean constructed from a sample of 45 OA 92% confidence interval for a mean constructed from a sample of 45 3) OA 90% confidence interval for a mean constructed from a sample of 45, using s OA 90% confidence interval for a mean constructed from a sample of 45, using oarrow_forwardFind and interpret the 95% confidence interval forμ, if ¯y = 70 and s = 10, based on a sample size of (a) 5,(b) 20.arrow_forwardSuppose that the 99% confidence interval (CI) was calculated at lower 99% = -1.82 and upper 99% =0.42 compared to a 95% confidence interval values of lower 95% = -1.309 and upper 95% = -0.091. Anwer the following questions i. the lower bound would be (smaller than/larger than/ equal to) the lower bound of 95% CI ii. the upper bound would be (smaller than/larger than/ equal to) the lower bound of 95% CI iii. the point estimate would be (smaller than/larger than/ equal to) the lower bound of 95% CI At 99% CI where B1 hat = -0.7 the critical value is 1.12 and SE is 0.192. At 95% CI where B1 hat = -0.7 the critical value is 3.184 and SE is 0.192.arrow_forward
- X. is found to be 19.1, and the A simple random sample of sizen is drawn from a population that is normally distributed. The sample mean, sample standard deviation, s, is found to be 4.9. (a) Construct a 96% confidence interval about u if the sample size, n, is 39. (b) Construct a 96% confidence interval about u if the sample size, n, is 68. How does increasing the sample size affect the margin of error, E? (c) Construct a 98% confidence interval about u if the sample size, n, is 39. How does increasing the level of confidence affect the size of the margin of error, E? (d) If the sample size is 14, what conditions must be satisfied to compute the confidence interval? (a) Construct a 96% confidence interval about u if the sample size, n, is 39. Lower bound: Upper bound: (Round to two decimal places as needed.) (b) Construct a 96% confidence interval about u if the sample size, n, is 68. Lower bound: ; Upper bound: (Round to two decimal places as needed.) How does increasing the sample…arrow_forwardA 90% confidence interval for a population mean is (65, 77). The population distribution is approximately normal and the population standard deviation is known (but not given here). This confidence interval is based on a simple random sample of 25 observations. Calculate (a) the sample mean . (b) the margin of error (c) the population standard deviation of (d) the standard deviation of the sample meanarrow_forwardA confidence interval for the true proportional difference between the amount of seniors that have skipped class and the amount of freshmen that have skipped class was found to be (-o.05, 0.17). What can we conclude about the proportion of seniors that skipped class and the proportion of freshmen that skipped class? A There is a difference between the proportion of seniors and treshmen that skip since O in included in the Interval. B There is a difference between the proportion of seniors and freshmen that skip since the interval shows us the average difference is 0.06. There is no difference between the proportion of senlors and freshmen that skio sloce the difference could be anything between 0.05 less to 0.17 more for seniors. D. There is no difference between the proportion of senlors and freshemen that skip since o is included in the interval.arrow_forward
- A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 111, and the sample standard deviation, s, is found to be 10. (a) Construct a 95% confidence interval about μ if the sample size, n, is 20. (b) Construct a 95% confidence interval about μ if the sample size, n, is13. (c) Construct a 90% confidence interval about μ if the sample size, n, is 20. D) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed?arrow_forwardWhy should a confidence interval for p fall between (0, 1) while it makes sense for a confidence interval for Pi - p2 to fall between (-1, 1)?arrow_forwardConstruct the indicated confidence interval for the difference between the two population means. Assume that the two samples are independent simple random samples.Independent samples from two different populations yield the following data. x̅1 = 393, x̅2 = 703, s1 = 85, s2 = 98. The sample size 348 for both samples. Find the 90% confidence interval for μ1 - μ2.arrow_forward
- Find the critical values for each. z α/2 for the 95% confidence interval z α/2 for the 99% confidence interval z α/2 for the 90% confidence interval z α/2 for the 92.5% confidence intervalarrow_forwardA simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x overbar , is found to be 107 , and the sample standard deviation, s, is found to be 10 . (a) Construct a 96 % confidence interval about mu if the sample size, n, is 25 . (b) Construct a 96 % confidence interval about mu if the sample size, n, is 16 . (c) Construct an 80 % confidence interval about mu if the sample size, n, is 25 . (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed? LOADING... Click the icon to view the table of areas under the t-distribution.arrow_forwardA simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 107, and the sample standard deviation, s, is found to be 10. (a) Construct a 96% confidence interval about u if the sample size, n, js 16. (b) Construct a 96% confidence interval about u if the sample size, n, is 21. (c) Construct a 99% confidence interval about u if the sample size, n, is 16. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed? Click the icon to view the table of areas under the t-distribution. (a) Construct a 96% confidence interval about u if the sample size, n, is 16. Lower bound:: Upper bound: (Use ascending order. Round to one decimal place as needed) (b) Construct a 96% confidence interval about u if the sample size, n, is 21. Lower bound:: Upper bound: (Use ascending order. Round to one decimal place as needed) How does increasing the sample size affect the margin of…arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill
Big Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin Harcourt
Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill
Big Ideas Math A Bridge To Success Algebra 1: Stu...
Algebra
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:Houghton Mifflin Harcourt
What is a Linear Equation in One Variable?; Author: Don't Memorise;https://www.youtube.com/watch?v=lDOYdBgtnjY;License: Standard YouTube License, CC-BY
Linear Equation | Solving Linear Equations | What is Linear Equation in one variable ?; Author: Najam Academy;https://www.youtube.com/watch?v=tHm3X_Ta_iE;License: Standard YouTube License, CC-BY